regex

[Solved] How to validate image file extension with regular expression using JavaScript [duplicate]

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Accordingly your issue the regular expression is quite simple. /\.(jpe?g|png|gif|bmp)$/i Do you really sure that nothing else will be used? For example, JPEG format allows both .jpg and .jpeg extensions. That’s why I put e? pattern in the regular expression. Example of validation could be as follows: var filename = “/site/images/test.png”; if ( /\.(jpe?g|png|gif|bmp)$/i.test(filename) ) … Read more

[Solved] Email Regex. Is this regex expression appropriate? [duplicate]

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What do you think of the above expression for email validation. For one, it doesn’t accept my address. So, there’s obviously a bug in there somewhere. I suggest you read RfC5322 carefully, it describes the valid syntax for addresses quite clearly, although unfortunately it hasn’t yet been updated for IDN. solved Email Regex. Is this … Read more

[Solved] I want to separate several parts of a String in Java [closed]

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This approach should work… // The variable ‘parts’ will contain 2 items: your 2 integers, though they will still be String objects String[] parts = myString.split(“mod”); try { int firstInt = Integer.parseInt(parts[0]); int secondInt = Integer.parseInt(parts[1]); ) catch(NumberFormatException nfe) { // One of your Strings was not an integer value } 0 solved I want … Read more

[Solved] Regex remove before colon notepad++ [closed]

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Instead of ^[^:]*:, use ^.+: because [^:] matches also newline. Find what: ^.+: Replace with: NOTHING Don’t check dot matches newline Edit according to comment: This will match the last occurrence of : within each line. If you want to match the first occurrence of : use ^.+?: 2 solved Regex remove before colon notepad++ … Read more

[Solved] java regular expression take next value [closed]

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If you want only the 12th value Using split: (very simply, a bit inefficient, but probably not too bad – I wouldn’t bother with anything else unless I’m writing production code) System.out.println(str.split(“,”)[12]); Using indexOf: (somewhat more complex, way more efficient) int index = 0; for (int i = 0; i < 12; i++) index = … Read more

[Solved] Regex to match given string filenames in a string

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This one should work exactly for first two files, but won’t work if there any additional special characters in file names: using System; using System.Collections.Generic; using System.Text.RegularExpressions; namespace ConsoleApplication1 { class Program { static void Main(string[] args) { const string example = “PrintFileURL(\”13572_IndividualInformationReportDelta_2012-06-29_033352.zip\”,\”13572_IndividualInformationReportDelta_2012-06-29_033352.zip\”,0,\”53147\”,\”Jun 29 3:33\”,\”/icons/default.gif\”)”; Console.WriteLine(example); const string pattern = “\\\”([a-zA-Z0-9\\-_]*?\\..*?)\\\””; var regex = new … Read more

[Solved] Regex to remove specific params from tags [closed]

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HEIGHT: \d+[^;]+; will match HEIGHT: 218px; in <body style=”HEIGHT: 218px; margin: 0px; background-color: #ffffff;” jQuery111105496473080628138=”10″> Something like this could get you going: (HEIGHT:\s*\d{1,}[^;]*;)(?<=<body.*style=”[^”]*)(?=[^”].*”\s*>) Which ~translates~ to : Capture: (HEIGHT:\s*\d{1,}[^;]*;) If preceded by: (?<=<body.*style=”[^”]*) And followed by: (?=[^”].*”\s*>) Implemented in code: using System; using System.Collections.Generic; using System.Text.RegularExpressions; static void Main(string[] args) { string string1 = “<body … Read more

[Solved] ñ to Ñ string php

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You will need to play with encoding. $content=”Nuñez”; mb_internal_encoding(‘UTF-8’); if(!mb_check_encoding($content, ‘UTF-8’) OR !($content === mb_convert_encoding(mb_convert_encoding($content, ‘UTF-32’, ‘UTF-8’ ), ‘UTF-8’, ‘UTF-32’))) { $content = mb_convert_encoding($content, ‘UTF-8’); } // NUÑEZ echo mb_convert_case($content, MB_CASE_UPPER, “UTF-8”); via PHP: mb_strtoupper not working solved ñ to Ñ string php

[Solved] How to generate numbers based on a pattern in python [closed]

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This should work: [int(“4″*i + “0”*(n-i)) for n in range(0,31) for i in range(1,n+1)] It generates 465 distinct integers: 4, 40, 44, 400, 440, …, 444444444444444444444444444440, 444444444444444444444444444444 On Edit: A recursive approach works in the more general case: def multiRepeats(chars,n,initial = True): strings = [] if len(chars) == 0 or n == 0: return [“”] … Read more

[Solved] How to find if a string contains uppercase letters and digits [closed]

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This should help: import re # Check if the string has 3 digits or more def haveDigits(text): if len(filter(str.isdigit, text))>=3: return True else: return False # Check if the string has 2 uppercase letters or more def haveUppercase(text): if len([char for char in text if char.isupper()])>=2: return True else: return False # First condition print(haveDigits(“hola123”)) … Read more