[Solved] Launch all URLs in webbrowser c# 2 seconds to 2 seconds

[ad_1] I think you are overwriting your websites-object in every loop with the following line: websites = new List<string> {“https://mbasic.facebook.com/groups/”+groups[i]}.GetEnumerator(); That’s why it only prints the last website. Have a look at How can I add an item to a IEnumerable collection? Furthermore this could help you, too: IEnumerable vs. IEnumerator and implementation 9 [ad_2] … Read more

[Solved] Coloring random color table of tr and td [duplicate]

[ad_1] You can’t just access DOM elements like properties in javascript. To get DOM elements, the easiest way is to use the querySelector() or querySelectorAll() methods. ( See the documentation here: https://developer.mozilla.org/de/docs/Web/API/Document/querySelector ) In your case, you would get all td elements like this: var x = document.querySelectorAll(‘table td’); which will return a NodeList containing … Read more

[Solved] Why “non-static variable cannot be referenced from a static context” produced for one program but not another? [duplicate]

Introduction [ad_1] When programming in Java, it is important to understand the concept of static and non-static variables. This is because the compiler will throw an error if a non-static variable is referenced from a static context. This error can be confusing, as it may appear in one program but not another. In this article, … Read more

[Solved] How can an array containing objects be restructured in a preferred format?

[ad_1] You could use Object.values and map. Use Computed property names to create the desired object let foobar = [{“foo”:{“title”:”example title foo”,”desc”:”example description foo”}},{“bar”:{“title”:”example title bar”,”unnecessary”:”this is not needed”,”desc”:”example description bar”}}] let output = foobar.map(a => { let { title, desc } = Object.values(a)[0]; return { How can an array containing objects be restructured in … Read more

[Solved] Javascript array filter child! [closed]

[ad_1] You could get the pathes first and then filter the given key, if it is more than in two pathes, then filter out this value. function filter(source, targets) { function getPath(array, target) { return array.reduce((r, { key, children }) => { var temp; if (key === target) return r.concat(key); if (children) { temp = … Read more