This should do it: Console.WriteLine(“Please enter a 7- bit binary number”); string number = Console.ReadLine(); int count = 0; for(int i = 0; i < number.Length; i++) { if(number[i] == ‘1’) { count++; } } Console.WriteLine(“Your number with parity bit is “+ number + (count % 2).ToString()); I’d imagine this is beyond your current level, … Read more
t = list(t) list(t) returns a new list while keeping t as a tuple. Think about a case you want to have both tuple and list. t2 = list(t) t is still a tuple while t2 is now a list. solved Permanently converting tuples to lists in Python [closed]
No, jQuery doesn’t have any method for that. You just use plain Javascript. Example: var handle = window.open(‘NewPage.html’, ‘_blank’, ‘width=600,height=300’); solved Window operations with JQuery? [closed]
var data = … the initial array var result = {}; for (var i = 0; i < data.length; i++) { var element = data[i]; result[element.id] = element; }; 3 solved Coverting json array to js objects
Here’s one of many ways to get it: >>> x = r”'”self.unsupported_cmds = [r’\s*clns\s+routing’,””’ >>> print x “self.unsupported_cmds = [r’\s*clns\s+routing’,” >>> import re >>> pattern = re.escape(x) >>> re.match(pattern, x) <_sre.SRE_Match object at 0x7ffca3f66098> >>> print pattern \”self\.unsupported\_cmds\ \=\ \[r\’\\s\*clns\\s\+routing\’\,\” solved Regular expression to match the string [closed]
You can use string.Format() with custom format specifiers. See details here. double dollars = 38.50; // your value int temp = (int)(dollars * 100); // multiplication to get an integer string result = string.Format(“{0:000000000}”, temp); // Output: 000003850 1 solved C# Convert currency to string, remove decimal point but keep decimals, prepend 0s to have … Read more
This is very crude and it is unclear what you want: s1 = “t his will fail” s2 = “t h i s s e p a d” def is_spaced(s): prev = s[0] result = “is spaced” for c in s[1:]: if not c.isspace() and not prev.isspace(): result = “not spaced” break prev = c … Read more
You could take a bitwise AND & with the day value and take this day. const days = { Monday: 1, Tuesday: 2, Wednesday: 4, Thursday: 8, Friday: 16, Saturday: 32, Sunday: 64 }, getDays = value => Object.keys(days).filter(day => value & days[day]); console.log(getDays(127)); // All Days console.log(getDays(80)); // Friday, Sunday console.log(getDays(7)); // Monday, Tuesday, … Read more
Introduction If you are working with JSON data and you encounter the error “Expecting ‘STRING’, got ‘}’”, you may be wondering how to fix it. This error occurs when the JSON data is not properly formatted. In this article, we will discuss the causes of this error and how to fix it. We will also … Read more
After looking at the data, it looks like their are two problems. Your collection of orders and items are not closed. The main json object is not closed. Let’s start with the Order and Item collection: The item collection in the order with recordId 3 is not closed properly. This is resulting in the order … Read more
Within your while loop instead of immediately printing the character that you read, store the char in a char array. Add an if statement that does a comparison that checks if the read char is a space character. If it is you should print the stored array and set the index of the array back … Read more
Assign the array as a value to the key “cars” myObj[‘cars’] = myObjArr; 2 solved Add array into object
while (aPhrase[i]) { c = aPhrase[i]; if (isVowel(c)) c=”!”; else if ((i % 3) == 0) c = toupper(c); putchar(c); ++i; } solved C++ How do you make every third letter of a char array into an uppercase letter? [closed]
Taking your question literally as “when I have no internet…” You’re requesting jQuery via a CDN; IF you literally have no internet connection then you’re not going to have access to jQuery. You need to download jQuery so you have a LOCAL copy available. Download it form the jQuery site then save it into your … Read more
I think, this is not a sorting but a generation of a new array that accomplish your output, in that case, you could do something like this: 1) First filter all A and all B on different arrays. 2) Then create a new array where progressively you put two elements (or the quantity available) of … Read more