Scott is right, and Leigh was right before, when you asked a similar question, jSoup is your best option. As to a regex solution. This is possible with regex but there are problems that regex cannot always solve. For instance, if the first or second table contains a nested table, this regex would trip. (Note … Read more
In void add(cluster*), the name cluster resolves to the data member queue::cluser, not to the class name ::cluster. Avoid giving the same name to a type and to a variable. You are only confusing yourself. solved Cluster is not a type + cluster does not name a type error. Error for add(cluster *). Cant have … Read more
Make your result an associative array keyed by user ID. Then it’s easy to collect all the image paths for the same user ID. $result = array(); while ($rowb = $result->fetch_assoc()) { $userid = $rowb[‘user_id’]; if (!isset($result[$userid])) { $result[$userid] = array(‘user_id’ => $userid, ‘image_path’ => array()); } $result[$userid][‘image_path’][] = $rowb[‘image_path’]; } The resulting JSON will … Read more
Given the following dataframe: df = pd.DataFrame({ ‘B’: [‘a’, ‘a’, ‘c’, ‘d’, ‘a’], ‘C’: [‘aa’, ‘bb’, ”, ‘dd’, ‘do’], }) B C 0 a aa 1 a bb 2 c cb 3 d dd 4 a do value_counts method counts the occurrences of all values in column ‘B‘: df.B.value_counts() a 3 d 1 c 1 … Read more
In general the question seems to be how to ensure that something happens at a certain date-time. Work out what the target date-time is and write it down somewhere stable (a file, user defaults, whatever) along with what has to happen then. Watch the clock. A timer that fires every minute will probably be good … Read more
Vocabulary lesson: these are actually combinations, not permutations. With permutations, a different order is a different permutations. Also, what you want technically isn’t all combinations, as there is the empty combination [] and it seems you don’t want that included. Anyway, here’s something I whipped up. function getCombinations(array) { let combinations = []; for (let … Read more
Search a lot and find a way $user=$_REQUEST[‘user’]; Php change to $user=$_REQUEST[‘username’]; Will work Perfectly.. Thanks to Yazen https://stackoverflow.com/users/3604083/yazan solved value
You need to be more precise when you write code. Your array of integers has a different number than the example output you want. I thought perhaps you wanted a set for a response, but there were two fails in there, so I ruled that out, too. Another source of imprecision are the ranges you … Read more
Put this function call where you show the response data alert writeToRecordStore(sb.toString().getBytes()); The function definition is as below: private static String RMS_NAME = “NETWORK-DATA-STORAGE”; private boolean writeToRecordStore(byte[] inStream) { RecordStore rs = null; try { rs = RecordStore.openRecordStore(RMS_NAME, true); if (null != rs) { //Based on your logic either ADD or SET the record rs.addRecord(inStream, … Read more
>>> lst = [6,12,8,9,1,18,24] >>> print([value for index,value in enumerate(lst) if index%6==0 and value%6==0]) [6 , 24] solved How to do list comprehension that display a list elements whose elements and index are divisible by 6?
That should do it: #include <stdio.h> #define HEIGHT 5 #define WIDTH 7 int main() { int roof = WIDTH / 2; int offset = (WIDTH % 2 == 0) ? 1 : 0; for(int col_start = roof; col_start > 0; col_start–) { if(col_start != roof || offset != 1) { for(int col = 0; col … Read more
Does this return what you want? [[1,2] , [3,7] , [2,9] , [10,19]].sorted(by: {$0[0]<$1[0]}) 3 solved Is there a way to sort an array by a subarray’s index in Swift?
If the table was as follows (I’ve renamed user_id, post, and favorites columns to clarify their roles as I understand them) ————————————- |Users |posts |favorites | |———–|———–|———–| |id |id |id | |username |title |uid | |password |post_text |post_id | | |uid | | | |fav_id | | ————————————- This sql code can be used to … Read more
After an if and after an else there needs to be exactly one statement. The statement after if will be executed if the condition is true, the statement after else will be executed if the condition is false. Now the important thing to understand is the following: A single semicolon ; is a statement. It’s … Read more
This has nothing to do with Java. In the first example you call lastNode once and store the result in p. In your second example, you call lastNode twice, but after the first call, you add a new last node to your list, so the return value is different the second time! 0 solved Why … Read more