A little bit of an advice: Keep everything as numbers for as long as possible. As you maybe noticed, handling strings is quite tedious. So you have inputs of both cpu and user. Now this makes two numbers.. Then its time for a switch or therealike: switch (user) case 1: if (cpu==1){ printf(‘draw’); }elseif (cpu==2 … Read more
Introduction This article provides a solution to the issue of underlined text getting crossed out in Firefox. This issue is caused by a bug in the browser and can be fixed by disabling a certain feature. The article provides detailed instructions on how to do this, as well as other possible solutions. Solution The issue … Read more
You have syntax errors. Try to use this if($type==’1′){$link_medalje=”<a href=”https://stackoverflow.com/questions/25112942/javascript:void(0);” onmouseover=”prikazimis(\”Administrator\’);” onmouseout=”sakrijmis();”><img src=””></a>’;} 2 solved onmouseover and onmouseout not work
[EDITED] The delete operator is only for deleting a property from an object. Your config variable contains an array of objects, so delete will not do what you want at all. You need to iterate through the config array and use something like splice to delete the array items that have the same name, date, … Read more
To display the JSON in sections efficiently you have to decode the JSON into a struct with a title member struct Root : Decodable { let status : Bool let sections : [Section] private enum CodingKeys : String, CodingKey { case status, data } init(from decoder: Decoder) throws { let container = try decoder.container(keyedBy: CodingKeys.self) … Read more
Thanks Guys for all the Moral Support because without you guys i would’t have researched this much. Thanks again solved it with: <?php echo $_SESSION[‘name’]; ?> now can anybody tell me how can i include in my form text field. Please solved I Want to create a Contact form with User profile name auto input … Read more
Unfortunately, this is possible. But in no sense can I condone it. #include <iostream> namespace std { class not_actually_cout{}; template<typename T> not_actually_cout& operator<< (not_actually_cout& stream, const T & v) { std::cout << v << std::endl; return stream; } not_actually_cout not_actually_cout_instance; } #define cout not_actually_cout_instance int main(void) { cout << “why god why”; cout << “please … Read more
There are lots of ways to do it, I have done this in the past by creating a specific class to wire up my values: public class LanguageItem { public bool Disabled { get; set; } public string Value { get; set; } public string Name { get; set; } } Then you can create … Read more
data returns an array .So replacing $udetails->comp_person_name with $udetails[‘0’]->comp_person_name solved the issue solved Trying to get property of non-object
You will need to implement the following: public Customer findCustomer(int id) { for (int i = 0; i < Bank.AllCustomers.Count(); i++) { if (Bank.AllCustomers.ElementAt(i).Id == id) return Bank.AllCustomers.ElementAt(i); } return null; //Not found } This will simplify your life, because when you want to add/subtract money to a given account, or remove it, or edit … Read more
Simply declare it outside the function: var currentDate; //declare outside function jQuery(“#datepicker”).datepicker({ onSelect: function(value) { alert(‘The chosen date is ‘ + value); currentDate= Math.round(Date.parse(value)/ 1000); } }); 1 solved JQuery- using a variable outside of the scope of the function
Do you mean something like this? $sql = “INSERT INTO prueba (nombre) VALUES ($nombre) WHERE id = ‘$id'”; 1)use mysqli instead of mysql 2) instead of $row[0] use $row[nombre_ID] (if thats what its called) 3) do the same for $row[1] to like $row[nombre] 4) change mysql_fetch_row($query) to mysqli_fetch_array($query,MYSQLI_ASSOC) 6 solved Copy current record to another … Read more
It show an error “operator ‘==’ cannot be applied to operands of type ‘string’ and ‘int’ ” in “where(x => x.person_id == id)” solved It show an error “operator ‘==’ cannot be applied to operands of type ‘string’ and ‘int’ ” in “where(x => x.person_id == id)”
You need to keep printing space in inner loop and once it come out from the inner loop print * and/or # accordingly. Scanner in = new Scanner(System.in); int x=0; System.out.println(“Enter number: “); x = in.nextInt(); for(int i=1;i<=x;i++){ for(int j=1;j<=i;j++){ System.out.print(” “); } if(i%2==1) { System.out.println(“*”); }else { System.out.println(“#”); } } >>>Demo Link<<< 0 solved … Read more
The only way I know is to json encode an array like this: <?php echo json_encode( [ “bundles” =>[ [ “type” => “TYPE1”, “items” => [ [ “bom” => [ [ “type” => “C”, “stockId” => “1”, “quantity” => 1, “metadata” => [ “key” => “value” ] ], [ “type” => “E”, “quantity” => 1, … Read more