[ad_1] IIUC, you need to change the key before the reduce, and then map your values back in the desired format. You should be able to do the following: new_rdd = rdd.map(lambda row: ((row[0], row[1][0]), row[1][1]))\ .reduceByKey(sum). .map(lambda row: (row[0][0], (row[0][1], row[1]))) 0 [ad_2] solved python : reduce by key with if condition statement?
[ad_1] One method is to convert array into object, and use productId as key: const data = [ { productId: 6, productName: “pouch”, productPrice: 29000, discountRate: 19, optionName: “13inch”, optionPrice: 0, qty: 2, }, { productId: 6, productName: “pouch”, productPrice: 29000, discountRate: 19, optionName: “15inch”, optionPrice: 1000, qty: 1, }, { productId: 4, productName: “pouch”, … Read more
[ad_1] you can use regionprops for that , for example: s=regionprops(bw,’BoundingBox’,’PixelIdxList’); where bw is your binary image. The output of s.BoundingBox is a [x,y,width,height] vector you can loop over s for i=1:numel(s) ar(i) = s(i).BoundingBox(3)/s(i).BoundingBox(4) end and see if the width/height ratio ar (or whatever you define aspect ratio) is approx above 1 or not … Read more
[ad_1] An approach should consider breaking the OP’s entire task into two separate ones. Within an intermediate step one firstly does reduce the list of material items into a map of (grouped) material items. The final step does a map–reduce on the values of the intermediate result, where the reduce task is responsible for summing … Read more
[ad_1] def map(func, values): rest = values[1:] if rest: yield from map(func, rest) else: yield func(values[0]) It’s a generator so you can iterate over it: for result in map(int, ‘1234’): print(result + 10) Gives: 11 12 13 14 4 [ad_2] solved how to implement map and reduce function from scratch as recursive function in python? … Read more