regex

[Solved] Text Edit Change Variable Names [closed]

by

You may catch a few false matches, but this is the jist of it. It backs up the original files by adding a .bak extension, but make sure you have your own backup before overwriting valuable code. I assume these are JavaScript files? perl -i.bak -pe’s/\bm_(\w)/m\u$1/g’ *.js solved Text Edit Change Variable Names [closed]

[Solved] extract information from xml using regular expression

by

Why couldn’t regex: <post\\s*author=\”([^\”]+)\”[^>]+>[^</post>]*</post> extract the author in following text. Because [^</post>]* represents a character class and will match everything but the characters <, /, p, o, s, t, and > 0 or more times. That doesn’t happen in your text. As for how to fix it, consider using the following regex <post\s*author=\”([^\”]+?)\”[^>]+>(.|\s)*?<\/post> // obviously, … Read more

[Solved] How will it be fixed so that it can catch mentioned URL formats? [closed]

by

What I can notice, you expect the pattern to catch the website with or without http/https – this is not included in your expression. What is more, I am not sure what the purpose of \(* is – ((((((https://some.url.com will also be caught. Is https://½½½½½½½½½½½½ a valid url? It will be accepted. What about http://= … Read more

[Solved] string matching using regular expressions in java

by

I think this one should do the trick: ^(?!000|666|9\d{2})\d{3}-\d{2}-\d{4}$ Edit: I find the negative look-ahead syntax in this thread. Edit 2: Here is a little code snippet for those who want to test it: import java.util.Scanner; import java.util.regex.Matcher; import java.util.regex.Pattern; public class Main { public static void main(String[] args) { Pattern pattern = Pattern.compile(“^(?!000|666|9\\d{2})\\d{3}-\\d{2}-\\d{4}$”); Scanner … Read more

[Solved] PHP regex for validating password [closed]

by

Have a look at the preg_match() PHP function in the manual. Quick Example: <?php // Check if the string is at least 8 chars long if (strlen($password) < 8) { // Password is too short } // Make the password “case insensitive” $password = strtolower($password); // Create the validation regex $regex = ‘/^[a-z][\w!@#$%]+\d$/i’; // Validate … Read more

[Solved] Search for a given row in a table [closed]

by

Um, it’s kinda hard to see what you’re asking, but I think what you want is new RegExp(‘1.*’+str,’i’); The period (.) matches any character and the * matches any character zero or more times. I’m not 100% on the syntax of that regex in javascript, but that should be a minor issue. Maybe a str.toString() … Read more

[Solved] How to check specific phrases in text are present with regex

by

I found a solution that works, after trying alot of different things (\bquick brown\b).*(\bover the\b) It has a match on “The quick brown fox jumps over the lazy dog, bla bla, something something” But not “The quick brown fox jumps over something the lazy dog, bla bla, something something” And not “The quick brownest fox … Read more

[Solved] Want to extract a value from String using patterns in java [closed]

by

Regex may complicate the code. If its a simple comparison you could use indexOf instead. Seeing the format of your strings it better to use properties then you have better control over the values. Eg import java.io.IOException; import java.io.StringReader; import java.util.Properties; public class StringToProp { public static void main(String[] args) { String str1 = “property: … Read more

[Solved] PHP regular expression matching date [duplicate]

by

<?php $date=”2009/10/22″; if ( preg_match(‘/^(?:(19[0-9]{2}|20[0-9]{2}))\/(0[1-9]|1[012])\/(0[1-9]|[12][0-9]|3[01])$/’, $date ) ) { echo $date , ‘ is a valid date format.’; } else { echo $date , ‘ is not a valid date format!’; } ?> Also please make sure you use checkdate() function in addition to this. 1 solved PHP regular expression matching date [duplicate]

[Solved] Regex for string that validates for a number which may include decimal and for a particular length [closed]

by

Run this code and test with all your inputs.It should solve your scenario. String regex = “^[0-9.]{5}$”; Pattern pattern = Pattern.compile(regex); String name= “123.4”; Matcher matcher = pattern.matcher(name); System.out.println(matcher.matches()); 1 solved Regex for string that validates for a number which may include decimal and for a particular length [closed]