[ad_1] Use (.*)(?:Bangalore) pattern >>> line = (“Kathick Kumar, Bangalore who was a great person and lived from 29thMarch 1980 – 21 Dec 2014”) >>> import re >>> regex = re.compile(‘(.*)(?:Bangalore)’) >>> result = regex.search(line) >>> print(result.group(0)) Kathick Kumar, Bangalore >>> 1 [ad_2] solved Extracting using a string pattern in Regex- Python
[ad_1] Limit the use of Regex to clean up the string, then put the cleaned string into json. Remember that the JSON specification uses double quotes “. [ad_2] solved How to convert String to Json using Regex?
[ad_1] Like this? Basically extract anything starting with {“old and till }}. {“old.+}} Regex demo. 5 [ad_2] solved extract sub string from a string using regex [closed]
[ad_1] According to Generate a Regular Expression to Match an Arbitrary Numeric Range, and after generating such a regex for your example at Regex_For_Range: \b0*(1[1-9][0-9]|[2-9][0-9]{2}|1[0-9]{3}|2[01][0-9]{2}|22[0-2][0-9]|223[0-4])\b would do the trick. The process would be (still following that Regex generator): First, break into equal length ranges: 110 – 999 1000 – 2234 Second, break into ranges that … Read more
[ad_1] String object cannot store whether the text is bold, italic. It has only a character array. Bold or Italic means a visual effect. You can try something like following to detect what are the text you should add effects. String str = “Google Plus style #ListViews are all the rage these days on #Android … Read more
[ad_1] You should be able to use the following : match \\abc{([^}]*)}{([^}]*)} replace by \1 : \2 You can try it here. [^}]* matches every character but }, it is used to match the content of the brackets without risk of overflowing. Aside from that we escape the \ to match its literal character, group … Read more
[ad_1] What you described is known as Levenshtein distance. There is library called Apache commons-text that you can use to do it for you. int ops = new LevenshteinDistance().apply(string1, string2) Here is source code 3 [ad_2] solved Calculate number of Updation, Insertion and Deletion on a One String to reach Another String [closed]
[ad_1] If different identifiers can have same values, your third map will keep the last parsed one. E.g. : File 1 : localId1 => “aaaa” localId2 => “bbbb” localId3 => “cccc” localId4 => “aaaa” File 2: localId1 => “1111” localId2 => “2222” localId3 => “3333” localId4 => “4444” Your first and second maps will store … Read more
[ad_1] Reimplement grep in Perl, and then use system to call your new grep command: # create a new perl script called “grep” in current directory # put this near the beginning of your script open GREP, “>grep”; print GREP <<‘EOF’; #! perl $regex = $ARGV[0]; while (<STDIN>) { print if $_ =~ $regex; } … Read more
[ad_1] I would use a negative lookahead assertion to make the regex fail if it is only “0”. @”^-?(?!0*(\.0*)?$)(0\.\d*[0-9]|[0-9]\d*(\.\d+)?)$ See it here on Regexr This expression (?!0*(\.0*)?$) makes the whole regex fail, if the number consists only of zeros. 0 [ad_2] solved Regex Pattern not alow zero [closed]
[ad_1] No need of regex here. Just split it using – and access the array element with index=1. var str = “RED-MPWMC-40486655646-024”; console.log(str.split(“-“)[1]); [ad_2] solved RegEx string – code with JavaScript [closed]
[ad_1] The slice method can be used for an Array or a String variable. The intention of slice method is to slice out some part of the data. For example, if I have a string let word = ‘India’; And I want to extract dia from it, we can do it using – let dia … Read more
[ad_1] Something like -{4,}? a{3,} Matches at least 3 consecutive a characters. Example: https://regex101.com/r/LmRMB2/1/ 3 [ad_2] solved How can I use regex to fix a string like “——–ab-c” to just “ab-c”? [closed]
[ad_1] I assume that you use your regex to find matches in the whole text string (all 3 lines together). I see also that both your alternatives contain starting ^ and ending $, so you want to limit the match to a single line and probably use m regex option. Note that [^…]+ expression matches … Read more
[ad_1] You are looking for the flag m (/regexp/m) It’s getting a little old, but http://rubular.com/ has a ruby regexp testing interface and the basic classes and modifiers remainder. [ad_2] solved Regex to match string over multiple lines