Month: August 2022

[Solved] Browser specific css for Internet Explorer [duplicate]

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Load the css_gen.css file first and then load the css_IE.css file. <link rel=”stylesheet” type=”text/css” href=”https://stackoverflow.com/css_gen.css”> <!–[if IE 6]> <link rel=”stylesheet” type=”text/css” href=”http://stackoverflow.com/css_IE.css”> <![endif]–> Hope that solves your problem. And try this too http://css-tricks.com/how-to-create-an-ie-only-stylesheet/ solved Browser specific css for Internet Explorer [duplicate]

[Solved] Creating json data with duplicate keys [closed]

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PHP comes with a JSON extension. The only thing you will need to figure out is how you have to create the data in PHP. [] in JSON is an array, {} is a dictionary. For the part mentioned you’ll need something like this: $foo = array( array( ‘c’ => array( array(‘v’ => ‘date3’), array(‘v’ … Read more

[Solved] Image noise removal is part of image enhancement or image restoration? [closed]

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Well there is the wikipedia page http://en.wikipedia.org/wiki/Image_restoration It says that Image restoration is the operation of taking a corrupted/noisy image and estimating the clean original image Image enhancement […] is designed to emphasize features of the image that make the image more pleasing to the observer The difference between the two is, as explained in … Read more

[Solved] XML nodes with SQL

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Please try the following solution. What we are doing here is called shredding, i.e. converting XML into rectangular/relational format. I am shooting from the hip because DDL and sample data population were not provided. The provided XML is not well-formed due to missing root element, but SQL Server allows to handle XML fragments. We are … Read more

[Solved] Multiple Insert or Replace Query in Android SQLite

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You can improve speed for Multiple/Batch Database Inserting or Replacing operation using concept of transaction and compileStatement so your query will be compiled only once. For Example: db.beginTransaction(); try { String sql = “Insert or Replace into Items (itemNumber, description,unitOfMeasure, weight) values(?,?,?,?)”; ArrayList<ItemMaster> itemsList = // Retrieve your items list here for(int i=0;i<itemsList.size();i++) { SQLiteStatement … Read more

[Solved] Can’t find the fix for: takes exactly 1 argument (2 given)

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import maya.cmds as cmds class ButtonPress: def __init__(self): self.value = 0 def buildUI(self): window = cmds.window(title=”Press Button”, w = 100, h = 50) columnL = cmds.columnLayout(w = 100, h = 50) cmds.button(parent = columnL, label=”Press me”, w = 100, h = 50, command = self.__increaseAndPrint) cmds.showWindow(window) def __increaseAndPrint(self, *args): # maya throwing through ui a … Read more

[Solved] Printing a statement using threads in Java [closed]

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I think your problem is in this method: synchronized void PrintMsg(String msg) { System.out.println(msg); try { wait(); } catch (InterruptedException e) { System.out.println(“Exception”); } System.out.println(msg); notify(); } The thread that call it are going to call wait() which causes them to wait indefinitely for someone to call notify(). But there are no other calls to … Read more

[Solved] How to divided number into three continuous parts such that the third part is the sum of the other two? [closed]

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Here’s my solution, it checks all possible combinations of splitting given number in 3 parts and checks whether sum of first two components are equal the third one. def correct_number(x): str_nmbr = str(x) for result_split in range(len(str_nmbr)-2): part_3 = int(str_nmbr[-result_split-1:]) for components_split in range(len(str_nmbr)-2-result_split): part_2 = int(str_nmbr[1+components_split: -result_split-1]) part_1 = int(str_nmbr[:components_split+1]) if part_1 + part_2 … Read more