Kirat[ad_1] This sequence is Stern’s diatomic sequence, and the function you’ve been given is called fusc(n). One way to compute it in O(log n) time and O(1) space complexity is to find the n’th value in the Calkin-Wilf tree. That value’s numerator will be fusc(n). You can read some background on the wikipedia page: https://en.wikipedia.org/wiki/Calkin%E2%80%93Wilf_tree … Read more
[ad_1] The basic markup for postal addresses is a p element with br elements for separating the lines. The address element conveys additional information, namely, that this postal address is (part of) the contact information for an article (if there is one) or the body (if there is no parent article). So in both cases … Read more
[ad_1] If we ignore errors, you can read the numbers in one at a time, and form a string for the first line of output. Forming the string will involve appending a reversed copy to the original. Once the string is formed, you can output that string for the first line. Then replace the first … Read more
[ad_1] I get a javascript error with your code: Uncaught ReferenceError: results is not defined on this line: var town = extractFromAdress(results[0].address_components, “locality”); That should be the place object you retrieved (that you got the rest of the information from): var place = autocomplete.getPlace(); Then it works (if the result has a result of type … Read more
[ad_1] There is no std::vector<…>::sort. Instead, you will need to use std::sort: std::sort(orderedList.begin(), orderedList.end()); However, this will try to compare the pointers in your std::vector<Shape*> (hint: refactor this if at all possible). Instead, you will need to pass a custom comparator that dereferences the pointers: std::sort( orderedList.begin(), orderedList.end(), [](Shape *a, Shape *b) { return *a … Read more
[ad_1] I managed to achieve what I wanted using the following: public bool DataIsValid(string s, Type someType) { o = 0; // a class member object variable try { o = Convert.ChangeType(s, someType); } catch { return false; } return true; } //using the object variable double someDouble = (double)0; //some more code Thanks for … Read more
[ad_1] Since you already have a C string, just use strcmp. It will likely be faster than the s.compare method since you avoid the overhead of doing a conversion to std::string for both the original string and the string to compare to. if (strcmp(c, “hello”) == 0) { … [ad_2] solved fastest way to compare … Read more
[ad_1] Here’s an example of how you could do it. Live demo (click). Markup: <div id=”inputs”> <input type=”checkbox” value=”Apple”> <input type=”checkbox” value=”Orange”> <input type=”checkbox” value=”Pineapple”> <input type=”checkbox” value=”Mango”> </div> <ul id=”results”></ul> JavaScript: $(‘#inputs input’).change(function() { $li = $(‘<li></li>’); $li.text(this.value); $(‘#results’).append($li); }); If you want to remove items when they’re unchecked and prevent duplicates, you could … Read more
[ad_1] you can do this, on two way : First: string A = “Username:Password”; string Username = A.Substring(0, A.IndexOf(‘:’)); A = A.Substring(A.IndexOf(‘:’) + 1); string Password = A; Second: string A = “Username:Password”; string[] Items = A.Split(‘:’); string Username2 = Items[0]; string Password2 = Items[1]; 2 [ad_2] solved Reading TextBox List in C# [closed]
[ad_1] Actually you need to use for loop if it’s not working with filter and map. I would suggest you to access date according to keys from the above arrays let x = { “name”: “Ola”, “dates”: [ { “7.01.2020”: [1, 2, 3] }, { “8.01.2020”: [4, 5, 6] }, { “9.01.2020”: [7, 8, 9] … Read more
[ad_1] The closest thing to what you’re looking for is called Near Field Communication (or NFC). Currently fully supported by many Android phones without major limitations. Apple devices are more limited in NFC usage (currently restricted to Apple Pay only). For more information, read Near field communication (Wikipedia). [ad_2] solved Is it possible to connect … Read more
[ad_1] You should use overflow-y: hidden as folows $(‘textarea’).css(“height”, $(“textarea”).prop(“scrollHeight”)) textarea { width: 300px; resize: none; margin: 0; padding: 0; overflow-y: hidden; } <script src=”https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js”></script> <textarea> Lorem Ipsum is simply dummy text of the printing and typesetting industry. Lorem Ipsum has been the industry’s standard dummy text ever since the 1500s, when an unknown printer … Read more
[ad_1] If you write all the statements in the same line, it will be an invalid syntax. For this, solution 1: a=[‘vishal’,123,345,’out’,25,’going’] a[2]=455 a[0]=’dinesh’ Now print your list, you will see the result: [‘dinesh’, 123, 455, ‘out’, 25, ‘going’] If you don’t want to write in different lines, you can do this, Solution 2: a=[‘vishal’, … Read more
[ad_1] Use LocalDateTime with its toString(). String s = LocalDateTime.now().toString(); // ISO standard representation // LocalDateTime to old Date: Date date = Date.from(localDateTime.atZone(ZoneId.systemDefault()).toInstant()); // Old Date holding time to LocalDateTime: LocalDateTime localDateTime = LocalDateTime.ofInstant(date.toInstant(), ZoneId.systemDefault()); Of cause with an SQL PreparedStatement, you could simply call setDate without the detour via String. [ad_2] solved How to … Read more
[ad_1] No, but it gives similar behaviour. So what you have created is a pointer to an array of vectors. So you will end up with this: adj[0] = [] adj[1] = [] … adj[number_nodes] = [] and doing a push_back is a legitimate way to add to the vectors: adj[0].push_back(some_num) –> adj[0] = [some_num] … Read more