[ad_1] There are many problems in your code. Of course the compiler stops you at compile time, but then you will get other errors at runtime So fixing the compile time problem is easy. Just write a retrun value if you don’t have any rows returned by your query: // This returns true if you … Read more
[ad_1] GROUP BY and HAVING Class 101 SELECT student_id, SUM(CAST(pass AS INT)) * 100 / COUNT(course_id) as pass_rate FROM MyTable GROUP BY student_id HAVING(sum(cast(pass as int)) * 100 / count(course_id)) > 95 [ad_2] solved SQL query a percentage [closed]
[ad_1] Use ajax $.ajax({ url: “fetchlist.php”, dataType: ‘json’, success: function(response){ // Here, you may bind response with your select HTML } }); You may either return json from your php file and create DOM elements in response. Or, you may create HTML version and return as response. Suggestion will be to use JSON for better … Read more
[ad_1] Use UNION like: SELECT id,name,add1 from mytable UNION SELECT id,name,add2 from mytable EDIT: for better performance you can use UNION ALL instead, that will give you the same result: SELECT id,name,add1 from mytable UNION ALL SELECT id,name,add2 from mytable 4 [ad_2] solved 1 x chen hyd 2 y bang mum [closed]
[ad_1] Try: select Agent, max(case when `desc` = ‘Total’ then ColValue else 0 end) Total, max(case when `desc` = ‘Replaced’ then ColValue else 0 end) Replaced from tbl group by Agent Demo sqlfiddle 1 [ad_2] solved T-SQL | SQL-Server Pivot [closed]
[ad_1] SELECT SUM(Value) FROM TableName; Using a GROUP BY (per your comment above) is when you want things grouped over a subset. In this case, a group by would return the same info you’ve sampled, because there’s no groups to sum on the desc field… however if you had two “e” descriptions (let’s say 40 … Read more
[ad_1] Few ideas below Remove as many left joins as possible. Use inner joins where-ever possible. Remove sub-query to get ISerialNumber. Get this later in wrapper query. Create indexes on columns in the WHERE clause if not already existing. Do not use this way of date comparison. Imagine this conversion for every row in your … Read more
[ad_1] Assuming your are using date and MSSQL2012+: SELECT UPPER( FORMAT(CONVERT(datetime, ‘2017-02-01′,121),’MMM’)) + ‘-‘ +RIGHT(CAST( YEAR( CONVERT(datetime, ‘2017-02-01’,121)) AS VARCHAR(4)),2) M_DELIVERY , ‘DELIVERY FOR ‘ +UPPER( FORMAT(CONVERT(datetime, ‘2017-02-01′,121),’MMM’))+’ ‘+ CAST( YEAR( CONVERT(datetime, ‘2017-02-01’,121)) AS VARCHAR(4)) AS Description Other way(using numbers and not date): (you can change months name abbrev.) SELECT SUBSTRING(‘GENFEBMARAPRMAYJUNJULAUGSEPOCTNOVDEC’,1+(MONTH_NUMB-1)*3,3)+’-‘+ RIGHT(YEAR_NUMB,2) AS M_DELIVERY , … Read more
[ad_1] You do not need any of these IF..ELSE statements or even the sub-queries in your select, what you are after, can be achieved with the following simple select query: CREATE PROC GET_ORDER_ACCOUNT_DETAILS @ORDERID INT AS BEGIN SET NOCOUNT ON; SELECT CASE WHEN od.calcType=”K” THEN od.price * od.kilo ELSE od.quant * od.price END as [AMOUNT] … Read more
[ad_1] First, I do not really know which is the default OUTER JOIN in T-SQL (I’d bet FULL), but in any case, I think it is unclear – it is best to use LEFT, RIGHT, OR FULL JOIN explicitly when you need one. JOIN joins tables. Already existent ones or subqueries. APPLY applies (duh) a … Read more
[ad_1] Replace the prefixes you want to remove, then find the index of the first and second underscores and then find the substring between those two separators: Oracle Setup: CREATE TABLE your_table ( value ) AS SELECT ‘DUM_EI_AO_L_5864_Al Meena Tower’ FROM DUAL UNION ALL SELECT ‘EI_AE_L_5864_Al radha Tower’ FROM DUAL Query: SELECT value, SUBSTR( replaced_value, … Read more
[ad_1] Join sailors with reserves, filter out rows before 2011-02-04, group by sailor and take only those results having a count over two. Translate this to SQL, and you are done. [ad_2] solved Can you provide a query for this question? [closed]
[ad_1] Write an SQL query to find all those hostnames that have encountered multiple logs //“init failure” on any given day at 5 min interval [ad_2] solved Write an SQL query to find all those hostnames that have encountered multiple logs //“init failure” on any given day at 5 min interval
[ad_1] Try this: {{ round(($unload->sum(“first”) * 100) / $unload->sum(“total_unload”)) }} % 0 [ad_2] solved How can I get round value from a object in laravel [closed]
[ad_1] select a.name as name,b.name as represon from table1 a inner join table1 b on a.code=b.rperson 0 [ad_2] solved How can I quickly solve this query? [closed]