[ad_1] You can use a regex to look for words that follow the word python, for example >>> import re >>> re.findall(r’Python (\w+)’, s) [‘is’, ‘has’, ‘features’, ‘interpreters’, ‘code’, ‘is’, ‘Software’] Since this list may contain duplicates, you could create a set if you want a collection of unique words >>> set(re.findall(r’Python (\w+)’, s)) {‘Software’, … Read more
[ad_1] You may achieve this using itertool.chain() with list comprehension expression as: >>> a=[[1,2,3],[4,5,6]] >>> b=[[5,8,9],[2,7,10]] # v join the matched sub-lists # v v your condition >>> [i + list(chain(*[j[1:] for j in b if i[1]==j[0]])) for i in a] [[1, 2, 3, 7, 10], [4, 5, 6, 8, 9]] [ad_2] solved How to … Read more
[ad_1] How about something like this? import re class context: grammar = r’and|or|#|\$|:|@|\w+’ subs = [ (r’\$(\w+)’, “context(‘\\1′)”), (r’!#(\w+)’, “intents(‘\\1′).isNot_()”), (r’#(\w+)’, “intents(‘\\1′).is_()”), (r’@(\w+):(\w+)’, “entities(‘\\1’).is_(‘\\2′)”), (r’@(\w+)’, “entities(‘\\1’).any()”) ] def __init__(self, val): self.val = val def parse(self): parsed = self.val for sub in self.subs: parsed = re.sub(*sub, parsed) return parsed >>> print(context(‘$foo\n#foo\n!#foo\n@foo\n@foo:bar’).parse()) context(‘foo’) intents(‘foo’).is_() intents(‘foo’).isNot_() entities(‘foo’).any() entities(‘foo’).is_(‘bar’) … Read more
[ad_1] if you just want to print out text instead of list then use str.join # … print(”.join(b)) # or like this: text=””.join([(c + ” | ” + x + “\n”) for _ in range(5)]) print(text) # or python 3.6 style text=””.join(f”{c} | {x}\n” for _ in range(5)) 2 [ad_2] solved Why does my \n … Read more
[ad_1] Your code is not working because you are never changing the n variable. In your function you’re checking if n > 0 and it will always be Here is a fix: n = int(input(“?”)) def again_book(self): if self > 0: again_book(self – 1) print(self) again_book(n) Another way of doing it is using a while … Read more
[ad_1] from functools import reduce import ast,sys input_int = int(sys.stdin.read()) num_list = [x for x in range(1, input_int+1)] print(reduce(lambda x, y : x + y ** 3, num_list) / reduce(lambda x, y : x + y ** ,num_list)) 1 [ad_2] solved Compute the ratio of the sum of cube of the first ‘n’ natural numbers … Read more
[ad_1] Print is a function in python 3 so change print buildConnectionString(myParams) To: print(buildConnectionString(myParams)) [ad_2] solved Syntax error on print-statement in Python 3 [duplicate]
[ad_1] Sorry but that day I didn’t know about slicing, sorry to bother, here it is: l=[1,2,3,4,5,6,7,8,9];l=[[l[i],l[i+1],l[i+2]] for i in range(0,9,3)];print(L) [ad_2] solved How to print a list as list of list in particular order in Python?
[ad_1] I was able to solve the problem by pre processing the data to store the person’s timezone. Then using pytz I do this. from django.utils import timezone import pytz valid_timezones = [] for tz in list_of_timezones: local_time = now().astimezone(pytz.timezone(tz)) if 19 < local_time.hour < 20: valid_timezones.append(tz) reminders = Person.objects.filter(timezone__in=valid_timezones) [ad_2] solved How to filter … Read more
[ad_1] The error occurs when you type in a letter instead of a digit. Also, you should test for the validity of the user input before trying to delete the number on that index: from numpy import random dice = [1, 2, 3, 4, 5, 6] first = [random.choice(dice) for i in range(5)] print(first) while … Read more
[ad_1] It is still not really clear what you want. If you want multidimensional array you can use lists: >>> matrix = [[None]*10 for x in range(3)]#replace 10 with 1000 or what ever >>> matrix [[None, None, None, None, None, None, None, None, None, None], [None, None, None, None, None, None, None, None, None, None], … Read more
[ad_1] input returns a string, and 0 != “0” Either parse your strings immediately parx = int(input(“Write your parX: “)) pary = int(input(“Write your parY: “)) Or check against strings while pary != “0” and parx != “0”: Note too that you should be using some error checking. If the user enters a non-number, your … Read more
[ad_1] I tried a couple of times to debug the code , but wasn’t able to fix it , so i wrote the code again with a different approach and it worked. Here‘s the code [ad_2] solved incorrect output from minimax algorithm for Tic Tac Toe
[ad_1] .append() is an in place update, and returns None, so your current generator is creating a list of None which can’t be compared by sorted(). That aside, you don’t need to keep track of your newly split items with map() as it’s a generator that is being fed into sorted(). Try: >>> my_list = … Read more
[ad_1] You have to pass “/” as a separator parameter to the split function: split(“/”). The split function by default splits by whitespace ” “. “Hello World”.split() => [“Hello”, “World”] “Hello/World”.split() => [“Hello/World”] “Hello/World”.split(“/”) => [“Hello”, “World”] Change your code to: print(sentence.split(“/”)[-1]) 3 [ad_2] solved Python How to get the last word from a sentence … Read more