Create a string of 100 letters, with 24 A’s, 12 B’s, and appropriate numbers of C’s and D’s. Generate a random number between 0 and 99; use this as an index into the string. That gives you your weighted random selection. That’s a simple but almost graphical way to do it. You can decide based … Read more
Using only integer numbers and Fisher-Yates shuffle: program cont3; {$APPTYPE CONSOLE} {$R *.res} uses System.SysUtils; const SummandsCount = 5; WantedSum = 100; var i, j, t, Cnt, WhereToInsert: integer; JustNaturalNumbers: array[1..WantedSum] of Integer; DividingPoints: array[0..SummandsCount] of Integer; begin Randomize; Cnt := 1; DividingPoints[0] := 0; DividingPoints[SummandsCount] := 100; for i := 1 to WantedSum – … Read more
Did you try googling for “boost random number” first? Here’s the relevant part of their documentation generating boost random numbers in a range You want something like this: #include <time.h> #include <boost/random/mersenne_twister.hpp> #include <boost/random/uniform_int_distribution.hpp> std::time(0) gen; int random_number(start, end) { boost::random::uniform_int_distribution<> dist(start, end); return dist(gen); } edit: this related question probably will answer most of … Read more
Due to the complaints that this question was not very direct I created other posts to get the answers I was looking for. This answers the main questions I had. Answers: Understanding how array.prototype.call() works explains the output of this pattern. A full detailed answer can be found here: Mapping Array in Javascript with sequential … Read more
You can print that character a random number of times in the following way: int rand = 1 + (rand() % maximum); for (int i = 0; i < rand; ++i) { printf(“%c”, RANDLOWER); } printf(“\n”); Replace maximum with the max number of characters you want to be printed. The reason I add the 1 … Read more
I’m not going to give you a full answer because then you wouldn’t learn from it. I am going to answer your question by giving an example of a shuffle that you could then use in your situation. This is a custom method to shuffle an array: public void shuffle(int[] t){ int temp = 0; … Read more
Good question… This is really hard to answer but I attempted a solution(what engineers try to do) that might work based on analyzing the pattern example you gave: import string import random def generate_similar(string): # Generates similar name by substituting vowels similar_word = [] for char in string: if char.lower() in ‘aeiou’: similar_word.append(random.choice(string.letters).lowercase()) else: similar_word.append(char) … Read more
Create random date from today Have while loop, Check generated already exist in exclude dates array (continue loop until you find date which is not in dates array) const randomDateFromToday = (exclude_dates, max_days = 365) => { const randomDate = () => { const rand = Math.floor(Math.random() * max_days) * 1000 * 60 * 60 … Read more
You could use the Set object. When using the method add(), values cannot be duplicated. Here is an example: function random(x, max = 10) { // x = how many random numbers and max = the max number const set = new Set(); for (let i = 0; i <= x; i++) { // Generate … Read more
Math.random() returns a double value between 0 (inclusive) and 1 (exclusive). It does not return an integer value. Therefore, when you take the number produced by Math.random() modulo 10, it returns the same double value. The final cast to int makes that value always 0. Run the following code to see for yourself: double random … Read more
Right now you generate any word type just once. Just generate the randoms before any phase function makeAPoem() { var nouns = [“cat”, “crow”, “snow”, “home”, “boy”, “raven”, “tree”, “moon”, “night”, “day”, “winter”, “heart”, “angel”, “madam”, “darkness”, “chamber”, “lady”, “bird”, “person”, “eye”, “darkness”, “air”]; var verbs = [“ran”, “felt”, “fell”, “focused”, “looked”, “stared”, “sat”, “sighed”, … Read more
nextGaussian() can return any value that can represented by a double data type. Gaussian distribution approaches but never reaches 0 on either side. So it’s theoretically possible to get a value of Double.MAX_VALUE, but very unlikely. Gaussian distribution looks like this: (http://hyperphysics.phy-astr.gsu.edu/hbase/Math/gaufcn.html) The distribution stretches to positive and negative infinity, so there is theoretically no … Read more
You’ve already generated a random number here: new Random().nextInt(names.length) You can use this random number to access an element in the names array. int randomNumber = new Random().nextInt(names.length); String option = names[randomNumber]; // here is the important bit! Now you can print option out! System.out.println(“You are going to eat ” + option); 0 solved How … Read more
Introduction Generating random numbers is a common task in programming, and it can be useful for a variety of applications. However, sometimes it is desirable to generate random numbers that are weighted towards certain numbers. This can be useful for creating a more realistic random distribution, or for creating a game with a higher chance … Read more
public static void main(String[] args){ ArrayList<Integer> list = new ArrayList<Integer>(); list.add(5);list.add(2);// to be continued … int randomInt = list.get((int) (Math.random() * list.size())); System.out.println(randomInt); } You’ll get your List of values, and then you just need to pick randomly an index and get back the value Math.random() will pick a value in [0;1[, if you multiply … Read more