The 1000th element is actually just 1 due to this constructor. vector <long long> vec(2000,1); // fill with 2000 elements, each set to 1 Then after this line vec.push_back(31); // element [2000] is now 31 Therefore your final vector is {1, 1, 1, …, 1, 1, 31} // length 2001 elements solved Can’t push_back() after … Read more
The main problem is that you are iterating over collection in which you append during the cycle and even through iterator which is defined as int instead of Agent. Create new vector and push your generated values into this new vector. Also be aware of using new keyword. You must dealocate that memory later. Solution: … Read more
you should define your vector variable first : std::vector<string> mylist (5); then use a reverse_iterator for it : std::vector<string>::reverse_iterator rit = mylist.rbegin(); update: if you put using namespace std; then when you compile your code you will find that the problem with list={} because list is reserved class in namespace std so you can’t use … Read more
push_back() and insert() both call grow(), which fails to increase the capacity because GROWER is an int, so 1.6 truncates to 1, and multiplying capacity * 1 doesn’t change its value. But even if capacity were increased properly, the data_ptr array is not being re-allocated at all to fit the new capacity. But even if … Read more
You can accomplish this as follows: # create a minimal example data.frame and # vector of values to match df <- data.frame(x = seq(0.1, 1, 0.1)) set.seed(1) v <- df$x + rnorm(10, mean = 0, sd = 0.1) # create a vector z that stores values from v that # are closest to values in … Read more
Annotate your class a little more, and that should make clear what is happening. #include <vector> #include <cstdio> using std::printf; using std::vector; class cVtst { static int seqCounter; int seq; int v; public: cVtst(int v) { this->v = v; this->seq = ++seqCounter; printf(“Creating cVtst#%d %d\n”, seq, v); } ~cVtst() { printf(“Closing cVtst#%d %d\n”, seq, v); … Read more
For the 2nd loop, I believe it should be for(j=0;j<t.size();j++) Also, i=s[x] Should probably check that x is with the bounds of indexes for s. 3 solved Segmentation fault while using vector in C++?
You are trying to call a function that takes a reference with a temporary. A temporary can only bind to a reference to const. Also, it would be wise to show, where the error actually originated. solved C++ Templates Error: no matching function for call
If you mean to replace 1000 elements in the x vector with values between 500 and 700, you first need to generate these 1000 elements: r <- runif(1000, min=500, max=700) I am assuming here that random values are uniformly between 500 and 700. Then you need to select places to put these values in: idx … Read more
this code will help you, loop the vector and apply abs (function to find absolute value ) for(unsigned int i = 0; i < numbers.size(); i++) { if(numbers[i] < 0)numbers[i] *= -1; //make positive. _OR_ use numbers[i] = abs(numbers[i]); std::cout<<numbers[i]<<std::endl; } 2 solved How do I compute absolute value of vector? [closed]
There’s an algorithm for that: std::is_sorted: if (std::is_sorted(v.begin(), v.end()) { return v.back(); // the largest element would be the last one } else { // ?? } 13 solved How can I check if vector elements are in order consecutively?
The “environment” parameter, traditionally named envp, is a zero-terminated array of char*. You can display it like this: int main(int argc, char* argv[], char* envp[]) { while (*envp) { std::cout << *envp << std::endl; envp++; } } It’s not part of POSIX (or any other standard) but supported by many compilers. solved What is an … Read more
I don’t know where you got data from, but you need to change it to array<int, 3> or make compareByValue a template: bool compareByValue(const array<int, 3> &a, const array<int, 3>&b) { return a[0] < b[0]; } 2 solved Sorting vector of arrays by array’s element
A vector is a templated class that can store anything that you ask it to store when you defined it. For example: vector<int> // vector that will store any number of integers vector<double> // vector of double precision floating points vector<string> // vector of strings vector<T> // vector of Ts, being understood that T is … Read more
I like findInterval for these sorts of tasks: x <- c(1,2,3,20,21,22,40,41,42,60,61,62,80,81,82) table(findInterval(x,c(0,20,40,60,80))) 1 2 3 4 5 3 3 3 3 3 4 solved Counting Values in R Vector