You can write the backend yourself using any language or if you just want to focus on doing Android and iOS apps then you can also use third party solutions like Firebase. solved What code should I use to manage a database connected with an android/apple app? [closed]
On this line here, emailRegex = re.compile(”'( [A-Za-z0-9-_+.]+ #name part (AZaz+_-.) @ #@ [A-Za-z0-9-_+.]+ #domain )”’, re.VERBOSE) # you missed a comma here after triple-quote. 1 solved Invalid Syntax on .findall (text) highlighting just the ( or random letter? [closed]
The first rule of debugging is to assume that the error message is telling you the truth. In this case it is telling you keyerror u’True. This means that somewhere in your code you’re doing the equivalent of some_dictionary[u’True’]. In the code you posted, there is nothing that is using the literal value True as … Read more
In function unsortedSearch you have a parameter named list1, but in the body of the function it looks like you are referring to it as list. So change all of your list with list1 and your current problem will be solved: def unsortedSearch(list1, i, u): found = False pos = 0 pos2 = 0 while … Read more
This is one way to approach the problem. As you can see, you can do everything with python’s builtin strings. Note that use str.lower().strip() to normalize the search terms and the menu items before comparing them. That will give more generous results and not punish users for inputting extra spaces, and is usually a good … Read more
Pretty crude way of writing the code. But see if this helps in understanding. Initially: name = [0] len(name) = 1 1st iteration name = [0, “Foo”] len(name) = 2 name[-2] = 0 if name[-2] => if 0 => False => REPEAT 2nd iteration name = [0, “Foo”, “Foo”] len(name) = 3 name[-2] = “Foo” … Read more
userWantToContinue = True while aqpool[0] and userWantToContinue: shuffle (aqpool) numRight = 0 for question, rightAnswer in aqpool: answer = raw_input(question + ” “) if answer == rightAnswer: print (“RÄTT SVAR!”) numRight = numRight + 1 else: print(“FEL SVAR! Rätta svaret är: ” + rightAnswer + “\n”) print(“Vill du försätta spela? (ja eller nej)”) userWantToContinue = … Read more
Let me try to understand the question: im given a list that looks like this l1 = [1, 3, 9, 1, 2, 7, 8] and im supposed to contract the list by taking the first number then the next bigest and the smallest after that and then the biggest again. This is a school assignment … Read more
You need require some credentials, AWS Elastic Beanstalk needs the following information to deploy an application: AWS access key ID AWS secret key Service region Application name Environment name Solution stack Here is the complete reference link 2 solved How to deploy the django app in AWS elastic beanstalk [closed]
The following runs well. Rename your Player class with an uppercase initial to avoid name conflicts. I added some test calls at the end, and the player is loaded with the intended (not default) stats. import pickle class Player: def __init__(self, hp, dmg): self.hp = hp self.dmg = dmg def save(obj): save_file = open(‘save.dat’, ‘wb’) … Read more
If I understand what you’re trying to do correctly, you can just do this: def littery(lst): return ”.join(lst)[:-1] >>> littery([‘Andy’, ‘Warhol’]) ‘AndyWarho’ Or if you want to take the last element off of each element of lst, you could do this: def littery(lst): return ”.join(word[:-1] for word in lst) >>> littery([‘Andy’, ‘Warhol’]) ‘AndWarho’ Or if … Read more
it’s using a dictionary and can’t find the key for your local host. this is probably causing the error breaking: ip_hash={}; # the dictionary is made and ip_hash[ip] = 1; # the dictionary is incorrectly accessed this part alone isn’t a good idea: if ip in ip_hash: print ” repeat ” + ip; else: ip_hash[ip] … Read more
If you want to split by any instance of any of those separators, you may want a regular expression: r = re.compile(r’|’.join(separators)) r.split(s) Note that this is not a safe way to build regexps in general; it only works here because I know that none of your separators contain any special characters. If you don’t … Read more
The default install location for Python-2.7 on Windows is: C:\Python27 Therefore you can: c: cd \Python27 python 5 solved Python 2.7.5 – Where is it installed on Windows Vista? [closed]
import os os.path.normpath(pages) normalizes your path and returns: ‘/bbs/board.php?bo_table=humor&wr_id=195?los=09&qwe=2&’ You don’t have to reinvent the wheel. solved Why do errors occur? [closed]