I think it is because your footer position is fixed with a fixed height. Also, next time post your code here. (or a JsFiddle) Not a link. Net begonnen met html zie ik. 2 solved my footer chances if i put something above it
1.create a table with some GUID as primary Key 2.do inserts and check fragmentation 3.Rebuild check Fragmentation you also can do search like below for more SO Examples sql server fragmentation site *.stackexchange.com simple Demo: create table test1 ( id varchar(255) primary key default newid() ) insert into test1 default values go 100 –check fragmentation … Read more
You shouldn’t use that many options. This is not only slow, but also uncomfortable. 2 solved How to remove lag when using more than 50,000 options in tag in html?? [closed]
It is an BitwiseOperators (Bitwise Right Shift): https://wiki.python.org/moin/BitwiseOperators All of these operators share something in common — they are “bitwise” operators. That is, they operate on numbers (normally), but instead of treating that number as if it were a single value, they treat it as if it were a string of bits, written in twos-complement … Read more
It’s not possible to do imagesc and axis off at the same time. However, you can modify the imagesc code to achieve this but you will not get MathWorks support for the modified version. To avoid the graphical artifacts, try different figure renderers: painters, opengl, … You can also try the startup flag -softwareopengl. solved … Read more
This is essentially the same as the solution to your previous question. data = [ [ 123.0, 23, “id1”, 34, “abc” ], [ 234.1, 43, “id2”, 24, “jsk” ], [ 423.5, 53, “id1”, 1, “xyz” ], [ 1.4, 5, “id2”, 0, “klm” ] ] sums = Hash.new {|h,k| h[k] = [0, 0, 0] } data.each_with_object(sums) … Read more
All of these solutions have me attaching to the DOM. I guess there is no solution if using Chrome and not attaching. solved non attached element width not working in Chrome
It is saying that on this line: med_sev =(accidents[quotient][1] + accidents[quotient+2][1])/2 you are trying to index something that doesn’t exist. I imagine it is on the part accidents[quotient+2][1] because this is the greater indexed one. What does this mean? Well suppose that accidents is something like accidents = [[thing0, thing1], [thing2, thing3]] now say the … Read more
You can use a counter to see if values of 1 are sequential. function containsSequence(arr, val, max) { var count = 0; for (var i = 0; i < arr.length; i++) { if (arr[i] === val) { counter++; // increment the counter by 1 } else { counter = 0; // reset counter } // … Read more
Noting your actual attempted solution posted in the comment to @ChristopherLouden’s answer, which looks suspiciously like the solution offered by @Jilber to a question from earlier today, I can finally reproduce your problem and offer a solution. For the sake of simplicity, here’s a much smaller data.frame to start our work with. Note that the … Read more
I do not exactly the rules you want to realize. Here is a simple example, how you could do things. Tell us more about your rules and your tries and you will get better answers. import random def random_change_case(old): new = ” for c in old: r = random.random() if r < 0.4: new += … Read more
prepare() goes with execute() Prepared statements basically work like this: Prepare: An SQL statement template is created and sent to the database. Certain values are left unspecified, called parameters (labeled “?”). Example: INSERT INTO mtTable VALUES(?, ?, ?) The database parses, compiles, and performs query optimization on the SQL statement template, and stores the result … Read more
The format argument you give should reflect the format that the data is currently in, not the format that you want to convert it to, so you would have to set format = “%Y-%m-%d”. Read the documentation on strptime again and it should make sense. 1 solved strptime returning NA values [closed]
I leave the refactoring of regex on you, but this is something you can do using String.prototype.match. function checkStr(str) { let match = str.match(/(\d)\?{3}(\d)/); return match && +match[1] + +match[2] === 10; } let out = checkStr(‘bdhfr6???3hfyrt5???eee5’); console.log(out) out = checkStr(‘bdhfr6???4hfyrt5???eee5’); console.log(out) solved consider a string which has question marks, numbers , letters [closed]
I think the problem you are dealing with is you do not take input correctly. In your current approach, user has to pass a string(“”), and also print() is expecting a string to be printed out. So in order for your function to work, you need to modify your print() to print(name1 + “\n” + … Read more