Scott is right, and Leigh was right before, when you asked a similar question, jSoup is your best option. As to a regex solution. This is possible with regex but there are problems that regex cannot always solve. For instance, if the first or second table contains a nested table, this regex would trip. (Note … Read more
You can try this regex… www.youtube[^’]* [^’] matches any character except ‘ [^’]* matches 0 to many characters except ‘ 3 solved Get URL from text using regexp [closed]
If you have small arrays, It is not a problem to run the algorithm with complexity O(n2). But for me better is less clear, but faster algorithm with complexity equals to O(2n) $array = array( array( ‘id’ => 12, ‘_from’ => 1, ‘_to’ => 2 ), array( ‘id’ => 13, ‘_from’ => 4, ‘_to’ => … Read more
If I understand your question, here’s one way to do it: use glob to find all files in the directory and grep to filter them. my $dir=”/usr/test”; my @files = grep { /REGEX_HERE/ } glob(“$dir/*”); 2 solved How to support the searching file based on regular expression
With no regard to whether the pattern is correct or not: Instead of using: var re = new RegExp(“\+”, “gmi”); use: var re = /\+/gmi; See MDN – Creating a regular expression. If you are using the string constructor, you need to string-escape all backslashes: var re = new RegExp(“\\+”, “gmi”); As already mentioned in … Read more
Split the task into 3 parts. First, a number in the range of 1-31 (tutorial), then a list of possible values for the month, and then two numbers. \b([1-9]|[12][0-9]|3[01])-(Jan|Feb|Mar|Apr|May|Jun|Jul|Aug|Sep|Oct|Nov|Dec)-(\d{2})\b Regex101 Demo 3 solved Regex for this date format?
you can try splitting using this regex ([\d,]+|[a-zA-Z]+ *[a-zA-Z]*) //note the spacing between + and *. [0-9,]+ // will search for one or more digits and commas [a-zA-Z]+ [a-zA-Z] // will search for a word, followed by a space(if any) followed by another word(if any). String regEx = “[0-9,]+|[a-zA-Z]+ *[a-zA-Z]*”; you use them like this … Read more
Your question has very limited detail, however the very simple answer is: ^[+]{2,}$ However, that would only match the character “+” 2 or more times. Since you’re saying punctuation, it seems to imply that you want to allow other text. In that case, I would go with: ^[\w+ ]{2,}$ Which would allow all “word characters” … Read more
This will do it for you: ^[\w.]+=\$\d+(?:\|[\w.]+=\$\d+)*$ It matches at least one word character or . followed by an =, $ and a digit. Then, optionally, a | followed by the first sequence again. This optional part can be repeated any number of times. See it here at regex101. Edit Allow multi-digit numbers. Edit 2 … Read more
You can use something like this : (https?:\/\/www\.google\.(?:(?:com)|(?:co\.in)).*#q=.+) For Google search result url. Since in Google the searched word will be there , after q= DEMO Explanation: solved Regular Expression For indenfity google search pages [closed]
To get everything between two pattern you can use this sed command: sed -n ‘/.* id:.*/,/.* uid:.*/p’ log.txt And you’ll get — Request — some content …. — Response — …. where -n suppresses automatic printing of pattern space p prints the current pattern space 1 solved Extract part of log file
Sounds like by “the last part”, you mean “the part before the query string or after the last slash if there’s no query string”, right? Well, you can find the bit after the last slash with this: /([^\/]+)$/ And you can find the bit between a slash and the first question mark like this: /([^\/]+)\?/. … Read more
Your content contains no ” quotes, and no text gm, so why would you expect that regex to match? FYI: Syntaxes like “foo”gm or /foo/gm are something other languages do for regex literals. Java doesn’t do that. The g flag is implied by the fact that you’re using a find() loop, and m is the … Read more
awk -F ‘|’ -v ‘OFS=|’ ‘{$13 = $16; NF -= 3; print}’ file or perl -F’\|’ -ne ‘splice(@F, 12, 3); print join(“|”, @F)’ file 1 solved How to match and remove a string of characters in a pattern
If you won’t have more than one of the pattern on a single line, I’d probably use sed: sed -n -e ‘s%.*https://\([-.0-9A-Za-z]\{1,\}\.[A-Za-z]\{2,\}\).*%\1%p’ Given the data file: Nothing here Before https://example.com after https://example.com and after Before you get to https://www.example.com And double your https://example.com for fun and happiness https://www.example.com in triplicate https://a.bb and nothing here The … Read more