You should probably look at message queues (the Microsoft version is called MSMQ and is built into Windows. Other message queues are available). They are designed for exactly this sort of scenario. Essentially, your application write an event to it’s local message queue. This will attempt to send it to the remote queue (on the … Read more
You Could Well Do This First Make a char array , Containing Number Of Maximum Stars that will be asked to print. char stars[] = “***************************************”; Then Ask User Input for number of stars they want to print. int a; printf(“Enter Number of Stars You Want To Print : “); scanf(“%d” , &a); Then You … Read more
Just make it one: create function ops() returns table (region varchar, man integer, woman integer, test integer) as $$ Select region,man, woman, Case When woman > man then woman – man When woman < man then man – woman ELSE 0 END AS test From people; $$ language sql; 0 solved Postgresql switch query to … Read more
From [-5, 5] to [5, 10]: output = (input + 7.5) * 0.5 From [5, 10] to [-5, 5]: output = (input – 7.5 ) * 2 From [5, 10] to [5, -5]: output = (input – 7.5 ) * -2 The idea is to first shift the average of input’s range to average of … Read more
To keep it simple, in case A, your program has to initialize i only once. Assign values to i only array.Length times. Increase i values only array.Length times. do the line execution and comparison 2*array.Length times. In case B, initialize i twice. Assign values to i 2*array.Length times. Increase i values 2*array.Length times. do line … Read more
You can use regular expressions: import re s = [el for el in re.split(‘([\W+])’, ‘☕ Drink the ❶ best ☕coffee☕’) if el.strip()] print(s) output: [‘☕’, ‘Drink’, ‘the’, ‘❶’, ‘best’, ‘☕’, ‘coffee’, ‘☕’] 2 solved Separate string in Python [closed]
In short Java Application for Swing based application and JavaFX for JavaFX based application. It depends on what you’re building. Swing has more components around for it (3rd party as well as built in) and not all of them have made their way to the newer JavaFX platform yet. On the other hand, FX provides … Read more
Why do I have to skip the month of february in the for loop and use mes->fevereiro[j] instead of mes->meses[1][j]? [closed] solved Why do I have to skip the month of february in the for loop and use mes->fevereiro[j] instead of mes->meses[1][j]? [closed]
Fairly simple with jQuery – see the code comments for explanation. // shorthand for on document load $(function() { // a variable to store our current first letter var currentFirstLetter; // for every child of mylist $(‘.mylist’).children().each(function() { // take the first character of its content var thisLetter = $(this)[0].innerHTML.substr(0,1).toLowerCase(); // if its different to … Read more
I didn’t really get what you mean, but if you want to replace a specific text in your file with a random integer then try: import fileinput from random import randint with fileinput.FileInput(fileToSearch, inplace=True, backup=’.bak’) as file: for line in file: print(line.replace(textToSearch, textToReplace), end=”) with textToReplace = randint(1990, 2020) Hope that helps 7 solved replace … Read more
You can use the following recursive function to get the depth where the uuid value is found. This version returns value 0 if the uuid value is not found at all. function searchDepth($uid, $array, $depth = 0) { $depth++; foreach ($array as $element) { if (isset($element[‘uid’]) && $element[‘uid’] == $uid) { return $depth; } else … Read more
UPDATE t1 SET t1.IdTwo = (SELECT top 1 t2.IdTwo FROM TableTwo t2 WHERE t2.IdOne = t1.IdOne AND t2.Active = 1) FROM TableOne t1 1 solved Update value of row based on result from another table SQL Server
Functions return their value in $v0; the print integer syscall expects its argument in $a0. You need to move $a0 to $v0 before you do the print, otherwise you’ll be printing whatever happened to be in $a0 (which in the case is the last value that you recursively added; i.e. 10). solved the answer is … Read more
You have to concatenate the two fields, and pass them together to the group by as following select id, concat(`field1`,`field2`) as `together` from table_name group by together 1 solved how to select duplicate record as one record in mysql
this is Ugly, but will eventually work: COLUMN = ‘jksjdksls#$#$@@kskjfjf,”123,456,789″ lsnslkdswfnslsjfls’ left( right(COLUMN,len(COLUMN)-instr(COLUMN,””””)), instr( right(COLUMN,len(COLUMN)-instr(COLUMN,””””)), “”””) -1 ) –> 123,456,789 This is what is done: We take this string ‘jksjdksls#$#$@@kskjfjf,”123,456,789″ lsnslkdswfnslsjfls’ find the first occurence of ” with instr(COLUMN,””””) –> returns 24 take the right end of the string with. Therefore we need to take … Read more