I can’t tell you what to do to make it “work”, since your desired result is pretty unclear, but a number of problems in your code jumped out at me as I skimmed it top to bottom. Some will still run but give results you aren’t expecting, but at least one problem will cause an … Read more
The reason you’re getting different results is because the calculator is giving you the sin of 27.5 degrees, whereas Google is giving you the sin of 27.5 radians (which is equivalent to 1576 degrees). To get the same result you’ll either have to change the calculator from DEG mode to RAD mode, or convince google … Read more
found the answer myself.. note that there is a difference between sinx and sin(x) function [sinx, error] = sinx_approx(x) % approximates the value of sin(x), the approximation is more accurate as % the number of terms selected is increased. n= input(‘Up to how many terms would you like to evaluate?’); sinx=0; for i=1:1:n sinx=(-1)^(i+1) * … Read more
If you are using LWJGL you can also use JOML, in which case the following is probably what you might want: import org.joml.*; public class CubePositions { public static void main(String[] args) { /* Cuboid center position */ float px = 10, py = 0, pz = 0; /* Euler angles around x, y and … Read more
Don’t define your own (broken) sin function – use the one that’s already in the math library: printf(“The sine of 1 radian is %.3f.\n”, sin(1.0)); 7 solved Using the math library to display the sine of 1 radian rounded to three decimal points in C [closed]