You’re going to have to provide more than just this snippet of code. What is the Time object you’re accessing via an indexer? Have you debugged this to see if Time[0] actually has a value? My guess here would be that Time[0] doesn’t return a value that DayOfWeek can work with hence Substring(0,3) is being … Read more
Look at the Math class. https://docs.oracle.com/javase/7/docs/api/java/lang/Math.html Math.PI Math.pow(…) Math.abs(…) etc. 11 solved Can someone help me to translate this line of code in java?
There are two parts to your question: 1. Emulator not working : HAXM is not working and emulator runs in emulation mode This one is already answered here: How to fix: “HAX is not working and emulator runs in emulation mode”. It was just one search away. AND 2. “Hello! World” not showing That is … Read more
That: return first_3 returns and therefore ends the function. The remaining code is just ignored, because you will never get past the return. solved Why does my return statement ignore the rest of my code in a function in python?
You should indent your main function with spaces or tabs. (4 spaces is recommanded) Like this: def main() num=input() # rest of your main code main() I saw you already did this for if/else, you should also do it for functions. I recommend you take a beginner python course like the one of codecademy. solved … Read more
input = 65 output = float(‘0.’ + str(input)) print(output) 1 solved Python how to add “0.” in-front of a number
The first condition should be greater or equal because when pat = 24, the program it’s going to the else and then is trying to access the range in the index 24 but the last index is 23. roue = range(24) pat = int(input()) if pat >= 24: while pat >= 24: pat -= 24 … Read more
I suspect what you are looking for is: public abstract class A { public abstract int add(int n1, int n2); public abstract int add(int n1, int n2, int n3); } public abstract class B : A { public override int add(int n1, int n2) { return (n1 + n2); } } public class C : … Read more
Check this code, I didn’t have all of your code for testing it for (int f = 0; (f <= 7); f++) { for (int c = 0; (c <= 7); c++) { if ((((((c % 2) != 0) && ((f % 2) == 0)) || (((c % 2) == 0) && ((f % 2) … Read more
Something along these lines should work. I might have made syntax errors 😀 using System; class Program { static void Main(string[] args) { var calculator = new Calculator(); var input = GetNumbers(); calculator.Add(input); Console.WriteLine(calculator.Add(input)); } public static int[] GetNumbers() { Console.WriteLine(“Enter Numbers Seperated With a Space”); string input = Console.ReadLine(); //Get user input with this … Read more
If you want to add all the values of s1, you need to iterate over the values() of dictionary students. students={ 1: {“pup1”: “001”, “s1”: 10, “s2”: 20}, 2: {“pup2”: “124”, “s1”: 20, “s2”: 30}, 3: {“pup3”: “125”, “s1”: 30, “s2”: 40}} sum1 = 0 for data in students.values(): sum1 += data[‘s1’] avg = sum1 … Read more
Run this code and test with all your inputs.It should solve your scenario. String regex = “^[0-9.]{5}$”; Pattern pattern = Pattern.compile(regex); String name= “123.4”; Matcher matcher = pattern.matcher(name); System.out.println(matcher.matches()); 1 solved Regex for string that validates for a number which may include decimal and for a particular length [closed]
You could defer the evaluation by collecting the values of the call. And then look with Array#some and Boolean as callback if some value is truthy. if ([checkPassword(), checkUserName()].some(Boolean)) { // … } 0 solved How to write an if statement in Javascript?
change this line of code 93: let author = dict![“author”] as? [String: AnyObject] 3 solved Having trouble with a nil while unwrapping an Optional value
The really smart answer is: #include <algorithm> As in: #include <iostream> #include <algorithm> main() { int x = 1, y = 2; std::swap <int> (x, y); std::cout << “Expecting 2: ” << x << std::endl; std::cout << “Expecting 1: ” << y << std::endl; } Because swap is already included in <algorithm>! The best C++ … Read more