Theoretically you can do this. Writing subquery in join statement will have no effect other than filtering the cartesian product of the two tables just like the where condition. But writing query this way makes no sense as we don’t know the context in which you are using it. The above query can be written … Read more
Try this should help: $datedb = “2018-03-01 11:54:33”; $date = date(‘d-m-Y’, strtotime($datedb)); echo $date; // will print 01-03-2018 And read about date() function of php: http://php.net/manual/en/function.date.php; https://www.w3schools.com/php/func_date_date.asp 0 solved SQL Timestamp format in PHP [duplicate]
I didn’t test it, but it should look something like that : var query = (from s in Suppliers select new { SupplierId = s.SupplierId, CompanyName = s.CompanyName, ContactPerson = s.ContactPerson, Address = s.Address, Email = s.Email, InActive = s.InActive, BranchId = s.BranchId, CreateDate = s.CreateDate, CreatedBy = s.CreatedBy, UpdateDate = s.UpdateDate, UpdateBy = s.UpdatedBy, … Read more
Use parametrized queries. For example the query would look like this: INSERT INTO anggota (no, nis, nama, kelas, jenis_kelamin, tempat_lahir, tanggal_lahir) VALUES (@no, @nis, @nama, @kelas, @jenis_kelamin, @tempat_lahir, @tanggal_lahir) Then adjust your code: cmd.Parameters.AddWithValue(“@No”, Tno.Text) cmd.Parameters.AddWithValue(“@nis”, Tnis.Text) cmd.Parameters.AddWithValue(“@Nama”, Tnama.Text) cmd.Parameters.AddWithValue(“@Kelas”, Tkelas.Text) cmd.Parameters.AddWithValue(“@Jenis_kelamin”, CBjk.Text) cmd.Parameters.AddWithValue(“@Tempat_lahir”, Tt4lahir.Text) cmd.Parameters.AddWithValue(“@Tanggal_lahir”, ttgllahir.Text) cmd = New OleDbCommand(sqltambah, conn) cmd.ExecuteNonQuery() 2 solved … Read more
Short answer is db.create_all(). Here is a piece of this answer app = Flask(__name__) app.config[‘SQLALCHEMY_DATABASE_URI’] = ‘postgresql+psycopg2://login:pass@localhost/flask_app’ db = SQLAlchemy(app) db.create_all() db.session.commit() solved sqlalchemy create tables [closed]
Try this UPDATE TPatientRaw SET tPatSSlidaID = RIGHT(‘0000000000’ + CAST(CAST(tPatSSlida AS int) + 10000 AS VARCHAR), 10) WHERE tPatSName=”CLINIC DENT” simple test 4 solved SQL Change Value + 10000
You should ALWAYS use parametrized queries – this prevents SQL injection attacks, is better for performance, and avoids unnecessary conversions of data to strings just to insert it into the database. Try somethnig like this: // define your INSERT query as string *WITH PARAMETERS* string insertStmt = “INSERT into survey_Request1(sur_no, sur_custname, sur_address, sur_emp, sur_date, sur_time, … Read more
SELECT * FROM students very simply but is a query to select all rows from a table called ‘students’ solved How to write SQL statements in php? [closed]
declare @t1 table ( col_a varchar(5) null ,col_b varchar(5) null ,col_c varchar(5) null ,col_d varchar(5) null ) declare @t2 table ( col_a varchar(5) null ,col_b varchar(5) null ,col_e varchar(5) null ) insert into @t1 values (‘Cat 1′,’Bla a’,’C-1′,’D-1′) ,(‘Cat 1′,’Bla a’,’C-2′,’D-2′) ,(‘Cat 1′,’Bla a’,’C-3′,’D-3′) ,(‘Cat 2′,’Bla b’,’C-4′,’D-4′) ,(‘Cat 2′,’Bla b’,’C-5′,’D-5′) insert into @t2 values (‘Cat … Read more
Assuming that there aren’t any partitioned table: USE [SpecificDatabank] SELECT sys.columns.name AS ColumnName, sys.tables.name AS TableName, sys.partitions.rows AS [Rows] FROM sys.columns JOIN sys.tables ON sys.columns.object_id = sys.tables.object_id JOIN sys.partitions ON sys.tables.object_id = sys.partitions.object_id and sys.partitions.index_id in (0,1) WHERE sys.columns.name LIKE ‘%ColumnName%’ 1 solved Find number of rows of each column name [duplicate]
This is your query: SELECT FirstName, LastName, ( SELECT COUNT(O.Id) FROM [Order] O INNER JOIN C On O.CustomerId = C.Id ) AS OrderCount FROM Customer C; It is invalid, because in the sub query you are selecting from C. This is a bit complicated to explain. In a query, we deal with tables and table … Read more
select user.name, user.country, data.best_time from user, data where user.user_name = data.user_name; solved Select from multiple tables using 1 column [closed]
A Student with just one Professor: A third table is not necessary, just add that foreign key (idp = Professor ID) in the Student Table so that you can do: SELECT * FROM Student JOIN Professor ON Student.idp = Professor.idp WHERE Professor.Name=”Jon” and this way you will get all the students who have Jon as … Read more
No. The block as a whole will get rolled back on failure, but the raise statement on its own does not perform a rollback. For example, this block fails and is implicitly rolled back (exactly as if it was an SQL insert etc): begin insert into demo(id) values(1); dbms_output.put_line(sql%rowcount || ‘ row inserted’); raise program_error; … Read more
This will do it on SQL Server. It’s really weird, but stackoverflow wouldn’t let me post that query, so I had to post a screen grab. 2 solved Sum of different attributes for a user [closed]