This is about the leanest you can get with that: Hello(?:[ /]?World)?|World Expanded: Hello (?: [ /]? World )? | World solved I need a regex pattern which matches the following Hello, World, Hello World
String[] values = input.replaceAll(“^[.,\\s]+”, “”).split(“[.,\\s]+”); Original Source: Split a string with arbitrary number of commas and spaces 3 solved Java Regex to get only words [closed]
You can use: String result = “http://sdsadasd/time/time.jsp?tp=&a”.replaceFirst(“time\\.jsp”, “java.jsp”); Or using the good friend ApacheCommon StringUtils… String result = StringUtils.replaceOnce(“http://sdsadasd/time/time.jsp?tp=&a”, “time.jsp”, “java.jsp”); For example, you can do: public static void main(String[] args) { String result = “http://sdsadasd/time/time.jsp?tp=&a”.replaceFirst(“time\\.jsp”, “java.jsp”); System.out.println(result); } // Print: http://sdsadasd/time/java.jsp?tp=&a 4 solved Replace Exact String in Java
Here is the code which searches for the number at the start. If number is matched it prints message in console. let regex = /^[0-9]/; let object = [{email:’[email protected]’},{email:’[email protected]’}]; for(let i =0;i<object.length;i++){ if(object[i].email.match(regex)){ console.log(‘E-mail ‘,object[i].email,’ is not valid.’) } } This is the used regex: ^[0-9] solved Email Regex for Javascript Which not start with … Read more
seems like a crazy question but why not >>> myval=”ObjectId(“5a60a394ac73c233ba1acc55″)” >>> myval.split(“(“)[1] ‘”5a60a394ac73c233ba1acc55”)’ >>> myval.split(“(“)[1].split(“)”)[0] ‘”5a60a394ac73c233ba1acc55″‘ >>> import re >>> re.findall(‘[a-zA-z0-9]’, myval.split(“(“)[1].split(“)”)[0]) [‘5’, ‘a’, ‘6’, ‘0’, ‘a’, ‘3’, ‘9’, ‘4’, ‘a’, ‘c’, ‘7’, ‘3’, ‘c’, ‘2’, ‘3’, ‘3’, ‘b’, ‘a’, ‘1’, ‘a’, ‘c’, ‘c’, ‘5’, ‘5’] >>> “”.join(re.findall(‘[a-zA-z0-9]’, myval.split(“(“)[1].split(“)”)[0])) ‘5a60a394ac73c233ba1acc55’ solved How to extract string … Read more
If it’s about filename, like Greg thinks, then I’d suggest find . -type f -not -name \*.\* command instead. 0 solved How can I find filenames that do not have a . in them? [closed]
preg_replace (‘/^(.) (.*) (.)$/’, ‘$1$2$3’, $string); 2 solved Replace spaces between first character and second one also reverse remove spaces between last and last but one? [closed]
String valueData = “{\”x\”:10,\”y\”:10,\”z\”:10}.”; valueData = valueData.replace(“.”, “”); valueData = valueData.replace(“{“, “”); valueData = valueData.replace(“}”, “”); valueData = valueData.replace(“\””, “”); System.out.println(valueData); 4 solved How to split and replace comma and parenthesis?
string.matches(“^([A-Za-z’\”][A-Za-z0-9_’\”]* *)+$”) Visualization 1 solved a word should not start with a digit in Java [closed]
use a character class to split the values: /(-?[\d.]+)/ -? May start with a negative such as -123 [\d.]+ Has one or more numbers and decimals var string = “stuff 1.23! (456) 789 stuff -234”.split(/(-?[\d.]+)/); console.log(string) solved Javascript Array – Split string at numbers [closed]
Give this one a shot: (\d+[\/\d. ]*|\d) http://regex101.com/r/oO9yI9 In the future, I’d suggest making your question more clear so we can actually understand what you’re trying to do — provide inputs, expected outputs, and include the programming language you’re using. vb.net is PCRE compliant, so you should be able to use this: Dim regex As … Read more
Use a regex like this: Building(\d+)Floor(\d+) 3 solved How do I get two numbers between two words (C#) [closed]
Here shows you how to use regex in C#. You could always just loop the directory that you’re looking in and check the file names instead of making a regex. (You’ll need to use System.IO) Perhaps something like this? string [] fileEntries = Directory.GetFiles(targetDirectory); Regex regex = new Regex(“target file name”); Match match = regex.Match(string.Join(” … Read more
You can use this regex ^(?=\d)(?!0(?![.]))(?:\d{0,3})(?:[.]\d{1,3})?$ Regex Demo Regex Breakdown ^ #Start of string (?=\d) #Lookahead to ensure there is a dot or number (?!0(?![.])) #Negative lookahead to ensure there is no 0 in starting followed by . (?:\d{0,3}) #Match at most three digits before decimal (?:[.]\d{1,3})? #Match at most three digits after decimal. If … Read more
str = “IV_04.03.2019-10-56-45_example_c584536f-ab26-40ce-b5b6-386f755ba747_1.csv” s1= str.split(“_”)[2] s2= str.split(“_”)[3] print (s1) print (s2) output: example c584536f-ab26-40ce-b5b6-386f755ba747 3 solved How to get string between two underscores? [closed]