itertools.permutations does this for you. Otherwise, a simple method consist in finding the permutations recursively: you successively select the first element of the output, then ask your function to find all the permutations of the remaining elements. A slightly different, but similar solution can be found at https://stackoverflow.com/a/104436/42973. It finds all the permutations of the … Read more
I guess you are new to programming and this may be one of your very first codes. It would be great if you start by learning syntax of programming language which you have decided to use as well as working of loops, return statements, etc. I personally preferred reading any basic programming language book. For … Read more
The Best answer is from Yousaf . x = [“apple”, “banana”, “carrot”, “cheese”, “pear”] print(“\””+’s ‘.join(x[:-1])+”s”+” and “+(x[4])+”s”+”\””) solved How removing commas in a list with strings, write in one line of code [duplicate]
try the following code. lst_val = [] class Sample: def func(any_list): global lst_val for value in any_list: lst_val.append(value) return lst_val Sample.func([1, 2, 3, 4]) print(lst_val) 1 solved Appending to the list outside function in python not changing the list [closed]
It is essentially a named tuple inside another tuple. A named tuple is an easy way to create a class. You can create that structure as follows. >>> from collections import namedtuple >>> Status = namedtuple(‘Status’, ‘message code’) >>> s = Status(‘Success’, 0) >>> s Status(message=”Success”, code=0) >>> (s, [[]]) (Status(message=”Success”, code=0), [[]]) Documentation for … Read more
To elaborate on comments from Nin17 and molbdnilo: Your function function(n) is supposed to return an integer value. Like you did in if branch with return(n**2), do return in the else branch: def function(n): if n % 4 == 1: return n**2 else: return function(n + 1) # inlined the increased n and do return … Read more
So it looks like youre having issues understanding how to invoke the function. Look at this code, see how i assign this to be equal to circle(77)? That is one way of invoking the function. Note that your functions can be in seperate files where you can import them from. If theyre in the same … Read more
Just add a += and a new variable like so: number = [1, 2, 4, 5, 6] y = 0 #new variable (output variable) for x in number: y += x #add = sign here print(y) Output: 18 But it would be better to use: y = sum(number) print(y) Output: 18 28 solved Number plus … Read more
Say you have some_list = [1, 2, 3] and you do some_list.insert(-1, 4) You might think, “okay, -1 means the last index, so it’ll insert 4 at the last index”. But the last index is index 2, over here: [1, 2, 3] # ^ It’ll insert 4 at that index, producing [1, 2, 4, 3] … Read more
You can’t really do that, the only possible thing is put the response and the source on the same line. Or you could use ; between statements, but that’s ugly. But more importantly, why would you do that? Why is it better to have it all in on line? >>> import this The Zen of … Read more
Plenty of ways to do this, here is one: def is_triangle(a, b, c): if (a > b + c) or (b > a + c) or (c > a + b): print “No” else: print “Yes” 4 solved Python exercise
lista = [“Albert Eienstein”,”Neils Bohr”] dictb = {} for elem in lista: dictb[elem] = elem.split(‘ ‘) print dictb Output: {‘Neils Bohr’: [‘Neils’, ‘Bohr’], ‘Albert Eienstein’: [‘Albert’, ‘Eienstein’]} 2 solved Dictionary out of list in python
This should do it: My_DICT = {‘Sale_Type’ : ‘Car’, ‘Sale_Length’ : 5, “Query_String” : “”} My_DICT[‘Query_String’] = “select * from Sales where Length > %s” % My_DICT[‘Sale_Length’] — EDIT — Considering your input example, you have a list of dictionaries in My_DICT. You could do it like this: for element in My_DICT: element[‘Query_String’] = “select … Read more
Here’s a way to do this using the .bit_length method of Python 3 integers. It also uses the string .format method to do the integer to binary string conversion. This function returns a string starting with ‘0’ for non-negative numbers so that they can be distinguished from negative numbers. def twos_complement(n): m = n + … Read more
This matches any string beginning with an alphabetic, and containing zero slashes or exactly three consecutive slashes. ^[A-Za-z][^/]*(///[^/]*)?$ 4 solved Regular expression in Python [closed]