Ok, first you should probably write your regex as: [\u0600-\u06FF\uFB8A\u067E\u0686\u06AF \.!?:)(,;1234567890%\-_#]+$ Here %\-_ inside […] means % or – or _ while your %-_ means “any symbol with the code from % to _. Try /[%-_]/.exec(“)”) and see what I mean: the ) symbol is in that range. I also put \. which highlights that … Read more
I know the OP says it has to be a regex, but I agree with @tbodt’s comment above. This will accomplish what the OP is asking for without a regex and is posted here for anyone trying to solve a similar problem and is open to a different type of solution. function everyAHasMatchingB(str) { return … Read more
Use this: grep -A 1 -B 1 ‘Server sent’ file.txt | sed ‘/^–$/d’ (OR) grep -C 1 ‘Server sent’ file.txt | sed ‘/^–$/d’ 0 solved Print every 3 strings who are start from special symbols
Build a regexp like this : .+?(r).* where r is you regexp. Java Code String s;// Your string String r;// Your regexp Pattern p = Pattern.compile(String.format(“.+?(%s).*”,r)); Matcher m = p.matcher(s); if (m.find()) { System.out.println(m.group(1)); } Note I assume your regexp will be matched only one time in your string s. 1 solved How do you … Read more
I’ll take one stab at this with two implementations. First, I’ll use a character vector. If yours is in a frame, replace it with myframe$mycolumn. v <- c(“110231 validation 108871 validation 85933”, “21102 validation 93442 21232 validation 73769 26402 validation 127221 26402”, “99763 99763 validation 99763 validation 99763”, “validation 199022 validation 122099 validation 12209 validation … Read more
In general case one would parse and write the BDF files with something like the pyNastran. However in this specific case using your approach is not that wrong; though your regular expressions are wrong, though the principle works here. Notice also, you need to use raw strings or escape \ in the paths; the use … Read more
[!?.]+(?=$|\s) Try this.You can add markers as needed.Replace by “. See demo. http://regex101.com/r/lS5tT3/15 7 solved Regex to match end-of-sentence markers [closed]
If you want to test if a string contains at least one alphanumeric and at least one non-alphanumeric string, use the following regex: /^(?=.*[a-z0-9])(?=.*[^a-z0-9])/i Breakup: / start of regex ^ match the start of the string (?= if the following is present there: .* anything at all (except newlines), then [a-z0-9] an alphanumeric character ) … Read more
“^[^ put_anything_you_dont_want_like_specials_and_space_in_here]{6,50}$” 0 solved Regex for string matching following criteria
One way to tell if the entry has been previously split is as follows If the regex.test fails, then If the results line passes, then the item has been previously split if not, then it is a blank, or a malformed entry Note that a lot of this could be avoided if you were not … Read more
You do not need a regex for this, because a greedy algorithm will do. You can match a string against a pattern in O(n+p), where n is the length of string and p is the length of pattern, by following a very simple strategy: for each character of the pattern, look for a matching character … Read more
If you don’t mind pushing this through multiple passes, I might suggest this: Search: ^(Query=.*\n)((?:(?!Query=).*\n)+)\1 Replace: \1\2 Live demo 1 solved How to concatenate multiples lines under first occurence of the header using Unix commands?
[javascript]-Regex code to input the text field not allowing to start with 0, but allow 0 and should not allow characters +,-, [closed] solved [javascript]-Regex code to input the text field not allowing to start with 0, but allow 0 and should not allow characters +,-, [closed]
You need to check for anchors (^ and $ forcing the check at the beginning and end of the string) as well, not just the patterns. ^\d{4}-[a-z]{4}-\d{5}$ Use with i option to ignore letter case. See demo Sample code: var re = /^\d{4}-[a-z]{4}-\d{5}$/i; var str=”1234-abcd-12345″; if (re.test(str)) { alert(“found”); } solved Not able to get … Read more
Why regular expression on numbers? You can select all numbers less than 1000 and greater than 99. my_array.select { |n| n<1000 && n>99 } 0 solved Get all three digit numbers from array and store in new array [closed]