Try stringOne .filter(function(el) { return el !== “”; }) .join(” – “); The filter gets rid of all elements that are empty, join should be straightforward. 1 solved Logically concatenating strings separated by hyphens
x = (x > 250000 && x < 500000) ? (x / 100) * 10 : ((x > 500000 && x < 1000000) ? (x / 100) * 20 : ((x > 1000000) ? (x / 100) * 30 : x)); Ternary operator of the form (conditional) ? expr1 : expr2 should be read as … Read more
Ternary operator expressions are not statements: you can’t use them on their own as a replacement for an if. You should write if (unprocessed_information.contains(“type:”)) { ( unprocessed_information.replace(“type:”,””).equals(“teacher”) ) ? (admin_accounts.add(username)) : (null); } as: if (unprocessed_information.contains(“type:”)) { if (unprocessed_information.replace(“type:”,””).equals(“teacher”)) admin_accounts.add(username); } or (better, since there is nothing in the first if but the second if): … Read more
It’s not the ternary that’s the issue, it appears to be how jQuery/HTML is handling the empty string. jQuery is most likely not resolving the property to an explicit false and thus creating an element with a “selected=”” which the browser may just be interpreting as “selected” which I believe is from an old HTML … Read more
You can rewrite what you just wrote like this: a > 5 ? ( a > 10 ? 10 : 5 ) : 0 After all, there is no other way you could arrange the parentheses that would make sense. Therefore, the a > 5 comparison must be tested first because if a > 5 … Read more
Take a look here: class Question05 { public static void main(String[] args) { double gpa = Double.parseDouble(args[0]); String res = gpa >= 3.6?”First class Hons”:(gpa<3.6 && gpa>=3.4?”Upper Second Class Hons”: (gpa<3.4 && gpa>=3.0?”Lower Second Class Hons”: (gpa<3.0 && gpa>=2.0?”Pass”:”you have failed”))); System.out.println(res); } } Edit: @veena, you were trying to assign a string to gpa, … Read more
Because x is 0. Recall that the ternary operator, if written condition ? a : b returns a if condition is true and b otherwise. You are using it with numbers, and any number except 0 is considered true as a boolean. x ? b : c in your case is 0 ? 2 : … Read more
That is because the ternary operator always evaluates to a single type. You can’t “return” different types with this operator. When the compiler encounters such an expression he tries to figure out whether he can reduce the whole thing to one type. If that’s not possible you get a compile error. In your case there … Read more
Why does any combination of true and false return the value it does? There is no combination of any boolean here. This ?: operator returns first or second expression, not the condition itself. condition ? first_expression : second_expression; The condition must evaluate to true or false. If condition is true, first_expression is evaluated and becomes … Read more