Kirat[ad_1] The only thing I could think of was to iterate over all polygons, and then loop over all the other polygons to find intersections. (Which means the algorithm has a quadratic run time complexity.) Inefficient, but it gets the job done. result = [] for i, shape in enumerate(polys): intersected_shapes = [poly for poly … Read more
[ad_1] @Pᴇʜ Regex pattern shared in the comment works perfectly per your examples. Here is how to use it with an in cell function. Don’t Forget to add the reference to “Microsoft VBScript Regular Expressions 5.5“ Function simpleCellRegex(Myrange As Range) As String Dim regEx As New RegExp Dim strPattern As String Dim strInput As String … Read more
[ad_1] If FULLNAME always consists of 3 parts (which is what you said), then it is relatively simple, using the REGEXP_SUBSTR regular expression function: SQL> with test (fullname) as 2 (select ‘Metro Goldwyn Mayer’ from dual 3 ) 4 select regexp_substr(fullname, ‘\w+’, 1, 1) first_name, 5 regexp_substr(fullname, ‘\w+’, 1, 2) middle_name, 6 regexp_substr(fullname, ‘\w+’, 1, … Read more
[ad_1] preg_match_all(‘/[a-z]\d{2,5}/’, $subject, $result, PREG_PATTERN_ORDER); for ($i = 0; $i < count($result[0]); $i++) { # Matched text = $result[0][$i]; } [ad_2] solved php preg_match item first five character regex [closed]
[ad_1] ” So created a SQL report to generate data that looks like this:” The reason for your downvotes is likely due to you not posting the SQL code here. Leaves me guessing at your table formats, so for my ease… select * from mytable is what I’ll guess you’ve used. I’m left guessing column … Read more
[ad_1] W3C specification states: A selector’s specificity is calculated as follows: count the number of ID selectors in the selector (= a) count the number of class selectors, attributes selectors, and pseudo-classes in the selector (= b) count the number of type selectors and pseudo-elements in the selector (= c) ignore the universal selector Selectors … Read more
[ad_1] Could use array_shift / array_unshift, but since the logic seems upside down, you could use something like <?php $apparentDB = array(“1” => “Jason” , “2” => “Jimmy” , “3” => “Christopher” , “4” => “Bruce” , “5” => “james” , “6” => “Mike” , “7” => “Brad” ); /* You can add it one … Read more
[ad_1] using reduce makes it fairly simple const timings = [{ monday: { from: “12:00”, to: “13:00” }, tuesday: { from: “11:00”, to: “13:00” }, thursday: { from: “11:00”, to: “13:00” }, friday: { from: “11:00”, to: “13:00” }, saturday: { from: “11:00”, to: “13:00” }, }, { monday: { from: “10:00”, to: “17:00” }, … Read more
[ad_1] the code maybe looks like this: #!/usr/bin/perl use strict; use warnings; my @array = (‘1′,’2′,’3′,’5′,’6’); my @array2 = (‘1’, ‘3’, ‘7’, ‘6’); for my $item(@array2) { if (grep($_ == $item, @array) > 0) { print “$item, Match\n”; } else { print “$item, Not Match\n”; } } Output 1, Match 3, Match 7, Not Match … Read more
[ad_1] First of all, you should use prepared statements like this: $note = “SELECT * FROM notify WHERE seeker=:seeker AND donor=:donor ORDER BY `date` DESC LIMIT 1”; $st = $conn->prepare($note); $st->execute(array( ‘:seeker’ => $_SESSION[’email’], ‘:donor’ => $email, ); Without the place holders you’re still open to SQL injection. Second, you can’t compare a string with … Read more
[ad_1] Use array find: var languages = [ {“name”: “english”, “iso_639_2_code”: “eng”}, {“name”: “esperanto”,”iso_639_2_code”: “epo”}, {“name”: “estonian”,”iso_639_2_code”: “est”} ]; var user = [{name: “john”,language: “eng”,country: “US”}]; var language = languages.find(l => l.iso_639_2_code === user[0].language); var languageName = language && language.name; // <– also prevent error when there is no corresponding language found console.log(languageName); EDIT: With … Read more
[ad_1] How can I extract a string from a text field that matches with a “value” in my Dictionary and return the dict’s key into a new column in the Output? [closed] [ad_2] solved How can I extract a string from a text field that matches with a “value” in my Dictionary and return the … Read more
[ad_1] Since it’s recursive and the recursive call comes before your printline, it will recursively call itself over and over until it reaches the base case. Only first after the recursive calls have ended will your print be allowed to execute. Something like this Do something first recursive call Do something second recursive call Do … Read more
[ad_1] okay so after spending sometime i figured it out options = [‘color’, ‘size’]; optionsValues= [[‘Red’,’Blue’], [‘L’, ‘XS’]]; function combination() { var r = [], arg = arguments[0], max = arg.length-1; function helper(arr, i) { for (var j=0, l=arg[i].length; j<l; j++) { var a = arr.slice(0); // clone arr var obj = {}; obj[options[i]] = … Read more
[ad_1] Here is a non Regex version of what you are trying to achieve. $str = “server_name::IMACW10\COZMOSQLEXPRESS @database_name::OneTwoThreePet username::pauline_pet databasePass::root”; $test = explode(” “, $str); $array = array(); foreach($test as $key){ $newkey = strtok($key,”:”); $array[$newkey] = substr($key, strpos($key, “:”) + 2); } list($server, $dbname, $username, $pass) = array_values($array); echo ‘$serverName=”.$server.”<br> $databaseName=”.$dbname.”<br> $username=”.$username.”<br> $pass=”.$pass; Output: $serverName=IMACW10\COZMOSQLEXPRESS … Read more