python

[Solved] how to map two list in a single list in python using zip() in list comprehension

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You can use map and zip for this: >>> data = [[‘Ankur’, ‘Avik’, ‘Kiran’, ‘Nitin’], [‘Narang’, ‘Sarkar’, ‘R’, ‘Sareen’]] >>> list(map(‘ ‘.join, zip(*data))) [‘Ankur Narang’, ‘Avik Sarkar’, ‘Kiran R’, ‘Nitin Sareen’] 0 solved how to map two list in a single list in python using zip() in list comprehension

[Solved] Python Create list of dict from multiple lists [closed]

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This is a perfect example of the zip function. https://docs.python.org/3.8/library/functions.html#zip Given: name = [‘Mary’,’Susan’,’John’] age = [15,30,20] sex = [‘F’,’F’,’M’] Then: output = [] for item in zip(name, age, sex): output.append({‘name’: item[0], ‘age’: item[1], ‘sex’: item[2]}) Will produce: [ {‘name’: ‘Mary’, ‘age’: 15, ‘sex’: ‘F’}, {‘name’: ‘Susan’, ‘age’: 30, ‘sex’: ‘F’}, {‘name’: ‘John’, ‘age’: 20, … Read more

[Solved] Split string on capital letter and a capital letter followed by a lowercase letter [closed]

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I’m trying to give an answer that will help you understanding the problem and work on the solution. You have a string with capital letters and at some point there is a small letter. You want the string to be split at the position before the first small letter. You can iterate through the string … Read more

[Solved] Python merge element of the list [closed]

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If you want to preserve the order of the first elements, something like this might work: from collections import OrderedDict def merge(seq): d = OrderedDict() for k,v in seq: d.setdefault(k, []).append(v) result = [[k]+v for k,v in d.iteritems()] return result This loops over each pair in the sequence. For each k, we either get the … Read more

[Solved] How to hide a value in Python? (display it as a *) [closed]

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This should be enough code to get you started. You just need a flag to determine whether a number should be hidden or not: grid = [ [{“number”: 1, “hidden”: True}, {“number”: 5, “hidden”: False}, {“number”: 8, “hidden”: True}], [{“number”: 3, “hidden”: True}, {“number”: 2, “hidden”: True}, {“number”: 4, “hidden”: False}], [{“number”: 9, “hidden”: True}, … Read more

[Solved] Python–always get “must be str not int”

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It is hard to tell what you want, but based on your edits it looks like you are trying to do something like this: replys = [] while True: reply = input(‘Enter text, [type “stop” to quit]: ‘) print(reply) if reply == ‘stop’ or reply == ‘ ‘: print(” “.join(replys)) break replys.append(reply) 1 solved Python–always … Read more

[Solved] Error in this python code [closed]

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Fix your indentation and add a colon after each if-statement as the following and change user_input == input(‘:’) to user_input = input(‘:’): while True: print (“Options”) print (“Write ‘Quit’ if you want to exit”) print (“Write ‘+’if you want to make an addition”) print (“Write ‘-‘ if you want to make a sottration”) print (“Write … Read more

[Solved] class Boo():pass var1 = Boo var1.x = 4 How is this possible

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Classes have a __dict__ by default, precisely for this purpose (run-time assignment and modification of attributes). Regular attribute assignment just puts the corresponding names and values values in there. It’s no different from setting it at class definition time, really: >>> class Boo: … x = 1 … >>> Boo.y = 2 >>> Boo.__dict__ mappingproxy({‘__dict__’: … Read more

[Solved] Accessing a function from a module

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EDIT: You’re actually not having a python issue but a bash one. You’re running your python script as if it were bash (hence the ‘from: can’t read from’), did you put #!/usr/bin/env python at the beginning of the file you’re running (not print_text.py, the other one)? You could alternatively call it that way: python myfile.py … Read more

[Solved] Python: Is there any reason a subset of a list would sort differently than the original list?

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I think I found why. That is because there are some nan in dpd.txt. And nan is unable to compare: float(‘nan’) > 1 # False while float(‘nan’) < 1 # False So this totally breaks comparison. If you change your key compare function to: def _key(id_): import math result = -dpd[index_map[id_]], id_.lower() if math.isnan(result[0]): result … Read more

[Solved] Reverse first n items of the list and return it

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>>> def reverse(n, lst): if n <= 0: return [] return lst[:n][::-1] + lst[n:] >>> reverse(4, [‘f’, ‘o’, ‘o’, ‘t’, ‘b’, ‘a’, ‘l’, ‘l’]) [‘t’, ‘o’, ‘o’, ‘f’, ‘b’, ‘a’, ‘l’, ‘l’] >>> Explanation: if n <= 0:: if n is less than or equal to zero… return []: return an empty list. Otherwise… return … Read more