This should do: import random num = random.randint(7, 14) print num message = “” prevnum = -1 for n in range(num): newnum = random.randint(100, 103) while newnum == prevnum: newnum = random.randint(100, 103) prevnum = newnum message += chr(newnum) You have made numerous mistakes in your code, you should review them. solved While Loop and … Read more
The range function creates an array of numbers between its parameters. For example: >>> range(1, 4) => [1, 2, 3] In your code you’re saying a%b which is finding the remainder between a number the user inputted and a range object. Think of the range object as a python list. So what you’re doing is … Read more
all the computationally expensive stuff can be done in opencv. so using python for the wrapper won’t cost you much computationally. 4 solved Image processing using Python and OpenCV on a Raspberry PI [closed]
To access a value from dictionary you need to simply use dictionary[key], so in your function you just need to return this value. solved Accessing a Dictionary [closed]
numbers = list(range(k+1)) # For Python 2, it is just range(k+1). Given an integer k, which you can get with input. The range creates an iterator (in Python 3) with those numbers (k+1 because it is not inclusive, but you need it to be), then we make it into a list. Demo: >>> k = … Read more
you need to insert the values in a list and then get the values out of list as you have integers value in list you need to make it a string before getting the values out of list. while True: while True: try: last_number = int(input(‘\nEnter last number :’)) except ValueError: print(“\nPlease enter only number”) … Read more
Python is free software, and it’s open source. Anyone can use it in a commercial or public project. Python is not a proprietary language, for the same reasons. Source: https://docs.python.org/3/license.html 13 solved Couple of questions about python [closed]
Assuming that you want to get the values after the comma, you can do something like this: with open(‘ops.log’, ‘r’) as log_fh: data = [int(line.split(‘,’)[1]) for line in log_fh.readlines()] print max(data), min(data) solved Return Max and min not working right [closed]
The latest continue takes effect on the outer for loop, as demonstrated by the following example: >>> for x in [1, 2, 3]: … for y in [4, 5, 6]: … print(‘x =’, x, ‘y =’, y) … else: … continue … print(‘here’) … x = 1 y = 4 x = 1 y = … Read more
You can strip your elements with str.strip() method : >>> l =[“[‘lady’]”, “[‘hen’]”, “[‘horse’]”] >>> [i.strip(“‘][“) for i in l] [‘lady’, ‘hen’, ‘horse’] 2 solved beginners issue with using of lists in python
1- Using while loop i = len(full_name.split()) – 1 while(i >= 0): print full_name.split()[i] i = i-1 2- Slicing x = full_name.index(” “) new_string = full_name[x+1:] + ” ” + full_name[0:x] print new_string 3- Counting lower and upper lower = 0 upper = 0 for letter in full_name: if letter.islower(): lower = lower + 1 … Read more
If you are familiar with UML notation you can just try http://www.w3sdesign.com. Architecture patterns: http://martinfowler.com/eaaCatalog/ 2 solved Popular and useful design patterns [closed]
I fixed both your functions. You had your raw_inputs at the wrong place: def yes_or_no(purchase_q): if purchase_q == “yes”: while True: things = raw_input(“Great. What is your hearts desire(type no more to exit shop): “) if things != “no more”: buying_something(things) else: print “Good luck on your journey then” break def buying_something(item): if item in … Read more
Programming challenge description: Write a program, given a positive integer, determines if the number is an exact power of two [closed] solved Programming challenge description: Write a program, given a positive integer, determines if the number is an exact power of two [closed]
Hi. I am learning Python and I get stuck with factorial calculation from a number. the codes that I write only return the result once [closed] solved Hi. I am learning Python and I get stuck with factorial calculation from a number. the codes that I write only return the result once [closed]