If you have F unique first names and L unique last names, then overall number of combinations is N = F * L So you can generate needed number of non-repeating random integer values in range 0..N-1 (for example, with Fisher-Yates sampling), sort them, and get corresponding name combinations: for i = 0..M-1 Generate K[i] … Read more
You generate the CC number once and display it multiple times. Instead, put the CC generator in the loop. from random import choices from string import digits for _ in range(5): cc_digits = choices(digits, k=16) cc_number = “”.join(cc_digits) space = ” “.join(cc_number[i:i+4] for i in range(0, len(cc_number), 4)) print(space) 1 solved How do I print … Read more
I do not know what within() does, but you may want to use the new methods to generate random numbers introduced with C++11. The link has a nice example. In case the link will become invalid in some future time, here’s the relevant code: #include <iostream> #include <random> int main { // Seed with a … Read more
you can use a for loop to generate it 3000 times for($i = 0; $i < 3000; $i++){ echo ‘mytext/’.generateRandomString().'<br>’; } The answer was inside your code snippet that you provided solved how to generate a random string + text + multiple lines
visit this link to find your solution. or try this code var originalArray:Array = new Array(‘Bob’, ‘George’, ‘Tom’, ‘Mohammed’, ‘Adam’, ‘Moses’, ‘Aaron’, ‘David’); var shuffledArray:Array = originalArray.sort(shuffle); trace(shuffledArray); private function shuffle(originalArray,shuffledArray):int { var sortNum : int = Math.round(Math.random() * 2) – 1; return sortNum; } 9 solved as3 randomly picking names
int count=0; if((second%10)==first){ count++; } if(Math.round((second/10))==first){ count++; } System.out.println(first+” occurs “+count+” times in “+second); Maybe this can help you ;), replace your last println by this 8 lines 😉 but as shmosel sait in comment, be carreful it’s int first = n.nextInt(10); int second = n.nextInt(90)+10; 0 solved How to check how many times one … Read more
NSArray *arrNumbers = @[@2, @4, @7, @9, @13, @15]; NSLog(@”%d”,[[arrNumbers objectAtIndex:arc4random_uniform(arrNumbers.count)] intValue]); 6 solved generate random number from given set of numbers in ios [closed]
Qoutes = []; Qoutes[0] = “yolo”; Qoutes[1] = “swag”; Qoutes[2] = “vdsa”; Qoutes[3] = “yolo”; Qoutes[4] = “swag”; Qoutes[5] = “vdsa”; Qoutes[6] = “yolo”; Qoutes[7] = “swag”; Qoutes[8] = “vdsa”; Qoutes[9] = “yolo”; Qoutes[10] = “swag”; Qoutes[11] = “vdsa”; You need to place quotes around your strings, or else Javascript will assume that they are … Read more
You can activate your program via the command prompt and then write this block of code in python: import random import shutil columns, rows = shutil.get_terminal_size(fallback=(80, 24)) size_of_console = columns * rows for i in range (size_of_console): print(chr(random.randint(33, 126)), end = ”) make sure you have the right libraries installed and you are good to … Read more
You realize, of course, that even a fair coin can give you ten heads in a row. There’s a probability that can be assigned to that combination. A fair coin will give half heads and half tails over many trials, but it’s not guaranteed to be 50/50 over a shorter run. Your own experience of … Read more
What you did is clean and fast enough. What you could improve on it is to pre-allocate the slice and fill it using a for.. range loop like this: s := make([]int, 5) for i := range s { s[i] = rand.Intn(100) } The math/rand package also has a rand.Read() function which fills a slice … Read more
You’re reseeding the pseudo-random sequence with the same seed before each call to rand, since the value returned by time only changes once a second. That causes you to get the same result each time. Only call srand once, at the start of the program. Better still, look at the C++11 <random> library, which has … Read more
The problem in your program comes from the subject selection (after adding the missing }): s=random_number_creator(5,0); Will return a random number between 0 and 4 included. To correct this, just replace this line by s=random_number_creator(7,0); To pick a number between 0 and 6. So the cou variable will be able to reach 0 Your code … Read more
I prefer to use shuffle. #include <algorithm> #include <iostream> #include <random> #include <vector> #include <cassert> class T455_t { private: // data std::vector<int> m_iVec ; public: T455_t() {} int exec() { std::vector<int> iVec; gen10(); for (int i=0; i<10; ++i) { int nxtRandom = uniqueRandomInt(); std::cout << nxtRandom << std::endl; } return(0); } private: // methods void … Read more
You should use r.nextInt(3); to get a number from the range 0-2. So, switch(r.nextInt(3)) { case 0: myVar = “a”; break; case 1: myVar = “b”; break; case 2: myVar = “c”; break; } 0 solved How do yo randomly assign a value to a variable? [closed]