Your date format MM/dd/yyyy’T’HH:mm:ss which your using is incorrect 1/31/2018 8:58:12 AM +00:00 and return different value from expected. SimpleDateFormat sdf = new SimpleDateFormat(“MM/dd/yyyy’T’HH:mm:ss”); return 1/31/2018T8:58:12 And you are trying to pass below 1/31/2018 8:58:12 AM +00:00 1 solved Exception on Date parsing android [duplicate]
Given this dataframe: df.head() complete mid_c mid_h mid_l mid_o time 0 True 0.80936 0.80943 0.80936 0.80943 2018-01-31 09:54:10+00:00 1 True 0.80942 0.80942 0.80937 0.80937 2018-01-31 09:54:20+00:00 2 True 0.80946 0.80946 0.80946 0.80946 2018-01-31 09:54:25+00:00 3 True 0.80942 0.80942 0.80940 0.80940 2018-01-31 09:54:30+00:00 4 True 0.80944 0.80944 0.80944 0.80944 2018-01-31 09:54:35+00:00 Create a 50 moving average: … Read more
I have found the solution. Just set customUserAgent : webView.customUserAgent = “Mozilla/5.0 (iPhone; CPU iPhone OS 11_2_5 like Mac OS X) AppleWebKit/604.5.6 (KHTML, like Gecko) Version/11.0 Mobile/15D60 Safari/604.1” solved Google label is not sharp (WKWebView)
Your description is vague, but to get what you described exactly: Public Sub Process() If Range(“A2”).Value <> “” Then Range(“B2”).Copy Range(“C3”) Range(“B2”).EntireColumn.Delete End If End Sub Edit In worksheet code: Private Sub Worksheet_SelectionChange(ByVal Target As Range) If Target.Address = Range(“A2”).Address And Range(“A2”).Value <> “” Then Range(“C3”).Value = Range(“B2”).Value Range(“B2”).EntireColumn.Delete End If End Sub I think … Read more
One of the problems is with this line: if (pass1 == newname & pass2 == newpassword){ System.out.println(“you are logged in”); }else{ System.out.println(“incorrect passoword or login”); } If you will debug this code, You will notice that this if statement, doesn’t compare the values of the String. For more details you may visit: https://stackoverflow.com/questions/513832/how-do-i-compare-strings-in-java Try this … Read more
what is wrong with this loop Initial value of b fails this check. 2*b+1 < 5 So neither loop body, nor the increment are ever executed. consider 2*b +1 as 2*c +1, i just ask, is this condition is a valid loop condition Yes, you can put any valid javascript expression there. As long as … Read more
if you run without –prod tag normally it will slow down your app. Use this ionic cordova run android –prod 1 solved Boost Ionic 2 Performances
Either you solve this with javascript or after submission with php. You can give your submit button a “onsubmit” and then check the value of your radio button group. If the wrong answer got selected, you show an alert or make a text box visible. Get Radio Button Value with Javascript Or you validate the … Read more
total = [] for line in lines: link = line.split(“ “)[1:] total.append(link) That should work. Let me know if that’s not what you were looking for. 1 solved storing each robots.txt value in an array
java.io.DataInputStream.readFloat() which invokes java.lang.Float.intBitsToFloat(int bits), you may try it. (read the api doc first) solved breaking float value in char and transmit it on tcp and read using java program [closed]
Try this: s = int(input()) sign = 1 if s < 0: sign = -1 s = s * -1 rev = str(s)[::-1] print(sign * int(rev)) solved How to reverse an integer while removing any leading zeroes?
The problem is in your first if statement: if (d=0) This is not comparing d to 0, but is assigning 0 to d. This expression then takes on the value of the assignment, i.e. 0, which evaluates to false. That in turn causes else if (d>0) to evaluate to false, bringing you to the else … Read more
The difference is likely to be negligible in terms of performance. The difference is the compiling of executing of three queries rather than one. But — assuming you are returning a fair amount of data — the returning of the data will probably dominate the performance. That said, be sure you use union all rather … Read more
OK, here is a fuller version of what you need: <?php function getDistance($addressFrom, $addressTo, $unit){ //Change address format $formattedAddrFrom = str_replace(‘ ‘,’+’,$addressFrom); $formattedAddrTo = str_replace(‘ ‘,’+’,$addressTo); //Send request and receive json data $geocodeFrom = file_get_contents(‘http://maps.google.com/maps/api/geocode/json? address=”.$formattedAddrFrom.”&sensor=false’); $outputFrom = json_decode($geocodeFrom); $geocodeTo = file_get_contents(‘http://maps.google.com/maps/api/geocode/json? address=”.$formattedAddrTo.”&sensor=false’); $outputTo = json_decode($geocodeTo); //Get latitude and longitude from geo data $latitudeFrom = … Read more
Find for std::map only takes a key value. So you would call it like this: if (purchase_list.find(“SearchName”) != purchase_list.end()) std::cout << “SearchName found!!” << std::endl; 0 solved c++ find a key match in a bi-dimensional map (map of map)