[ad_1] You can use scheduling in Spring to update it on regular interval (with cron jobs for example). Look at @Scheduled(cron = ”). Also for your token, is there an special reason to keep it in file. Why not use a bean to store it and pass it around with @Autowired? 0 [ad_2] solved Is … Read more
[ad_1] I am getting an error: “Unexpected token <” in a javascript file that i used as part of an online banking project.I have attached the file below [closed] [ad_2] solved I am getting an error: “Unexpected token
[ad_1] The complete lexical specification for ECMAScript (aka JavaScript) can be found in Section 11 (Lexical Grammar) of ECMA 262. (New versions of ECMA-262 are released roughly annually, but the URL in that link — correct as of ECMAScript 2020 — should continue to work, or be easy to fix. I didn’t transcribe the list … Read more
[ad_1] else block is the problem. Else block should be inside of curly braces if there is more than one line. 6 [ad_2] solved Uncaught SyntaxError: Unexpected token in JS
[ad_1] To retrieve the data from the file.txt: data = {} with open(‘file.txt’, ‘r’) as f: # opens the file for line in f: # reads line by line key, value = line.split(‘ : ‘) # retrieves the key and the value data[key.lower()] = value.rstrip() # key to lower case and removes end-of-line ‘\n’ Then, … Read more
[ad_1] The error is essentially “Cannot convert from SymmetricSecurityKey(string) to IEnumerable<SymmetricSecurityKey>”. This means that the IssuerSigningKeys is expecting an IEnumerable (List or Array) of SymmetricSecurityKey instead of a single value. The fix is easy, give it an array: services.AddAuthentication(JwtBearerDefaults.AuthenticationScheme).AddJwtBearer(options => { options.TokenValidationParameters = new TokenValidationParameters { ValidateIssuerSigningKey = true, IssuerSigningKeys = new[] { new SymmetricSecurityKey(key) … Read more
[ad_1] When you call JSONObject.get(“2”),you get a JSONObject again,it have a pair which key is 3 and value is numbertoken,so you just need try to get the numbertoken again:JSONObject.get(“2”).get(“3”) 1 [ad_2] solved read each part of a token response in android
[ad_1] If I understand correctly your Scanner is breaking on spaces. You want it to break on new lines: Scanner scanner = new Scanner(System.in); scanner.useDelimiter(System.getProperty(“line.separator”)); // this scans for lines while (scanner.hasNext()) { String input = scanner.next(); System.out.println(input); // take a look for yourself } 4 [ad_2] solved I have an issue using tokens, scanning … Read more
[ad_1] Assuming you’re trying to decrement…count by 1…you need one more minus sign, like this int i = 10; i–; to be a valid expression in C/C++. 1 [ad_2] solved Getting error in the c Program regarding expected ; before token [closed]
[ad_1] If you have know just English knowledge, then you can eazly delete this } in shown your error message side You can’t add break in if condition, you need to return instead of break and remove {} in if conditions } Error message appears here : Syntax error on token “}”, delete this token … Read more
[ad_1] I would suggest you to check out all links properly which you put in action attribute of the form, or may be some other links. I don’t think there is any cookies related issue is there, unless you used it additionally. 0 [ad_2] solved UPDATE please look again – CSRF token mismatch server (local … Read more
[ad_1] #include <stdio.h> #include <string.h> int main(void) { char *order[] = {“Day”, “Month”, “Date”, “Year”, “Hour”, “Minute”, “Second”}; char text[] = “Saturday, July 8, 2017, 22:14:10″; char* delims = ” ,:”; char* token = strtok(text, delims); char** label = order; while(token) { printf(“%-8s: %s\n”, *label, token); token = strtok(NULL, delims); label++; } return 0; } … Read more