Error shown bcz you makes function on onClickListener. Try below code:- save.setOnClickListener(new OnClickListener() { @Override public void onClick(View arg0) { // TODO Auto-generated method stub saveToInternalStorage(); } }); saveToInternalStorage function:- public void saveToInternalStorage() { } 1 solved Error in saving bitmap image in internal storage [closed]
Here is one way if len(set(line.split()).intersection(keywords)) > 2: This splits the line into words with line.split() first . Then uses sets intersection function to find the common elements of 2 sets 3 solved Finding lines that include two or more words from a list
You can explode by the slash by one way. $exploded_text = explode(“https://stackoverflow.com/”, $text); $new_text = $exploded_text[0] . $exploded_text[1] . ‘p’ . $exploded_text[2]; It’s not the best way, but it will work. 4 solved Add a text in a string PHP
It seems that the Typescript’s compiler does not understand that if the length of the array is different from zero, it will surely enter the loan and return a value. So, the simple soultion is this: private createBreadcrumbs(route: ActivatedRoute, url: string = ‘#’, breadcrumbs: MenuItem[] = []): MenuItem[] { const children: ActivatedRoute[] = route.children; for … Read more
With no sample input, I will just guess and maybe it will help: cat file header for file 1111 header for file 1111 2222 header for file 3333 4444 5555 awk ‘/header/&&c++>0 {next} 1’ file header for file 1111 1111 2222 3333 4444 5555 Though I am not the greatest in sed sed ‘1!{/^header/d;}’ file … Read more
Try SignalR or maybe SocketIO and see how they do ? I talked to the best guy I know in networking and he said that You should not disable ICMP totally, but instead be very careful if changing ICMP at all. Use WSS (ssl/tls), since routers will let that traffic through Out of scope, but … Read more
To achieve what you described you can simply store the last visible activity in SharedPreferences and have a Dispatcher activity that starts the last activity according to the preferences. in every activity you want to re-start automatically: @Override protected void onPause() { super.onPause(); SharedPreferences prefs = getSharedPreferences(“X”, MODE_PRIVATE); Editor editor = prefs.edit(); editor.putString(“lastActivity”, getClass().getName()); editor.commit(); … Read more
<?xml version=”1.0″ encoding=”utf-8″?> <LinearLayout xmlns:android=”http://schemas.android.com/apk/res/android” android:layout_width=”match_parent” android:layout_height=”wrap_content” android:orientation=”horizontal”> <Button style=”@style/Base.Widget.AppCompat.Button.Borderless” android:layout_width=”wrap_content” android:layout_height=”wrap_content” android:layout_weight=”1″ android:background=”@null” android:text=”Criar Contan” android:textAllCaps=”true” /> <View android:layout_width=”1dp” android:layout_height=”match_parent” android:layout_marginBottom=”16dp” android:layout_marginTop=”16dp” android:background=”@color/background_grey” /> <Button style=”@style/Base.Widget.AppCompat.Button.Borderless” android:layout_width=”wrap_content” android:layout_height=”wrap_content” android:layout_weight=”1″ android:text=”Entrar” android:textAllCaps=”true” /> 2 solved How to do these android buttons
You are looking at whole tuples with unicode strings; the u” is normal when showing you a tuple with unicode values inside: >>> print u’Hello World!’ Hello World! >>> print (u’Hello World’,) (u’Hello World’,) You want to format each row: print u’ {:<15} {:<8} {:<6}’.format(*row) See the str.format() documentation, specifically the Format Syntax reference; the … Read more
You should separate your classes and use the nested classes as property types. namespace WindowsFormsApp { class Car { public Id Id { get; set; } public Tires Tires { get; set; } } public class Id { public string brand { get; set; } public string model { get; set; } public int year … Read more
Since you didn’t really give more details, we can only give you broad pointers. First Check out: Stable Marriage Problem. And also search the web for Bipartite matching (or in cases of weighted edges: Assignment Problem, which can be solved using: Hungaring Algorithm). Note that a solution to the stable marriage problem might also solve … Read more
Do not use this answer, just use Select() method much simpler. class Program { static void Main(string[] args) { string[] s = new string[] { “hi”, “hello”, “what’s up” }; string[] newS = s.ArrayTo<string>(x => x.Remove(0, 1) ); foreach (string str in newS) Console.WriteLine(str); } } static class Ext { public static T[] ArrayTo<T>(this T[] … Read more
Your string literals should be enclosed in single quotes instead of double quotes. SELECT e.ename FROM emp e WHERE e.job = ‘MANAGER’ AND e.mgr NOT IN(SELECT empno FROM emp WHERE job = ‘MANAGER’); Also, based on your title, I wonder if this query shouldn’t be written more generically to account for any job in common? … Read more
I would do something like this: char const* sep = “”; // item separator (nothing to begin with) for(a;a<=b;a++) { if(a%3 == 0 && a%2 != 0) { cout << sep << a; // output the separator before the next value sep = “, “; // now change it to a comma } } cout … Read more
This one could be #include <bits/stdc++.h> using namespace std; int main(){ int i; for(int i=1; i<10; i++){ string binary = bitset<8>(i).to_string(); cout << binary << endl; } return 0; } 8 is bitset here. 3 solved C++ program . The program should use recursion and looping [closed]