[ad_1] A boolean value can go directly into a conditional (if) statement if programRepeated: If programRepeated is equal to true, then the code block will execute. Some notes on your code though: = is an assignment operator. If you would like to check if something is equal, please use two equal signs ==. Your code … Read more
[ad_1] Just you can use int(): number=int(input(‘Enter a number? ‘)) print(number) Otherwise, to be fool-proof, use try..except: while True: try: number=int(input(“Enter a number ? “)) break except ValueError: print(“Please input a vaild number !!”) [ad_2] solved How to convert a string to integer entered in input functon? [duplicate]
[ad_1] You are first assigning an empty list to x: x = [] And then you assign a single int (twice): for i in range (2): x = int(input(“enter a number: “)) 1: x = [] 2: x = first user input 3: x = second user input What you want to do is append … Read more
[ad_1] If there is an if statement after an elif, this means this a different block of if statements. For example, if I do yes = “yes” no = “no” if yes == “yes”: print(“yee”) elif no == “no”: print(“:(“) It will only print “yee” as after it stopped after the first one worked. However, … Read more
[ad_1] Assuming that your urls.csv file look like: https://stackoverflow.com;code site; https://steemit.com;block chain social site; The following code will work: #!/usr/bin/python # -*- coding: utf-8 -*- from bs4 import BeautifulSoup #required to parse html import requests #required to make request #read file with open(‘urls.csv’,’r’) as f: csv_raw_cont=f.read() #split by line split_csv=csv_raw_cont.split(‘\n’) #remove empty line split_csv.remove(”) #specify … Read more
[ad_1] To fix the KeyError you can do the following thing: variable = {} for word in wordlist: variable[word] = [] for boolean in booleanlist: variable[word].append(True) Note that in this code snippet every keyword has the same list of Booleans, but that’s what you have given to us. edit: removed the global declaration, it was … Read more
[ad_1] You need to check if titletext.a is None before you can use it for sure. for titles in title: titleheading = soup.findAll(‘h2’) for titletext in titleheading: if titletext.a: titlename = titletext.a titlelink =titlename.get(‘href’) print(i) print(titlelink) i+=1 2 [ad_2] solved Non Type object has no attribute get error
[ad_1] This operation is just doing the “merge” step of a Merge Sort and can be done in O(l1+l2) time. The general premise is to iterate over both (already sorted) lists at the same time, but only advance the list with the lowest head value, while using the advanced value in the resulting output. The … Read more
[ad_1] More than likely your code would read (in more “human” terms)if the length of original_term is more than zero characters print something. [ad_2] solved Python how to use the len() on pig game [closed]
[ad_1] The difference is that list1‘s value would be [‘abc’], while list2‘s value would be [‘a’, ‘b’, ‘c’]. Observe: >>> [‘a’ ‘b’ ‘c’] [‘abc’] >>> [‘a’, ‘b’, ‘c’] [‘a’, ‘b’, ‘c’] >>> This is due to the fact that adjacent string literals (delimited by whitespace), possibly using different quoting conventions, are allowed, and their meaning … Read more
[ad_1] Most likely you are handling things as integers. You can use raw_input to read it in as is: response = raw_input(‘Enter your number –> ‘) And treat this as a string. print (“Your first digit is”, response[0]) [ad_2] solved I’m not sure of a way to go about this task using Python code [closed]
[ad_1] If you want to subtract the first element with the rest, Result = [abs(Nums[0] – item) for item in Nums[1:]] [ad_2] solved Python List : The different between the elements of a same list [closed]
[ad_1] httplib is for the job, and you may refer to the example code at the bottom of the document. and google for the httplib sample code. 1 [ad_2] solved HTTPS post login form [closed]
[ad_1] if Enter == “Yes” or “yes”: This is not how or works. This is interpreted as if (Enter == “Yes”) or “yes”:. In python, non-empty strings are always true, so all of the if statements like that will be true. I would suggest something like if Enter.lower() == “yes”: which takes care of all … Read more
[ad_1] To quote the Python FAQ, raw string literals in Python were “designed to ease creating input for processors (chiefly regular expression engines) that want to do their own backslash escape processing”. Since the regex engine will strip the backslash in front of the quote character, Python doesn’t need to strip it. This behavior will … Read more