I need to split it to get only 1 and 6 and I only want whole number I want to ignore the floating numbers You can use String.prototype.split() with RegExp /\D|\d+\.\d+/ to split characters that are not digits, or digits followed by . character followed by digits to handle for example 2.456, Array.prototype.filter() with parameter … Read more
You create instance of Encrypted method, but you set @code = 2, @string = “Hello” and @encrypted = []. So if you call @encrypted[0], ruby return nil. So you can modify your class like this: class Encrypt def initialize(code, string) @code, @string, @encrypted = code, string, [] end def to_byte @string.each_byte { |c| @encrypted << … Read more
If I understand your question correctly, this should do the trick. arr = [] for z in np.arange(0, 0.5, 0.01): Q = a + z t = b + z # here I would like to store Q and t in an array arr.append([t,Q]) for item in arr: i = item[0] j = item[1] It … Read more
Something like that? $i = 0; foreach($string as $menu){ $i++; if($i == 6){ break; } $menu_name = $menu[‘name’]; $menu_style = $menu[‘style’]; // i want to show total 5 menu names. if($menu_style == ‘magazine’ && $i <= 5){ // i have 5+ menus names (magazine style) // butt here i want to show just one last … Read more
As you say, HTML + javascript. I would recommend you using at least jQuery as you can get and modify HTML elements easily but you can go with just HTML + css + js (it’s slightly harder). With jQuery you can listen to page events, like click. $(document).on(“click”, function() { // Change text attributes. For … Read more
There is a problem in this line: double v[k] = log(log(sqrt(e[k]+1)+1)+1); in the first iteration k == 0 so you are trying to declare a zero sized array. I dont understand the code enough to tell you how to fix it, but a zero sized array is definitely not what you want in that place. … Read more
Since this code is littered with ternary operators, that seems to be what you are having the most trouble with. Basic syntax: condition ? a : b is the same as if (condition) { a } else { b } For weight: If you want to use kilo, just remove that whole line and set … Read more
Option -1: Download the jquery file and store it in the directory of the project and add the script tag in your html file and then add second js file which you can write jquery <script src=”https://stackoverflow.com/questions/37921952/jquery.min.js”></script> <script src=”main.js”></script> //Here you can write your custom js with jquery loaded first Option -2 : First take … Read more
Python strings are immutable. Any operation that appears to be changing a string’s length is actually returning a new string. Definately not your third option — a string can start out arbitrary long but can’t later change it’s length. Your option 1 sounds closest. You may find the Strings subsection of this web page helpful. … Read more
This is for MS SQL Server. You can easily replicate this if you use any other RDBMS declare @email varchar(100) set @email=”[email protected]” select substring(@email,1,charindex(‘@’,@email)-1) 3 solved Select @ before values
I think what you’re trying to do is this: float cal_area(triangle aTriangle) { float Area; Area = (aTriangle.vertices[1].x – aTriangle.vertices[0].x) * (aTriangle.vertices[2].y – aTriangle.vertices[1].y) – (aTriangle.vertices[1].y – aTriangle.vertices[0].y) * (aTriangle.vertices[2].x – aTriangle.vertices[1].x); if (Area < 0.0f) { return -Area / 2.0f; } else { return Area / 2.0f; } } solved Structured Data: Nesting Triangles … Read more
You could take a look at something like the cordova-universal-links-plugin, which can be found here. I am not sure whether this would work from an SMS and could not find any information on that, but I am guessing that any links send in an SMS can be opened in the browser. 1 solved Ionic application … Read more
here is the simple javascript code which will validate both email and phone number. <html> <head> <script src=”https://ajax.googleapis.com/ajax/libs/jquery/1.12.0/jquery.min.js”></script> <script> function ValidateEmail(mail) { var mailformat = /^\w+([\.-]?\w+)*@\w+([\.-]?\w+)*(\.\w{2,3})+$/; // if (/^\w+([\.-]?\w+)*@\w+([\.-]?\w+)*(\.\w{2,3})+$/.test(myForm.emailAddr.value)) if(mail.match(mailformat)) { alert(mail); return (true) } alert(“You have entered an invalid email address!”) return (false) } function validate() { var data=document.getElementById(“email”).value; checkNumberorEmail(); } function phonenumber(inputtxt) { … Read more
All seems well until line 82: st->readdata(); where the variable st is not initialised but used. 1 solved cross initialization error in while loop (c++ program)
public static void main(String[] args) { List<String> data = new ArrayList<String>(); String yourRequiredString = “dessert”; data.add(“apple fruit”); data.add(“carrot vegetable”); data.add(“cake dessert”); for (int i = 0; i < data.size(); i++) { if (data.get(i).contains(yourRequiredString)) { System.out.println(i); } } } Hope this helps… solved Find String in ArrayList Containing Phrase