[ad_1] You can use the following ([abAB])\.([abAB]) >>> import re >>> s = [‘a.b’, ‘A.b’, ‘a.B’, ‘A.B’] >>> [re.sub(r'([abAB])\.([abAB])’, r’\1. \2′, i) for i in s] [‘a. b’, ‘A. b’, ‘a. B’, ‘A. B’] The issue with your approach is that you are not saving capturing groups to use in the result of the substitution. … Read more
[ad_1] I believe you are looking for a regex pattern (?<!%%)(?<=%)\w+(?=%)(?!%%) That would find variables that are surrounded by a single % character on each side. Test the regex here. Java code: final Pattern pattern = Pattern.compile(“(?<!%%)(?<=%)\\w+(?=%)(?!%%)”); final Matcher matcher = pattern.matcher(input); while (matcher.find()) { System.out.println(matcher.group(0)); } Test the Java code here. UPDATE: If you … Read more
[ad_1] You don’t need a regex for this, you can use URL parameters. app.get(‘/foo/bar/:slug’, function(req, res, next) { console.log(req.params.slug); next(); } ); Requesting /foo/bar/myImage.jpg would populate req.params.slug with ‘myImage.jpg’. 2 [ad_2] solved Regexp in express get request
[ad_1] Given your requirement as described: var output = Regex.Split(input, “(?<!or.*),”); However, given your sample output it seems you want to split on ‘or’ as well: var output = Regex.Split(input, “((?<!or.*),)|(or)”, RegexOptions.ExplicitCapture); 4 [ad_2] solved C# Regex to split string by commas that are only before “or” [closed]
[ad_1] You may want to take a look at this: addEventListener(‘load’, function(){ var wtf=”arg1:”2 words” business corporate arg2:val2 arg3:”fixedIt””; function customObj(string){ var a = string.split(/\s+(?!\w+”)/), x = [], o = {}; for(var i=0,s,k,l=a.length; i<l; i++){ s = a[i].split(/:/); k = s[0]; s[1] ? o[k] = s[1].replace(/”/g, ”) : x.push(k); } o[‘extra’] = x.join(‘ ‘); return … Read more
[ad_1] use: string sample = “1a2b3c4d”; MatchCollection matches = Regex.Matches(sample, @”\d”); List<string> matchesList = new List<string>(); foreach (Match match in matches) matchesList.Add(match.Value); matchesList.ForEach(Console.WriteLine); or use LINQ: List<string> matchesList2 = new List<string>(); matchesList2.AddRange( from Match match in matches select match.Value ); matchesList2.ForEach(Console.WriteLine); 6 [ad_2] solved c# should i use string with regex matchs or not
[ad_1] You need to anchor your pattern and use lookahead to validate those cases. if(preg_match(‘/^(?=.*[A-Z])(?=.*[a-z])(?=.*[0-9])[a-zA-Z0-9@:.]+$/’, $username)) { … } (?= … ) is a zero-width assertion which does not consume any characters on the string. Therefore, It only matches a position in the string. The point of zero-width is the validation to see if a … Read more
[ad_1] This seems like a regular expression. There * is not a wildcard but a quantifier. It means that the preceding character or group can occur zero or more times. . is a wildcard. It means any character except newline. […] is a character set. It means any character from the set. . is a … Read more
[ad_1] Assuming you only want to match letters: d[a-zA-Z]{2}$ or d[a-zA-Z]{2}\b Depending if you want to match strings (first example) or words (second). 0 [ad_2] solved Regular expression to match last 3 letter pattern in a string
[ad_1] Regular expression functions in Python return None when the regular expression does not match the given string. So in your case, match is None, so calling match.groupdict() is trying to call a method on nothing. You should check for match first, and then you also don’t need to catch any exception when accessing groupdict(): … Read more
[ad_1] To solve this problem you can use a positive lookahead ‘.*(?=START)’, as follows: # load environment library(stringr) # create text vector text = c(‘hello guys this is it START hi’, ‘one two START this is good’, ‘a longer example. I cannot believe it! START hello’) # remove pattern text = str_remove(text, ‘.*(?=START)’) # print … Read more
[ad_1] Here are the required steps: Use the u pattern option. This turns on PCRE_UTF8 and PCRE_UCP (the PHP docs forget to mention that one): PCRE_UTF8 This option causes PCRE to regard both the pattern and the subject as strings of UTF-8 characters instead of single-byte strings. However, it is available only when PCRE is … Read more
[ad_1] Tested this RegEx against your test string: ([Ss]peak(.|\r|\n)*?(?=http)) The part (?=http) is the positive lookahead, which asserts that at the end of your string http follows. [ad_2] solved Finding a string that matches till http is found [duplicate]
[ad_1] ^(?=.*[A-Z]{1,})(?=.*[a-z]{1,})(?=.*[0-9]{1,})(?=.*[!@#\$%\^&\*()_\+\-={}\[\]\\:;”‘<>,./]{1,}).{4,}$ should do it. Explaination: ^ start (?=.*[A-Z]{1,}) at least one upper (?=.*[a-z]{1,}) at least one lower (?=.*[0-9]{1,}) at least one digit (?=.*[!@#\$%\^&\*()_\+\-={}\[\]\\:;”‘<>,./]{1,}) at least one of the mentioned chars .{4,} min length 4 $ end [ad_2] solved Password RegExpression [closed]
[ad_1] You can try ^(?!0\*0)(?:\d+\*\d+,?)+$. ^ and $ ensure that the entire string matches. (?!0\*0) is a negative look ahead to check that the string is not 0*0. (?: and ) indicates that the contents are a non-capturing group \d+ matches one or more digits (0–9) \* matches a literal * character \d+ matches one … Read more