Kirat To answer your question “How to return the matrix”: you are already doing it the right way. As you can see from the comments so far, the problem lies in the declaration of A. A is declared and initialized inside the for-loop: int [][]A = new int [size_num][size_num]; Hence its visibility is limited to the … Read more
Use pdfviewer library.This library is good for viewing pdf on Android platform. https://github.com/jblough/Android-Pdf-Viewer-Library/zipball/master 2 solved need to display in my android app
I’ll give an example and hope it will help you get what you want. In this example your Registered.txt file should look like: Smartsasse,myPassword OlofBoll,P@ssword //var path = @”C:\Registered.txt”; var path = “Registered.txt”; var allLines = System.IO.File.ReadAllLines(path); var userInfo = allLines.Select(l => l.Split(‘,’)).Select(s => new { Username = s[0], Password = s[1] }).ToList(); var user … Read more
With java.sql.Time you retrieve the right value from your time field in mysql. import java.io.IOException; import java.sql.Time; import java.text.ParseException; import java.text.SimpleDateFormat; import java.util.Date; public class teste { /** * @param args * @throws IOException */ public static void main(final String[] args) throws IOException { SimpleDateFormat sdf = new SimpleDateFormat(“HH:mm:ss”); try { Date data = sdf.parse(“21:00:00”); … Read more
you can set the text in xml file by: android:text=”some text” or in code by following textView.setText(“some text”); solved how to set text in textView? [closed]
This somewhat depends on the context, but it effectively means “the element of the variable ‘filename’ at the fourth position from the end.” So, if filename is a string with the value of ‘Test string.’ then filename[-4] will be ‘i’. In this particular case, the expression would evaluate to False, because “i” is not “B”. … Read more
Use this: <table> <tr> <td><?php echo $json[‘rows’][0][0]; ?></td> </tr> </table> 1 solved Get just one data in an array in PHP [closed]
Server-side-generated JavaScript would be an appropriate description. It even shows up on Google autocomplete, and there are many results. I am not a fan of this pattern. I find that it is better to keep JavaScript on the view-side completely and just inject the values you need via an init method of some sort. 1 … Read more
You can use DISTINCT to achieve it. Syntax: SELECT DISTINCT column_name FROM table_name; Based on above syntax, your query should be SELECT DISTINCT CLASS FROM ‘table_name’ solved Retrieve table values without retrieving duplicate values [closed]
Python 3 Code: def main(): dateStr = input(“Enter a date (mm/dd/yyyy): “) monthStr, dayStr, yearStr = dateStr.split(“https://stackoverflow.com/”) months = [“January”, “February”, “March”, “April”, “May”, “June”, “July”, “August”, “September”, “October”, “November”, “December”] monthStr = months[int(monthStr)-1] print (‘Converted Date: ‘ + ‘ ‘.join([str(dayStr), monthStr, str(yearStr)])) main() Python 2 Code: Use raw_input: def main(): dateStr = raw_input(“Enter a … Read more
In modern browsers (and IE8), you can use document.querySelector to use any CSS selector to find an element. In your case, for instance, you could use var x = document.querySelector(‘[action=”form_action.asp”]’); …to look it up by the value of its action attribute. The rest of your function doesn’t change. querySelector finds the first matching element. If … Read more
You could use a negated class like: [^A-Za-z0-9\s] Btw, you also can shorten it to: [^A-Za-z\d\s] And.. if you don’t mind to preserve underscores your could use: [^\w\s] The idea of the negated class is to not match the characters in it. For this regex: [^A-Za-z0-9\s] it means: ^ —> not match the following A-Za-z … Read more
You have some weird hidden characters in that line of HTML. specifically, before the closing ” of the onclick and after the opening ” of the style. You can fine them if you move through the line of HTML with the right arrow key. Here is your HTML pasted into a simple word processor: <a … Read more
>>> a=”sruthi” >>> >>> list([a]) [‘sruthi’] >>> or like in the comments above… >>> a=”sruthi” >>> a = [a] >>> a [‘sruthi’] pick your flavor… solved How to convert a string into a list as a single element?
Your problem is that you are adding a preliminary 1 to 1/1 which gives 2. Try this: def count(n): sum = 0 #Intializing the return variable for i in range(1, n+1): sum+=1.0/i #Adding to the return variable return sum This works as such: >>> def count(n): … sum = 0 … for i in range(1, … Read more