Kirat[ad_1] Okay, so here’s some code to get you started. I based the names on the code you gave, which is why it was helpful. I’ve commented this a lot to try and aid your learning, there are only actually about a dozen lines of code! Note: this code will likely not work “as is”. … Read more
[ad_1] You need to check if titletext.a is None before you can use it for sure. for titles in title: titleheading = soup.findAll(‘h2’) for titletext in titleheading: if titletext.a: titlename = titletext.a titlelink =titlename.get(‘href’) print(i) print(titlelink) i+=1 2 [ad_2] solved Non Type object has no attribute get error
[ad_1] I have found my mistake, and I am really sorry about taking your time. I noticed that I didn’t place my function to the event handler. private void label3_Click(object sender, EventArgs e) { count++; chechTurn(); printXorO(_01); checkWin_Loose_Draw();// here … _01.Enabled = false; } 2 [ad_2] solved Can someone help me with my tic tac … Read more
[ad_1] Use std::none_of, along with isdigit: #include <algorithm> #include <cctype> #include <string> #include <iostream> int main() { std::string test = “abc123”; if ( std::none_of(test.begin(), test.end(), ::isdigit)) std::cout << “All good\n”; else std::cout << “You’ve entered an integer\n”; // Try with good data test = “abcdef”; if ( std::none_of(test.begin(), test.end(), ::isdigit)) std::cout << “All good\n”; else … Read more
[ad_1] They all seem to be examples of linear search. According to the Wikipedia article: It sequentially checks each element of the list for the target value until a match is found or until all the elements have been searched. 7 [ad_2] solved Does this algorithm have a name? [closed]
[ad_1] Create an array containing all your quotes Create a random number based on the current date, which goes from 0 to n (n being the amount of quotes in your array – 1) Show the item of the array which has the index of the random number created in step 2 Try to write … Read more
[ad_1] You will have to use a javascript charting library such as flot or jqplot. Another easy way is to use google visualization. https://github.com/aaronjorbin/flot-examples/blob/master/index.php http://www.jqplot.com/tests/ https://developers.google.com/chart/interactive/docs/reference There are many more libraries than this – do your research and choose the one that fits your needs. 2 [ad_2] solved I wanted to draw pie chart and … Read more
[ad_1] Here: http://goo.gl/yvwKi3 First 3 results tell you how to do it with full source code. [ad_2] solved How can search by Ajax? [closed]
[ad_1] Maybe: enumerate the windows on the system find the one with the text “Windows Security” find it’s children’s HWND and search for the text fields SetWindowText (HWND, etc … ) Send a message to the “Ok” button Tell us if it works or not … [ad_2] solved Program that test username and password in … Read more
[ad_1] Use UICollectionView 1) Inefficient way : If you want to play all media simultaneously. Grid View of mediaplayers. – (UICollectionViewCell *)collectionView:(UICollectionView *)collectionView cellForItemAtIndexPath:(NSIndexPath *)indexPath { UICollectionViewCell *cell = [collectionView dequeueReusableCellWithReuseIdentifier:CollectionCell forIndexPath:indexPath]; // get URL Player *mediaPlayer = [[self playerArray]objectAtIndex:indexPath.row]; NSURL* videoURL = [NSURL URLWithString:mediaPlayer.url]; MPMoviePlayerController* mPlayer = [[MPMoviePlayerController alloc] initWithContentURL:videoURL]; [mPlayer prepareToPlay]; [mPlayer play]; … Read more
[ad_1] A little bit quick’n’dirty, but you should get the idea. public static void Main(string[] args) { Regex regex = new Regex(“(([_ ]*[a-z]+)_ ?)+([_ ]*[a-z]+)”); string str = “a_b_c_ _ _abc_ _ _ _abcd”; Match match = regex.Match(str); // 2 – because of specific regex construction for (int i = 2; i < match.Groups.Count; i++) … Read more
[ad_1] This operation is just doing the “merge” step of a Merge Sort and can be done in O(l1+l2) time. The general premise is to iterate over both (already sorted) lists at the same time, but only advance the list with the lowest head value, while using the advanced value in the resulting output. The … Read more
[ad_1] More than likely your code would read (in more “human” terms)if the length of original_term is more than zero characters print something. [ad_2] solved Python how to use the len() on pig game [closed]
[ad_1] Use character class. So use: /^[A-Za-z0-9]+$/ And yes, testuser is a valid input for the above regex. 2 [ad_2] solved JavaScript : Alphanumeric REGEX pattern [closed]
[ad_1] #include <stdio.h> int main(){ int arr[] = {12,3,4,23,5,46,5,6,7,78,67,68,134,45,46,47,67,11,23,18,-3}; int count = 21; int i; int pos=0, len=0; for(i=0;i<count-1;++i){//i<count-1-len int k; for(k=0;arr[i+k]<arr[i+k+1];++k) ; if(k>len){ len = k; pos = i; } i += k; } printf(“Longest series: “); for(i=pos;i<=pos+len;++i) printf(“%d “, arr[i]); printf(“\n”); return 0; } [ad_2] solved what is the algorithm for function that … Read more