[ad_1] No need for a regexp: you just need to scan the string once and LINQ your way through the task. yourString.Select(c => string.Format(Char.IsUpper(c) ? ” {0}” : “{0}”, c)); This will hand you a IEnumerable<string> object containing all the data you need, which can become what you need like this: string[] output = string.Split(” … Read more
[ad_1] Just split by a newline and get the first element: test_str = “# <init> (Lorg/cyanogenmod/audiofx/ActivityMusic;)V\n , 0 iput-object v1, v0, Lorg/cyanogenmod/audiofx/ActivityMusic$11;->this$0 Lorg/cyanogenmod/audiofx/ActivityMusic;\n , 4 invoke-direct v0, Ljava/lang/Object;-><init>()V\n , a return-void ” print(test_str.split(‘\n’)[0]) See demo Output: # <init> (Lorg/cyanogenmod/audiofx/ActivityMusic;)V. If it is not the first line: A non-regex way: test_str = “some string\n# <init> (Lorg/cyanogenmod/audiofx/ActivityMusic;)V\n … Read more
[ad_1] Try System.out.println(“10 and Mayfield and London”.replaceAll(“(\\p{Alpha}+)”, “SYN($1)”).replace(“SYN(and)”, “and”)); output 10 and SYN(Mayfield) and SYN(London) 1 [ad_2] solved regular expression wrapping words [closed]
[ad_1] Well I was able to figure this out after a couple of days at it. This issue here is that Regex is that it will match a string as a whole, so if I wanted the exclude a character from a match I could do so by using Regex to drop either the first … Read more
[ad_1] Try: var value = $(“param[name=”movie”]”).val();//get attribyte value if(value && (value = value.match(/secEncCode=(\w+)/))){//reg exp value = value[1];//get first pocket console.log(value);//res } http://jsfiddle.net/xbQxw/ update by comment If you want change secEncCode value: var param = $(“param[name=”movie”]”),//get obj value=param.val(),//get attribyte value key; if(value && (key = value.match(/secEncCode=(\w+)/))){//reg exp key = key[1];//get first pocket param.val(value.replace(key, “YOUR NEW KEY”));//replace … Read more
[ad_1] const regex = /(.*?&.*?)&.*/; const str = `https://www.bing.com/search?q=something+something+something+something&mkt=en-IN&organic=True&ads=False&snippet=False`; const result = str.replace(regex, ‘$1’); The regular expression searches everything before the second “&” and replaces the original string with this match. [ad_2] solved Regex for finding the second occurrence of a character in a dynamic string in javascript
[ad_1] Try this : put id for anchor tag <a id=”anchor1″ href=”https://stackoverflow.com/questions/25931155/site.com/register.php?mid=username&mode=bn&bid=1″> use below javascript <script> var href = document.getElementById(‘anchor1’).href; //get index of ? var indexStart = href.indexOf(‘?’); var indexLast = href.length; //get href from ? upto total length var params = href.substring(indexStart+1, indexLast); //get tokens with seperator as ‘&’ and iterate it var paramsArray … Read more
[ad_1] Extract the number from the string then increment it and put it back, e.g. using String.replaceXxx() and Integer.parseInt() etc. If you want to increment multiple independent numbers, try this: String input = “ABC999DEF999XYZ”; //find numbers Pattern p = Pattern.compile( “[0-9]+” ); Matcher m = p.matcher( input ); StringBuffer sb = new StringBuffer(); //loop through … Read more
[ad_1] I’m assuming you want ASCII letters and digits, but not Thai digits, Arabic letters and the like. AANNN is (?i)^[a-z]{2}[0-9]{3}$ ANEE is (?i)^[a-z][0-9][a-z0-9]{2}$ Explanation The ^ anchor asserts that we are at the beginning of the string [a-z] is what’s called a character class. It allows any chars between a and z. In a … Read more
[ad_1] The escaped quotes match each other in the HTML string that you’re creating. The quotes are not “surrounding” +i+. They’re being used to end the string that begins with “<p id=\”element” and to begin the next string: “\”>Hello world, …” This is concatenating i between these two strings. So if i contains 0, the … Read more
[ad_1] A new approach since Java’s Regex.Split() doesn’t seem to keep the delimiters in the result, even if they are enclosed in a capturing group: Pattern regex = Pattern.compile( “[+-]? # Match a number, starting with an optional sign,\n” + “\\d+ # a mandatory integer part,\n” + “(?:\\.\\d+)? # optionally followed by a decimal part\n” … Read more
[ad_1] If you want to catch all strings containing only upper and lowercase characters, periods and spaces, you can use ^[a-zA-Z\. ]+$ Here’s a breakdown of how the regex works ^ matches the beginning of the string [a-zA-Z\. ] matches any character a-z, A-Z, or a period or space + makes the above match any … Read more
[ad_1] (?> … ) is the syntax for an atomic grouping. And the syntax for look-ahead assertion is just (?! … ). Edit Try this regular expression instead: .*$(?<!-CONST) The .*$ will consume everything and the look-behind assertion will exclude those that end with a -CONST. Edit Just for completeness’ sake: If your regular expression language does … Read more
[ad_1] You could use Regex.Replace for converting matches to UpperCase. For example, var result= Regex.Replace(text, pattern,c=>c.ToString().ToUpper()); 1 [ad_2] solved How do I find Roman Numerals in a string and make it all upper case in C#? [closed]
[ad_1] This expression matches only those desired iOS versions listed: iOS[89]|iOS[1][0-3] Demo Test const regex = /iOS[89]|iOS[1][0-3]/gm; const str = `iOS7 iOS8 iOS9 iOS10 iOS11 iOS12 iOS13 iOS14`; let m; while ((m = regex.exec(str)) !== null) { // This is necessary to avoid infinite loops with zero-width matches if (m.index === regex.lastIndex) { regex.lastIndex++; } … Read more