Month: January 2023

[Solved] I need to work it like but using javascriptIs there any javascript function to forward to another page? [closed]

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Java practices site sums it up nicely: Forward a forward is performed internally by the servlet the browser is completely unaware that it has taken place, so its original URL remains intact any browser reload of the resulting page will simple repeat the original request, with the original URL Redirect a redirect is a two … Read more

[Solved] Properties in C# advantage [duplicate]

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From personal experience: You would generally have Private data member when you do not want it to be accessed externally through another class that calls the class containing the Private data member. Public data members are those that you can access by other classes to obtain its contents. My opinion is that it is simply … Read more

[Solved] Javascript User Input [closed]

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Use radio buttons <form> <fieldset id=”group1″> <input type=”radio” value=”” name=”group1″> <input type=”radio” value=”” name=”group1″> </fieldset> <fieldset id=”group2″> <input type=”radio” value=”” name=”group2″> <input type=”radio” value=”” name=”group2″> <input type=”radio” value=”” name=”group2″> </fieldset> </form> This answer is from here Multiple radio button groups in one form If you edit the code a bit you get (You use value1 … Read more

[Solved] C# Webservice to copy datas from one DB to Another [closed]

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if an employee’s datas changed in HR database automatically FD system must notified to refresh his database Consider looking at SQL Server Replication (or) AlwaysOn feature for this same purpose. Specifically you should look at Transactional Replication 2 solved C# Webservice to copy datas from one DB to Another [closed]

[Solved] Terminating app due to uncaught exception ‘NSRangeException’, reason: ‘*** -[__NSArrayM objectAtIndex:]: index 5 beyond bounds [0 .. 4] ‘

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Terminating app due to uncaught exception ‘NSRangeException’, reason: ‘*** -[__NSArrayM objectAtIndex:]: index 5 beyond bounds [0 .. 4] ‘ solved Terminating app due to uncaught exception ‘NSRangeException’, reason: ‘*** -[__NSArrayM objectAtIndex:]: index 5 beyond bounds [0 .. 4] ‘

[Solved] I’m trying to use this code to add items to the database, but it doesn’t add them to database. How to use POST METHOD using PHP CODE with ajax?

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I’m trying to use this code to add items to the database, but it doesn’t add them to database. How to use POST METHOD using PHP CODE with ajax? solved I’m trying to use this code to add items to the database, but it doesn’t add them to database. How to use POST METHOD using … Read more

[Solved] Writing a pattern in java [closed]

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for(int i=0; i <= n; i++) { for(int j=i; j > 0; j–) { System.out.print(j + ” “); } System.out.println(); } In the above loops. First loop goes from 0 to n times depending on value of n. Second loop is goes from value of i and keeps looping as long as j > 0. … Read more

[Solved] android error :ViewRootImpl$CalledFromWrongThreadException [closed]

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Your are touching the views(widgets) in the Non UI Thread. public class B extends Thread { TextView inputtext; Activity activity; public B(Activity activity, TextView x) { inputtext = x; this.activity = activity; } public void run() { activity.runOnUiThread(new Runnable() { @Override public void run() { inputtext.setText(“hero”); } }); } } While starting the Thread B … Read more

[Solved] I can’t use a “kill” process in my code. (its underlined with red) [closed]

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Lets make it very simple. Create a Process field and use it everywhere: private Process pNotepad; //Process field void sRecognize_SpeechRecognized(object sender, SpeechRecognizedEventArgs e) { if (e.Result.Text == “alice present”) { SoundPlayer sndPlayer = new SoundPlayer(Ai.Properties.Resources.My_name_is_A_L_I_C_E); sndPlayer.Play(); } if (e.Result.Text == “open notepad”) { //starting Process “notepad” pNotepad = new Process(); pNotepad.StartInfo.FileName = “notepad.exe”; pNotepad.Start(); } … Read more

[Solved] I want to design an ANDROID app which sets user mobile number by taking input from them and after that it always shows next activity using service? [closed]

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@Override protected void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); SharedPreferences sharedPref = PreferenceManager.getDefaultSharedPreferences(context); if(sharedPref.getBoolean(“isFirstTime”, true)){ Intent startWelcomeScreen = new Intent(this,Welcome.class); startActivity(startWelcomeScreen); finish(); Intent startWelcomeScreen = new Intent(this,Welcome.class); startActivity(startWelcomeScreen); finish(); } setContentView(R.layout.activity_main); } MainActivity.java If your app is executing for the first time, then it is redirected to Welcome screen. Notice the finish() call in the Main Activity. … Read more