I’ve mocked up some table data to test my query. WHERE clauses must be positioned after JOINs. You are also a little ambiguous about the comparison of COUNT AND 5 — if you want more than 5 then >5, if you want 5 or more then >=5. SQL: (SQLFiddle Demo) SELECT a.user_id,a.username,COUNT(b.user_id) FROM users a … Read more
A way to do this in C#: I don’t claim this the best way, but it gives an idea. using System; using System.Collections; using System.Collections.ObjectModel; namespace ShowNames { class Program { static void Main(string[] args) { Console.WriteLine(“Hello World!”); var People = new Collection<Person>() { new Person() { Name = “Jack”, Age = 24, AverageGrade = … Read more
Since font-awesome icons are fonts, they can be added to options by Unicode: <script src=”https://unpkg.com/angular/angular.js”></script> <link rel=”stylesheet” href=”https://unpkg.com/font-awesome/css/font-awesome.css”> <body ng-app> <i class=”fa fa-camera-retro”></i> fa-camera-retro<br> <select ng-model=”choice” class=”fa”> <option value=””>Choose</option> <option value=” camera”> camera</option> <option value=” bell”> bell</option> <option value=” bicycle”> bicycle</option> </select> <br> Choice = <span class=”fa”>{{choice}}</span> <br><span class=”fa”>--</span> </body> The DEMO on PLNKR The … Read more
if true condition is always satisfied. You should modify your userInput() method to return a boolean value, if you want to use it. func userInput() -> Bool { return Util.shared.isPalindrome(word: word) } And then handle the result: if userInput() { // do something } else { // do something else } solved Why is the … Read more
In this case, “of” is the label for the argument called “name”. If you were to call this function, it would be student(of: “Mathematics”) However inside the student function, you would get it’s value with “name” func student(of name: String) -> String { print(name) // TODO: Do something and return } Just a suggestion, IMHO … Read more
Assuming you have a model class for your electrician object named Electrician, to get a list of electrician objects, please use the following code: DatabaseReference rootRef = FirebaseDatabase.getInstance().getReference(); DatabaseReference electricianRef = rootRef.child(“Employee”).child(“Electrician”); ValueEventListener valueEventListener = new ValueEventListener() { @Override public void onDataChange(DataSnapshot dataSnapshot) { List<Electrician> list = new ArrayList<>(); for(DataSnapshot ds : dataSnapshot.getChildren()) { Electrician … Read more
You create a vector of size n. Then you check for each input line if the second string contains the text gmail and you store the pair in the i-th element. You increment i even if you skip the input. That means that some elements of the vector can remain empty. At the end you … Read more
Yes, it’s possible to access the web server from an external network, depending on your current network configuration. There are two simple solutions I think would suit you. Configure your firewall if needed, enable port forwarding in your router settings to forward port 80 to the internal IP of the machine running your XAMPP-server. If … Read more
So the pseudocode for this function is roughly like this: function checksum(DATA) RESULT = 0xA50F74FF; for each DWORD in DATA do RESULT = RESULT xor DWORD return RESULT where DWORD is a four-byte integer value. The function is actually going though (almost) all of the data (not 25%) but it’s doing it in 4-byte increments … Read more
Use Array.reduce to calculate the sum const sum = array.reduce((acc, o) => acc + parseInt(o.value), 0) 2 solved sum all values of an object in an array of objects javascript
Have to write a program that gives me the sum of even numbers without using if statements nor loops nor array how should I do that in java? solved Have to write a program that gives me the sum of even numbers without using if statements nor loops nor array how should I do that … Read more
int RTPower = Int32.Parse(powerTextBox.Text); or for decimal values decimal RTPower = Decimal.Parse(powerTextBox.Text); You need to convert the value from a string to an int. Also, I assume you are new to c# – my advice would be to avoid using var and explicitly declare your variables. It will make things clear and easier for you … Read more
You can use Contains status = false; for (var i = 0; i < ids.Count; i++) { if (list.Count > 0 && !list.Contains(ids[i])){ list.Add(ids[i]); //add this, be it duplicate or not status = true; //different element found break; //break if this is not duplicate } else { //do something for duplicate list.Add(ids[i]); //add this, be … Read more
The Logcat shows that the exception occurred when parsing Integer when the provided Integer is “”. From the fields you are using, the integer is probably edtAgeInput. The way you solve it depends from how you want to handle empty values. If you are getting the user input, what should happen if age is not … Read more
Try $().length property instead, and place this snippet at the very bottom of the page, before closing body tag <script src=”http://ajax.microsoft.com/ajax/jquery/jquery-1.4.2.js” type=”text/javascript”></script> <script type=”text/javascript”> jQuery(document).ready(function($) { if ($(‘.toplink’).length > 0) { $(‘.toplink’).addClass(‘adin’).attr(‘data-aid’, ‘114’); } }); </script> 2 solved Add new class and attributes to div if it exists on the page [duplicate]