A neat way to do it is String s = “[1,2,3]” s=s.sbustring(1,s.length-1); List<Long> numLongs = new ArrayList<Long>(); for(String eachString: s.split(“,”)){ try { numLongs.add(Long.parseLong(eachString)) } catch (NumberFormatException e){ System.out.println(“failed to convert : “+s); } } 0 solved Converting a string into an List [closed]
Here’s a working code: #include <stdio.h> int main () { char x[100] = {0}; char m; int i, j; printf (“Type:\n”); for (i=0; i<99; i++) { m = getchar(); getchar(); if ((m != ‘ ‘) && (m != ‘\n’)) { x[i] = m; } else { printf (“Breaking.”); break; } } printf (“\n”); for (j=0; … Read more
There’s a constructor for std::stringstream that takes a std::string as a parameter and initializes the stream with that value. #include <iostream> #include <sstream> #include <string> int main() { std::stringstream ss(“foo bar”); std::string str1, str2; ss >> str1 >> str2; std::cout << “str1: ” << str1 << std::endl; std::cout << “str2: ” << str2 << std::endl; … Read more
It’s because you’re splitting by a single character, you would have to do this eagerly: String[] Operators = stringNumbers.split(“[0-9.]*”); Or you can filter the results: String[] Operators = Arrays.stream(stringNumbers.split(“[0-9.]”)) .filter(str -> !str.equals(“”)) .toArray(String[]::new); 5 solved Why there are empty string while trying to split a string in Java? And how to fix it?
I believe you could set a local notifications that will fire each 24 hour then display any quote. So a day contains 86400 seconds, we could use a timer that will count down from 86400 seconds to zero, when it hits zero we reset the timer and remind them a quote @IBOutlet weak var label:UILabel! … Read more
You could use the below regex to extract all ipaddresses, phone number, dates. (?<ipaddress>\d{1,3}(?:\.\d{1,3}){3})|(?<Phonenumber>\d{10})|(?<Date>\d{1,2}\/\d{1,2}\/\d{4}) DEMO 2 solved Return Mobile Number, IP Address and Date Format in PHP String using regular expression [closed]
So you are getting access voilation…. The problem is that your buffers are probably overflowing and you have no length check in your code… The buffers you have allocated are only 25 bytes long char str1[25], str2[25]; so to intruduce a length check, add an extra parameter to concat which tells how long the output … Read more
You can do this using type or insinstance of python builtin module, like, if type(user_input) is int: # your code type returns the type of the obect. Or using insinstance, if isinstance(user_input, int): # your code isinstance return True if the object is instance of a class or it’s subclass. Now, in your code you … Read more
You can do it using a Set. You need unique elements and Set gurantees you containing the unique elements. HashSet is implementation of Set, you can use it to implement this idea. public boolean ifAllCharsUnique(String input){ char[] arr = input.toCharArray(); int length = arr.length; Set<Character> checker = new HashSet<>(); for(int i =0 ; i < … Read more
The whole point of a type in a language like C is that it describes some well-defined, useful set of values. A value of type unsigned int can hold any integer in a range defined by your compiler and processor. This is typically a 32-bit integer, meaning that an unsigned int can hold any integer … Read more
I see 3 ways (I’m not sure about which one has the best perfs, but I will bet on the last procedural way): Using the json_decode function, you will get an array from your string and then just iterate over it to get your data Using regexp, see an example here with pattern /subdomain:(.*?),.*?comment:(.*?),/ Using … Read more
You can use standard C function memmove. For example #include <stdio.h> #include <string.h> int main( void ) { char temp[] = “\nHello”; if (temp[0] == ‘\n’) { memmove(temp, temp + 1, strlen(temp)); } puts(temp); } 1 solved How to get rid of ‘\n’ at the beginning of string
You need to use the substr() function echo substr($msg, 0, 10); 0 solved Show first 10 letters from a string variable [duplicate]
You can use ast.literal_eval to safely evaluate strings containing Python literals. from ast import literal_eval a=”[“Hello”, “World!”, 2]” b = literal_eval(a) # [“Hello”, “World!”, 2] Note that the string can only be compromised of: strings, bytes, numbers, tuples, lists, dicts, sets, booleans, and None (taken from the documentation here) solved how to convert string consisted … Read more
Using implode and array_map $input = [13 => 500, 16 => 1000]; $output = implode(‘, ‘, array_map( function ($v, $k) { return $k . ” ” . $v; }, $input, array_keys($input)) ); var_dump($output); Using foreach $input = [13 => 500, 16 => 1000]; $output = “”; foreach ($input as $k => $v) { $output .= … Read more