A dictionary maps strings to values. An array maps integers to values. That is about it! So, seriously: in the end, both data structures map a “key set” to values. For dictionaries, the keys can of (almost) arbitrary type, without any constraint on them (besides being “hash able”). Whereas an array maps a consecutive range … Read more
You need to call the method: month.lower() == ‘march’ The method is an object too, and without calling it you are comparing that method with a string. They’ll never be equal: >>> month=”January” >>> month.lower <built-in method lower of str object at 0x100760c30> >>> month.lower == ‘January’ False >>> month.lower == ‘january’ False >>> month.lower() … Read more
You can just add, while computer1 in GuessList: computer1 = randint(0, 5) After your computer1 = randint(0, 5). You might have to remove your GuessList = [ ] because that will reset your GuessList each time. Instead, you should have that at the very start of your code and leave the append statement. Or you … Read more
You can split the string , then convert each elements to int – >>> s=”12 14 17″ >>> list(map(int,s.split())) [12, 14, 17] >>> solved How to convert a string filled with numbers to seperate integers in a list? [duplicate]
We have: xs = [“A”, “B”, “C”] ys = [1, 2, 3] Let’s take a simple example: f repeats y times the char x f=lambda x,y:x*y The computation of the matrix is obvious: for each y, we compute a row of f(x,y) with all x in xs. matrix = [[f(x,y) for x in xs] for … Read more
you can use something like that: sentence = input().split() ans = [] for i in range(len(sentence)): if i%2: ans.append(sentence[i]+’…’) else: ans.append(sentence[i]) print(‘ ‘.join(ans)) solved How to iterate odd indexes and add them back to original list
def QuestionSet1(): print(“Challenge level 1 has being selected.”) print(“Can you translate these words into french?”) a=input(‘Q1. Hello! :’) score = 0 if ‘bonjour’ in a.lower(): score = score + 1 print(‘Correct!’) else: print(‘Wrong! ‘+’Its Bonjour’) print(‘You have finished and scored’, score, ‘out of 10’) You would need make a reference to score before you give … Read more
All you need to do is get rid of the first hangman() call: … for i in range(1, num_of_players + 1): print(players_dict[‘Player {}’.format(i)] if hangman() is False: results += False else: results += True If you need to keep hold of the value returned, assign it to a variable beforehand: … r = hangman() if … Read more
I don’t know exactly what you were going for, but this should fix most of it: print(‘You have ‘ + turns + ‘ more guesses’) no need to use str for stuff like this and don’t use + outside the parenthesis of print() This assumes your turns variable is a string, but if it is … Read more
Can you try the following: req_keys = [‘col1’, ‘col2’, ‘col3’, ‘col4’] all_list = [incoming[i] for i in req_keys] all_list = [i for i in all_list if i] print(‘1’.join(all_list)) Example: incoming = {} incoming[‘col1’] = ‘a’ incoming[‘col2’] = None incoming[‘col3’] = ‘c’ incoming[‘col4’] = None Output: a1c Another Example: incoming = {} incoming[‘col1’] = ‘a’ incoming[‘col2’] … Read more
Disregarding the myriad of syntax errors, your myarray variable seems to be declared globally and that’s why it has global scope? 4 solved Why Python scope my variable outside my function?
You had most of the elements correct in your script, but you need to think more about the order of everything. Make sure you pass any arguments that are needed to a function. Your getAvg function needed three arguments for it to calculate the average and display it with the student number. Also you forgot … Read more
Programming challenge description: Write a program, given a positive integer, determines if the number is an exact power of two [closed] solved Programming challenge description: Write a program, given a positive integer, determines if the number is an exact power of two [closed]
You might want to try future statements. Basically, keep the code the way it is, and backport features to 2.7. I already see the print statements causing problems, so at the top just add from __future__ import print_statement. This will cause Python 2.7 to read print as if it were running in 3.x. Running the … Read more
Without version checking or `six`, how can I use `except MyError, e:` vs `except MyError as e` to work with Python 2&3? solved Without version checking or `six`, how can I use `except MyError, e:` vs `except MyError as e` to work with Python 2&3?