[ad_1] The solution is relatively simple: Philosopher attempts to get fork on left SUCCEED -> Continue to step 2 FAIL -> wait (for a while) Philosopher attempts to get fork on right SUCCEED -> Continue to step 3 FAIL -> Release left fork and wait (for a while) Eat and release both forks. Then wait … Read more
[ad_1] Serializing a List<LinkedListNode<string>> is a bit of an odd thing to do – normally one would just serialize the underlying linked list. Perhaps you’re trying to serialize a table that gives the nodes in a different order than the underlying list? If that’s the case, it might appear that one could serialize the node … Read more
[ad_1] Try the following approach #include <stdio.h> #include <string.h> int main(void) { enum Animal { cat, dog, elephant }; char * animal_name[] = { “cat”, “dog”, “elephant” }; enum Animal b; size_t n; char s[100]; fgets( s , sizeof( s ), stdin ); n = strlen( s ); if ( s[n – 1] == ‘\n’ … Read more
[ad_1] Yes, you can simply use multiple from clauses: var result = from x in list1 from y in list2 from z in list3 select x+y+z; In the csharp interactive shell, this gives: csharp> var list1 = new string[] {“A”, “B”, “C”}; csharp> var list2 = new string[] {“1”, “2”, “3”}; csharp> var list3 = … Read more
[ad_1] Well, if I am interpreting your question right, you can declare an array or list, then initialize these elements in a loop For example (array) (if you want a fix number of elements): int n = 10; // number of strings string[] str = new string[n]; // creates a string array of n elements … Read more
[ad_1] char y[] = { ‘a’, ‘b’, ‘a’, ‘c’ }; int count[52] = {0}; for (int i = 0; i < (sizeof(x) / sizeof(char)); i++) { if (y[i] >= 65 && y[i] <= 90) count[y[i] – ‘A’]++; else if (y[i] >= 97 && y[i] <= 122) count[(y[i] – ‘a’) + 26]++; } for (int i … Read more
[ad_1] The memory is being managed by your numpy arrays. As soon as they go out of scope (most likely at the end of the PySparse constructor) the arrays cease to exist, and all your pointers are invalid. This applies to both large and small arrays, but presumably you just get lucky with small arrays. … Read more
[ad_1] This seems to be a delay or error during the permission propagation time. Note that permission propagation is not immediate and can have a delay. You may have to wait a few minutes to see the changes reflected. The default time is 60 seconds and it can take up to 7 min However if … Read more
[ad_1] To click on the element with text as Show 10 more deals on the page https://www.uswitch.com/broadband/compare/deals_and_offers/ you can use the following solution: Code Block: from selenium import webdriver from selenium.webdriver.support.wait import WebDriverWait from selenium.webdriver.support import expected_conditions as EC from selenium.webdriver.common.by import By url = “https://www.uswitch.com/broadband/compare/deals_and_offers/” options = webdriver.ChromeOptions() options.add_argument(“start-maximized”) options.add_argument(‘disable-infobars’) browser = webdriver.Chrome(chrome_options=options, executable_path=r’C:\Utility\BrowserDrivers\chromedriver.exe’) … Read more
[ad_1] To see if a file name exists simply check it as follow: File file = new File(filePath); if (file.exists()) { // do something } Note that the file can be also a directory, not necessarelly a true file. If you need also to check if it is a file: File file = new File(filePath); … Read more
[ad_1] Maybe you can initialize your List? private static List<string> SetPointObjectDefectRow(string[] row, string owner) { const int zone = 54; const string band = “U”; List<string> result = new List<string>() { owner, string.Empty, string.Empty }; if (Helpers.NormalizeLocalizedString(row[7]).Contains(@”a”) || Helpers.NormalizeLocalizedString(row[12]).Contains(@”b”)) { var geoPosition = UtmConverter.StringUtmFormatToLocation(zone, band, Convert.ToDouble(row[15]), Convert.ToDouble(row[14])); var beginGeoPosition = geoPosition.LatString + “, ” + … Read more
[ad_1] It doesn’t return anything. You can check that by logging the result of the forEach call: var arr = [1, 3, 2]; var arr_temp = []; console.log(arr.forEach(function (i) { return arr_temp.push(i + i); })); // undefined console.log(arr_temp); // 2, 6, 4 3 [ad_2] solved .forEach() Javascript function is returning an Array?
[ad_1] This is a stack trace. It shows not just where the actual error occurred directly, but also what the program was doing while it occurred. The code df.loc[‘origin’ == ‘US’] (on line 6) is at the top of the trace, meaning it’s the root cause, but this by itself is not an error. This … Read more
[ad_1] First you should check that you understand the definition of the Fibonacci numbers. By definition, the first two Fibonacci numbers are 0 and 1, and each remaining number is the sum of the previous two. Some sources omit the initial 0, instead beginning the sequence with two 1s. You need two variables to remember … Read more
[ad_1] Use implode(). $yourArray = array_map(“mysql_real_escape_string”, $yourArray); $query = “SELECT * FROM user_detail WHERE user_id='”; $query .= implode($yourArray, “‘ OR user_id='”); $query .= “‘”; Or indeed, use the SQL IN keyword: $yourArray = array_map(“mysql_real_escape_string”, $yourArray); $query = “SELECT * FROM user_detail WHERE user_id IN (‘”; $query .= implode($yourArray, “‘,'”); $query .= “‘)”; 0 [ad_2] solved … Read more