[Solved] My program is executing as expected but in the end I am an extra line called a segmentation fault near the output. Could someone see to it?

[ad_1] You’ve tagged this as c++ but it seems like you’re using entirely c.. So I’ll answer this as if it’s c. A segmentation fault occurs when you access memory that you don’t own. In this case you’re trying to print a character outside of the bounds of your string. (e.g. your string is len … Read more

[Solved] When click in numeric keyboard close keyboard and put number [closed]

[ad_1] To Close keyboard: // Check if no view has focus: View view = this.getCurrentFocus(); if (view != null) { InputMethodManager imm = (InputMethodManager)getSystemService(Context.INPUT_METHOD_SERVICE); imm.hideSoftInputFromWindow(view.getWindowToken(), 0); } And to set the number typed you use the editText´s Listerners [ad_2] solved When click in numeric keyboard close keyboard and put number [closed]

[Solved] C Program not working

[ad_1] Why are you writing this line largest = nvalue; ? And your if-else if commands are totally wrong. Try this code: #include <stdio.h> int main(){ int largest = 0; int no1, no2, no3; printf(“Number1: “); scanf(“%d”, &no1); printf(“Number2: “); scanf(“%d”, &no2); printf(“Number3: “); scanf(“%d”, &no3); if ((no1 > no2) && (no1>no3)){ largest=no1; } else … Read more

[Solved] Issue with if-else statements [closed]

[ad_1] You are indeed missing something basic – namely, that the output of your function doesn’t depend on answer at all. No matter what you feed in as answer, because 6 > 5 is always True, it will always return the result of that case. What you need is def greater_less_equal_5(answer): if answer > 5: … Read more

[Solved] How to merge two dictionaries with same keys and keep values that exist in the same key [closed]

[ad_1] def intersect(a, b): a, b = set(a), set(b) return list(a & b) def merge_dicts(d1, d2): return {k: intersect(v1, v2) for (k, v1), v2 in zip(d1.items(), d2.values())} dictionary_1 = {‘A’ :[‘B’,’C’,’D’],’B’ :[‘A’]} dictionary_2 = {‘A’ :[‘A’,’B’], ‘B’ :[‘A’,’F’]} merge = merge_dicts(dictionary_1, dictionary_2) print(merge) # {‘A’: [‘B’], ‘B’: [‘A’]} 4 [ad_2] solved How to merge two … Read more

[Solved] Multiple Array puzzle

[ad_1] using combination of array_map, array_column and array_reverse : $myArrays = array( array(1, 2, 3, 4), array(5, 6, 7, 8), array(9, 10, 11, 12), array(13, 14, 15, 16) ); $index = 0; $myArrays = array_map(function ($v) use (&$index, $myArrays) { if (($index % 2) != 0) { echo implode(“\n”, array_reverse(array_column($myArrays, $index))) . “\n”; } else … Read more

[Solved] Update Once each in specific time [closed]

[ad_1] Your code doesn’t add much to your question, so I don’t really know if this is what you are looking for, but here is some code to call a function every X time (swift 3): // call MyMethod every 1 second : Timer.scheduledTimer(timeInterval: 1, target: self, selector: #selector(MyController.myMethod), userInfo: nil, repeats: true) Please search … Read more

[Solved] In JDK1.8, is it necessary to use ConcurrentHashMap on all occasions that require synchronization?

[ad_1] No, it is not necessary to replace use of Collections.synchronizedMap with ConcurrentHashMap when used by multiple threads. The Concurrent Collections section in the javadoc for package java.util.concurrent says: “Synchronized” classes can be useful when you need to prevent all access to a collection via a single lock, at the expense of poorer scalability. In … Read more

[Solved] How to make double border on left only with thick outside and thin inside [duplicate]

[ad_1] I think this is what you are looking for.. .border1{ width:100px; height:100px; border-left: 10px solid #ccc; } .border2{ width: 100px; height: 100px; display: block; margin-left: 15px; border-left: 3px solid #ccc; } <div class=”border1″> <div class=”border2″></div> </div> Check it and let me know if you want any thing else.. 2 [ad_2] solved How to make … Read more

[Solved] Object Array Initialization [duplicate]

[ad_1] Variables and array elements are all references to objects. They are not the actual objects. To illustrate, I’ll “name” actual objects using a number scheme, e.g. #1 is the first object. Your code runs as follows: Class is initialized by the JVM, and root1, root2, and root3 are all null. Node root[]={root1,root2,root3} is executed … Read more