[ad_1] You have an error in your SQL syntax; check the manual that corresponds to your MariaDB server version for the right syntax to use near ‘0 [ad_2] solved You have an error in your SQL syntax; check the manual that corresponds to your MariaDB server version for the right syntax to use near ‘0
[ad_1] select to_char(systimestamp,’YYYY-MM-DD”T”HH24:MI:SS.FF2TZHTZM’) from dual; 2018-02-07T11:43:37.47+0800 [ad_2] solved How to print system date in this format “2017-04-04T05:30:27.27-0700”
[ad_1] there are many ways of skinning this particular cat, this is just one method. By the way in your example you gave a date of 31st April, this does not exists. SELECT TO_Char(ordered_date,’DD-MON-YYYY’) as ordered_date, order_number, customer_name FROM order_tbl WHERE NVL(:P_ORDER_NUMBER, order_number) = order_number AND ordered_date between NVL(TO_DATE(:P_FROM_DATE,’DD-MON-YYYY’),TO_DATE(’01-MAR-1900′,’DD-MON-YYYY’)) and NVL(to_date(:P_TO_DATE,’DD-MON-YYYY’),TO_DATE(’31-DEC-2100′,’DD-MON-YYYY’)) AND NVL(:P_CUSTOMER_NAME, customer_name) = … Read more
[ad_1] I think I’ve figured out what you are trying to do now. For example, you are expecting the query to match R2.1.2 which lies between R1.1.2 and R106.2.3 according to your id scheme. First of all, your SQL is syntactically invalid. Assuming that these ids are represented by a VARCHAR or similar, you need … Read more
[ad_1] You can use SELECT Split.r.value(‘.’, ‘VARCHAR(100)’) AS Data FROM ( SELECT CAST (‘<M>’ + REPLACE(roolno, ‘,’, ‘</M><M>’) + ‘</M>’ AS XML) AS Data FROM table1 ) AS r CROSS APPLY Data.nodes (‘/M’) AS Split(r); or if you want to put where clause you can put it like this SELECT Split.r.value(‘.’, ‘VARCHAR(100)’) AS Data FROM … Read more
[ad_1] Oh my god, thanks @Orel Eraki, of course beside the unbalanced single-quotes you will have to follow proper SQL Insert Syntax and hava a form of ‘INSERT INTO …’, try it like this (see my change dirctly after “values(” as the one of Orel Eraki (no ‘table’ “keyword” after into): Sql_insert=”insert into itemmanag(itemID,purchesPrice,sellPrice,quantity,vendor,unitM )values(‘”+txt_itemID.getText()+”‘,'”+Item_Pprice.getText()+”‘,'”+txt_itemSprice.getText()+”‘,'”+txt_qunti.getText()+”‘,'” … Read more
[ad_1] You can use least(): least(sum(case when type=”A” then cost else -cost end) * 0.08, 300) as AMY If the sum() exceeds 300, then the return value is 300. You can use greatest() if you want to impose a minimum. So, this would ensure that the value is between -300 and 300: greatest(least(sum(case when type=”A” … Read more
[ad_1] Try this: DECLARE @SUM VARCHAR(50)=’33.90′; SELECT CAST(CAST(LEFT(@SUM,CHARINDEX(‘.’,@SUM,0)-1) AS INT)+ CAST(SUBSTRING(@SUM,CHARINDEX(‘.’,@SUM,0)+1,LEN(@SUM)) AS INT)/60 AS VARCHAR(10))+’.’+ CAST(CAST(SUBSTRING(@SUM,CHARINDEX(‘.’,@SUM,0)+1,LEN(@SUM)) AS INT)%60 AS VARCHAR(10)) result: 34.30 1 [ad_2] solved How to convert the Varchar of sum to time using sql server 2008 [closed]
[ad_1] Same as any other… Based on PEMDAS Parenthesis Exponents Multiply and Divide at same level, left to right Add and Subtract at same level left to right. (D-E) is done first (B) is done next, but is left as-is as no other direct relation A * B C * 100 then (result of C … Read more
[ad_1] You seem to want aggregation: select disport, actualagent, . . . , country, sum(pallats), sum(gross) from t group by disport, actualagent, . . ., country; You need to list all the columns where the . . . is. 1 [ad_2] solved Select distinct record from table and perform Sum of column (Pallats, Gross) of … Read more
[ad_1] You can try following code: import pandas as pd df1 = pd.read_csv(“Insert file path”) df2 = pd.read_csv(“Insert file path”) df1[‘Date’] = pd.to_datetime(df1[‘Date’] ,errors=”coerce”,format=”%Y-%m-%d”) df2[‘Date’] = pd.to_datetime(df2[‘Date’] ,errors=”coerce”,format=”%Y-%m-%d”) df = df1.merge(df2,how=’inner’, on =’Date’) df.to_csv(‘data.csv’,index=False) This should solve your problem. 4 [ad_2] solved how to save sql query result to csv in pandas
[ad_1] You can do this directly in SQL. Use distinct to get only records that are no duplicates SELECT DISTINCT a.NAME FROM your_table a WHERE a.NAME = ‘JOHN SMITH’ or use top to get only a certain amount or records as result SELECT top 1 a.NAME FROM your_table a WHERE a.NAME = ‘JOHN SMITH’ 1 … Read more
[ad_1] go to on this URL and read it http://blog.sqlauthority.com/2009/04/13/sql-server-introduction-to-joins-basic-of-joins/ I think it is very helpful to understanding join in SQL… [ad_2] solved how to join two table in sql [closed]
[ad_1] You can use apply: select a.*, b.* from a cross apply (select top (1) b.* from b where b.code = a.code and b.time < getdate() order by b.time desc ) b; This assumes that time is really a datetime. If you just want to compare times, then use convert(time, getdate()). 2 [ad_2] solved Left … Read more
[ad_1] SELECT ID,SUM(CASE WHEN Level=1 AND Grade IN (‘A’,’B’,’C’,’D’) THEN 1 WHEN Level=2 AND Grade IN (‘A’,’B’,’C’) THEN 1 ELSE 0 END AS GradeCount FROM YourTable GROUP BY ID; 0 [ad_2] solved Select criteria using a case expression in where clause based on other columns [closed]