Here is the closest code: public class Stackoverflow_03262019 { public static void main(String[] args) { int[] arr=new int[5]; Arrays.fill(arr,0); Arrays.stream(arr).forEach(val-> System.out.println(val)); } } “` You can add any value instead of 0; 2 solved Is it possible to do this in Java? [closed]
EDIT: Sorry, misread your question. I thought you only wanted to keep these values. Changed my code accordingly. list1 = [“13:00″,”13:10″,”13:20″,”13:30″,”13:40”] range_start = “13:10” range_end = “13:30” You can use list comprehension with the range condition: list1 = [x for x in list1 if not(range_start<=x<=range_end)] print(list1) You could also use filter on your list: list1=list(filter(lambda … Read more
If you want only print the resulting dictionaries, uncomment the print statement (and comment the following 2). d1 = [ {‘index’:’1′,’color’:’red’}, {‘index’:’2′,’color’:’blue’}, {‘index’:’3′,’color’:’green’} ] d2 = [ {‘device’:’1′,’name’:’x’}, {‘device’:’2′,’name’:’y’}, {‘device’:’3′,’name’:’z’} ] result_list = [] for dict1 in d1: merged_dict = dict1.copy() for dict2 in d2: merged_dict.update(dict2) # print(merged_dict) result_list.append(merged_dict.copy()) print(result_list) The result: [{‘name’: ‘x’, ‘device’: … Read more
In your program, you haven’t defined the variable participant_details so its value cannot be looked up. You should define that variable first before accessing it. 2 solved “errorMessage”: “name ‘ ‘ is not defined” [closed]
So this isn’t exactly an answer for the specific way you decided to go about this program but this is a much simpler way: from random import randrange def beginner_addition(): A = randrange(1,11) # Increase range on harder questions B = randrange(1,11) # Ex. for intermediate_addition(), randrange would be (10,21) maybe… C = A + … Read more
Here some ideas: use new_str = str.upper() so beer and Beer will be same (if you need this) use list = str.split() to make a list of the words in your string. use set = set(list) to get rid of double words if needed. start with an empty word_list. Copy the first set in the … Read more
You do not need to cast the int in your line number 1. Change this: x=int(10000) to this: x = 10000 Your code is fine, if the intention is to print the original value inside the loop and the last value i.e. 0 after the iterations, you need to print the current value afterwards. print(x) … Read more
Operator precedence. Bitwise operations have higher precedence than equality comparison operator, so your bitwise operation is being computed as: print (year%4 == (0 & (year%100==0 or year%400==0))) 0 solved Difference between & and and in python [duplicate]
>>>l1 = [i for i in range(1,25)] >>>l2 = [i for i in range(24, 50)] >>>[x for x in l1 if x in l2] [24] Sorry I misread. How about this: for i in range(len(l1)): for j in range(len(l2)): if l2[j] == l1[i]: print l2[j] If you need to add matches to a list just … Read more
Couple of points: Misplaced return statement. Should be at end. if yes(): It is wrong. You want to compare function input with yes. It should be if s == ‘yes’:. Same for rest also. Since you have written function definition as def shut_down(s):, it is expecting one argument. You should pass one argument while calling … Read more
To understand what yield does, you must understand what generators are. And before you can understand generators, you must understand iterables. Iterables When you create a list, you can read its items one by one. Reading its items one by one is called iteration: >>> mylist = [1, 2, 3] >>> for i in mylist: … Read more
If your goal is just to exchange the letters in a string with others that you specify, then the solution is the following: decrypted = ‘abcdefghijklmnopqrstuvwxyz’ #normal alphabet encrypted = ‘MNBVCXZLKJHGFDSAPOIUYTREWQ’ #your “crypted” alphabet #Encription text=”cryptme” #the string to be crypted encrypted_text=”” for letter in text: encrypted_text += encrypted[decrypted.find(letter)] print encrypted_text #will print BOWAUFC #Decription … Read more
You have to go to the settings in there and if there is no way of finding them then you can go onto the python website and reinstall them from there 🙂 solved Recovering Python modules
If you want a more pythonic way: from itertools import groupby from pprint import pprint from collections import ChainMap a = [{‘a’:0,’b’:23}, {‘a’:3,’b’:77}, {‘a’:1,’b’:99}] b = [{‘a’:1,’c’:666}, {‘a’:4,’c’:546}] c = [{‘d’:33,’a’:3}, {‘d’:1111,’a’:4}, {‘d’:76,’a’:1}, {‘d’:775,’a’:0}] d = [{‘a’:2,’e’:12}, {‘a’:4,’e’:76}] dict_list = a + b + c + d # You just need to specify the key … Read more
It is because [12, 2] is a list, and next notation: [0] or [1] is indexing. You can test it if you try to print: print([12, 2][2]) you should get index out of range error. EDIT: to answer your second question: It is hard to say. target_f = self.model.predict(state) – it is some kind of … Read more