Considering you’re only selecting the address, those selects are equivalent. It returns two addresses because there are two “Johns”. Joining on address would allow you to figure you who else lives with John. For example: SELECT c2.first_name FROM users c1, users c2 WHERE c1.address = c2.address AND c1.first_name=”John” AND c2.first_name != ‘John’ would tell you … Read more
A simple GROUP BY should work for you: SELECT Col1,Col2 FROM YourTable T GROUP BY Col1,Col2 HAVING COUNT(*) > 1 Please post what you have tried going forward… –EDIT– If you’re look at returning all rows that have the same lat/lon, then something like this would work: SELECT * FROM YourTable WHERE (lat,lon) IN ( … Read more
Most, but not all (I think Oracle is one which doesn’t) database systems implemented the INFORMATION_SCHEMA which you can query to get information about database objects. In order to get the ordinal position of a column in a table, you can use: SELECT C.ORDINAL_POSITION FROM INFORMATION_SCHEMA.COLUMNS AS C WHERE C.TABLE_NAME = ‘Table’ AND C.COLUMN_NAME = … Read more
Introduction Tuple variables are a type of variable used in SQL statements. They are used to store multiple values in a single variable. They are similar to arrays, but they are more efficient and can be used to store different types of data. They are also used to store multiple values in a single column … Read more
–Set up table and data DECLARE @ATable TABLE ([date] DATETIME, [Count] INT) INSERT @ATable( date, Count ) SELECT ‘2015-05-14 01:00:00’, 1 UNION ALL SELECT ‘2015-05-15 02:00:00’, 2 UNION ALL SELECT ‘2015-05-15 20:00:00’, 3 UNION ALL SELECT ‘2015-05-16 03:00:00’, 4 — Query SELECT d.[date], ( — This subquery returns the sum of counts for the 36 … Read more
Introduction SQL statement thinking is a process of understanding how to use SQL to solve a problem. It involves understanding the structure of the data, the relationships between the data, and the logic of the query. It is important to think through the SQL statement before writing it, as it can save time and effort … Read more
Introduction This article will discuss how to use SQL to group data by 36 hours. We will look at how to use the GROUP BY clause to group data by 36 hours, as well as how to use the DATEADD function to add 36 hours to a date. We will also discuss how to use … Read more
You must use echo for print value like: echo “<td><a href=””.$row[“url’].”‘>”.$row[‘url’].”</a></td>”; or <td><a href=”https://stackoverflow.com/questions/60163422/<?php echo $row[“url’]; ?>’><?php echo $row[‘url’]; ?></a></td> 2 solved echo value from DB as a Link in PHP/HTML table [closed]
You can convert it to String and then validate it with matches(). 2 solved Validating sql date type in java [closed]
Your first clause in your WHERE is only going to match rows where died is not null. given that, you can reorder the clauses something like: WHERE first_name NOT IN (‘Hannah’, ‘Julia’, ‘Frasier’) AND last_name NOT LIKE ‘%o%’ AND (nationality <> ‘German’ OR speciality <> ‘Photo’) AND ((died – born BETWEEN 50 AND 80 AND … Read more
YOU WANT TO DO IT LIKE THIS BECAUSE THIS WILL WORK TO SOLVE YOUR PROBLEM. SELECT ‘NetworkKey’ AS AuthKey, COUNT(*) AS TotalCount, SUM(CASE WHEN NetworkSK IS NULL THEN 1 ELSE 0 END) AS NUllcount, SUM(CASE WHEN NetworkSK IS NOT NULL THEN 1 ELSE 0 END) AS NotNullcount FROM EDW.Fact.AuthorizationRequest Happy holidays. 5 solved SQL Query … Read more
I did that using the following query. UPDATE SchemeMember SET personID = b.personUID FROM SchemeMember s,benefit b WHERE s.Id = b.SchemeMemberId solved Update newly added column with value on another table
In your query only USER_ID column in the where condition is not specified with a table name. I guess USER_ID is there in multiple table. Try the where condition with proper table name SELECT INDIVIDUAL.INV_FNAME, INDIVIDUAL.INV_LNAME, INDIVIDUAL.INV_IC_NUM, CUSTOMER.MEMBER_LEVEL, CUSTOMER.MEMBER_POINT_BALANCE, CUSTOMER.MEMBER_DISCOUNT_RATE, PROGRAM_USER.USER_CONTACT_NUM, PROGRAM_USER.USER_ADDRESS, PROGRAM_USER.USER_CITY, PROGRAM_USER.USER_STATE, PROGRAM_USER.USER_ZIP_CODE, PROGRAM_USER.USER_COUNTRY, PROGRAM_USER.USER_EMAIL FROM PROGRAM_USER,CUSTOMER,INDIVIDUAL WHERE PROGRAM_USER.USER_ID = ‘san’; Also like … Read more
You need of jar that have the class com.microsoft.sqlserver.jdbc.SQLServerDriver. This class is part of library JDBC to connect with SQLServer. You can do download in this web site: https://www.microsoft.com/pt-BR/download/details.aspx?id=11774 If your project use maven, you can add this dependency: https://mvnrepository.com/artifact/org.springframework/spring-jdbc/5.0.0.M5 0 solved How to output the queries from my sql database? [duplicate]
This really depends on what is being requested in the query and the size of each table. A select all SELECT * FROM Table will consume whatever memory required to load records in that table. 2 solved Which is the most memory intensive SQL query: select, update or insert? [closed]