[ad_1] You can use map and zip for this: >>> data = [[‘Ankur’, ‘Avik’, ‘Kiran’, ‘Nitin’], [‘Narang’, ‘Sarkar’, ‘R’, ‘Sareen’]] >>> list(map(‘ ‘.join, zip(*data))) [‘Ankur Narang’, ‘Avik Sarkar’, ‘Kiran R’, ‘Nitin Sareen’] 0 [ad_2] solved how to map two list in a single list in python using zip() in list comprehension
[ad_1] This is a perfect example of the zip function. https://docs.python.org/3.8/library/functions.html#zip Given: name = [‘Mary’,’Susan’,’John’] age = [15,30,20] sex = [‘F’,’F’,’M’] Then: output = [] for item in zip(name, age, sex): output.append({‘name’: item[0], ‘age’: item[1], ‘sex’: item[2]}) Will produce: [ {‘name’: ‘Mary’, ‘age’: 15, ‘sex’: ‘F’}, {‘name’: ‘Susan’, ‘age’: 30, ‘sex’: ‘F’}, {‘name’: ‘John’, ‘age’: … Read more
[ad_1] I’m trying to give an answer that will help you understanding the problem and work on the solution. You have a string with capital letters and at some point there is a small letter. You want the string to be split at the position before the first small letter. You can iterate through the … Read more
[ad_1] If you want to preserve the order of the first elements, something like this might work: from collections import OrderedDict def merge(seq): d = OrderedDict() for k,v in seq: d.setdefault(k, []).append(v) result = [[k]+v for k,v in d.iteritems()] return result This loops over each pair in the sequence. For each k, we either get … Read more
[ad_1] the only needed is list I assume you talk about collections, because lists without atomic values to put into lists are worthless. Still, there are lots of things lists don’t work well for. Of course, if you never (or so rarely elegance and performance doesn’t matter) need to [better choices in brackets]… Get a … Read more
[ad_1] This should be enough code to get you started. You just need a flag to determine whether a number should be hidden or not: grid = [ [{“number”: 1, “hidden”: True}, {“number”: 5, “hidden”: False}, {“number”: 8, “hidden”: True}], [{“number”: 3, “hidden”: True}, {“number”: 2, “hidden”: True}, {“number”: 4, “hidden”: False}], [{“number”: 9, “hidden”: … Read more
[ad_1] It is hard to tell what you want, but based on your edits it looks like you are trying to do something like this: replys = [] while True: reply = input(‘Enter text, [type “stop” to quit]: ‘) print(reply) if reply == ‘stop’ or reply == ‘ ‘: print(” “.join(replys)) break replys.append(reply) 1 [ad_2] … Read more
[ad_1] Fix your indentation and add a colon after each if-statement as the following and change user_input == input(‘:’) to user_input = input(‘:’): while True: print (“Options”) print (“Write ‘Quit’ if you want to exit”) print (“Write ‘+’if you want to make an addition”) print (“Write ‘-‘ if you want to make a sottration”) print … Read more
[ad_1] Classes have a __dict__ by default, precisely for this purpose (run-time assignment and modification of attributes). Regular attribute assignment just puts the corresponding names and values values in there. It’s no different from setting it at class definition time, really: >>> class Boo: … x = 1 … >>> Boo.y = 2 >>> Boo.__dict__ … Read more
[ad_1] EDIT: You’re actually not having a python issue but a bash one. You’re running your python script as if it were bash (hence the ‘from: can’t read from’), did you put #!/usr/bin/env python at the beginning of the file you’re running (not print_text.py, the other one)? You could alternatively call it that way: python … Read more
[ad_1] Firstly, You should not write in range(0,5) if you want to iterate through n numbers. Secondly, You do not need to write another while function. You use for loop or while loop for this question. Change for i in range(0,5): while i < 5: print(i ** 2) i += 1 break to for i … Read more
[ad_1] I think I found why. That is because there are some nan in dpd.txt. And nan is unable to compare: float(‘nan’) > 1 # False while float(‘nan’) < 1 # False So this totally breaks comparison. If you change your key compare function to: def _key(id_): import math result = -dpd[index_map[id_]], id_.lower() if math.isnan(result[0]): … Read more
[ad_1] The error is pretty clear : pick is an int. The syntax for i in *someInt* is not a valid syntax in python. Because you wrote this line : pick = int(raw_input(‘Pick a number between 1 and 64: ‘)) Then, you use …. in pick . Just imagine pick value is 5 . What … Read more
[ad_1] >>> def reverse(n, lst): if n <= 0: return [] return lst[:n][::-1] + lst[n:] >>> reverse(4, [‘f’, ‘o’, ‘o’, ‘t’, ‘b’, ‘a’, ‘l’, ‘l’]) [‘t’, ‘o’, ‘o’, ‘f’, ‘b’, ‘a’, ‘l’, ‘l’] >>> Explanation: if n <= 0:: if n is less than or equal to zero… return []: return an empty list. Otherwise… … Read more
[ad_1] I think that is what you need: s=”Here Comes The Sun And I Say It Is Alright”.split() for i in range(2, len(s), 3): s[i] = s[i – 1] print(‘ ‘.join(s)) # ‘Here Comes Comes Sun And And Say It It Alright’ 8 [ad_2] solved Removing words from a string- Python 2.7