[ad_1] I hope this is what you need: snake_case = “” variableName = “parselTongue” for character in variableName: if character.isupper(): snake_case += “_”+character.lower() else: snake_case += character print(snake_case) 2 [ad_2] solved What will be the code for this? you have to solve with python
[ad_1] The code will try to stop randomly all the applications listed in the Applications list. After a reboot, the system will work as usual. [ad_2] solved How safe is this python code and should I run this [closed]
[ad_1] You can do it in 2 lines by combining the print statements: digits = [1,2,3,4,5,6] print(max(digits),min(digits),sum(digits)) Or alternatively split it by new lines: print(max(digits), min(digits), sum(digits), sep=’\n’) [ad_2] solved max min sum printing can be simplify in fewer lines?
[ad_1] One way: storeFullNames = [] storeFullNames.append(‘Jane Doe’) storeFullNames.append(‘Ray Charles’) print(storeFullNames) Second way: storeListNames = [] for name in names: if len(name.split(‘ ‘)) > 1: storeListNames.append(name) print(storeListNames) both ways return a list with full names only… [ad_2] solved How can I write a python code where it extracts full names from a list of names
[ad_1] This Works for me: import re book = open(“book.txt”, “r”) #Here we open the book, in this case it is called book.txt book = str(book.read()) #this is now assigning book the value of book.txt, not just the location chapters = re.split(“Chapter “, book, flags = re.IGNORECASE) #Finds all the chapter markers in the book … Read more
[ad_1] This is perhaps a bit of an aside, but you could greatly simplify this by saying: while True: guess = input(“Guess one letter in the word!: “) if guess in l: print(“Correct”) else: print(“Incorrect”) This would also have the side effect of allowing you to change your word to guess to one of a … Read more
[ad_1] Not a library but an easy way to do what you want: string_a=”ABCD” string_b = ‘ADCT’ print ([ind for ind,char in enumerate(string_a) if string_b[ind] != char]) [1, 3] enumerate gives you the index of each char through the string, if string_b[ind] != char checks if the chars at corresponding indexes are not the same. … Read more
[ad_1] You can use a for loop: for i,line in enumerate(textFile): #code to run on each line Where line is the value of the current line in the loop and i is the line number so let’s say your text file was: John Doe Then the for loop would be: i as 0 line as … Read more
[ad_1] # If Your Looking To Parse An .html File from bs4 import BeautifulSoup with open(‘test.html’) as html_file: soup = BeautifulSoup(html_file, ‘html.parser’) ul = soup.find(‘ul’, {‘class’, ‘ports’}) a = ul.findAll(‘a’) Ports=[] for port in a: Ports.append(port.string) # If Your Looking To Parse A Website from bs4 import BeautifulSoup import requests session=requests.session() endpoint = LINK response … Read more
[ad_1] You can use built-in xml.etree.ElementTree instead: >>> import xml.etree.ElementTree as ET >>> url=”<a rel=”nofollow” href=”https://stackoverflow.com/example/hello/get/9f676bac2bb3.zip”>XYZ</a>” >>> ET.fromstring(url).attrib.get(‘href’) “https://stackoverflow.com/example/hello/get/9f676bac2bb3.zip” This works on this particular example, but xml.etree.ElementTree is not an HTML parser. Consider using BeautifulSoup: >>> from bs4 import BeautifulSoup >>> BeautifulSoup(url).a.get(‘href’) “https://stackoverflow.com/example/hello/get/9f676bac2bb3.zip” Or, lxml.html: >>> import lxml.html >>> lxml.html.fromstring(url).attrib.get(‘href’) “https://stackoverflow.com/example/hello/get/9f676bac2bb3.zip” Personally, I prefer BeautifulSoup … Read more
[ad_1] I would do it following way: Assume that you have file input.txt: 520.980000 172.900000 357.440000 320.980000 192.900000 357.441000 325.980000 172.900000 87.440000 then: from decimal import Decimal import re counter = Decimal(‘1.0’) def get_number(_): global counter counter += Decimal(‘0.1′) return ” “+str(counter)+’\n’ with open(“input.txt”,”r”) as f: data = f.read() out = re.sub(‘\n’,get_number,data) with open(“output.txt”,”w”) as … Read more
[ad_1] The pyobjc modules are only for MAC OSX. https://pyobjc.readthedocs.io/en/latest/ . Looks like you are trying to install on windows PC. [ad_2] solved How to solve pyobjc installation problem?
[ad_1] Something like this using a generator function: lis = [‘ALRAGUL’,’AKALH’, “AL”, ‘H’,’ALH’ ,’to7a’,’ALRAGULH’] def solve(lis): for x in lis: if x.startswith(“AL”) and x.endswith(“H”): yield x[:2] if len(x)>4: yield x[2:-1] yield x[-1] elif x.startswith(“AL”): yield x[:2] if len(x)>2: yield x[2:] elif x.endswith(“H”): if len(x)>1: yield x[:-1] yield x[-1] else: yield x new_lis = list(solve(lis)) print … Read more
[ad_1] OK, what’s going on inside checkdata? Well, whatever it’s doing before the end, after dig = mod(dig, 9) it’s got a number from 0 to 8, and it’s comparing that to the last character (code.charAt(code.length-1))). Notice that the for loop above does i<code.length-1 rather than i<code.length, so that last character isn’t included in the … Read more
[ad_1] import re with open(“in1.txt”) as f: lines = f.read() m = re.sub(r'(?s)my _car_.*?(?=my|$)’, ”, lines) m = re.sub(r’\n+’, ‘\n’, m) print m, 2 [ad_2] solved Delete regex matching part of file