You can use a regex to look for words that follow the word python, for example >>> import re >>> re.findall(r’Python (\w+)’, s) [‘is’, ‘has’, ‘features’, ‘interpreters’, ‘code’, ‘is’, ‘Software’] Since this list may contain duplicates, you could create a set if you want a collection of unique words >>> set(re.findall(r’Python (\w+)’, s)) {‘Software’, ‘is’, … Read more
You may achieve this using itertool.chain() with list comprehension expression as: >>> a=[[1,2,3],[4,5,6]] >>> b=[[5,8,9],[2,7,10]] # v join the matched sub-lists # v v your condition >>> [i + list(chain(*[j[1:] for j in b if i[1]==j[0]])) for i in a] [[1, 2, 3, 7, 10], [4, 5, 6, 8, 9]] solved How to merge two … Read more
How about something like this? import re class context: grammar = r’and|or|#|\$|:|@|\w+’ subs = [ (r’\$(\w+)’, “context(‘\\1′)”), (r’!#(\w+)’, “intents(‘\\1′).isNot_()”), (r’#(\w+)’, “intents(‘\\1′).is_()”), (r’@(\w+):(\w+)’, “entities(‘\\1’).is_(‘\\2′)”), (r’@(\w+)’, “entities(‘\\1’).any()”) ] def __init__(self, val): self.val = val def parse(self): parsed = self.val for sub in self.subs: parsed = re.sub(*sub, parsed) return parsed >>> print(context(‘$foo\n#foo\n!#foo\n@foo\n@foo:bar’).parse()) context(‘foo’) intents(‘foo’).is_() intents(‘foo’).isNot_() entities(‘foo’).any() entities(‘foo’).is_(‘bar’) 1 … Read more
if you just want to print out text instead of list then use str.join # … print(”.join(b)) # or like this: text=””.join([(c + ” | ” + x + “\n”) for _ in range(5)]) print(text) # or python 3.6 style text=””.join(f”{c} | {x}\n” for _ in range(5)) 2 solved Why does my \n not work … Read more
Your code is not working because you are never changing the n variable. In your function you’re checking if n > 0 and it will always be Here is a fix: n = int(input(“?”)) def again_book(self): if self > 0: again_book(self – 1) print(self) again_book(n) Another way of doing it is using a while loop: … Read more
from functools import reduce import ast,sys input_int = int(sys.stdin.read()) num_list = [x for x in range(1, input_int+1)] print(reduce(lambda x, y : x + y ** 3, num_list) / reduce(lambda x, y : x + y ** ,num_list)) 1 solved Compute the ratio of the sum of cube of the first ‘n’ natural numbers to the … Read more
Print is a function in python 3 so change print buildConnectionString(myParams) To: print(buildConnectionString(myParams)) solved Syntax error on print-statement in Python 3 [duplicate]
Sorry but that day I didn’t know about slicing, sorry to bother, here it is: l=[1,2,3,4,5,6,7,8,9];l=[[l[i],l[i+1],l[i+2]] for i in range(0,9,3)];print(L) solved How to print a list as list of list in particular order in Python?
I was able to solve the problem by pre processing the data to store the person’s timezone. Then using pytz I do this. from django.utils import timezone import pytz valid_timezones = [] for tz in list_of_timezones: local_time = now().astimezone(pytz.timezone(tz)) if 19 < local_time.hour < 20: valid_timezones.append(tz) reminders = Person.objects.filter(timezone__in=valid_timezones) solved How to filter Django queryset … Read more
The error occurs when you type in a letter instead of a digit. Also, you should test for the validity of the user input before trying to delete the number on that index: from numpy import random dice = [1, 2, 3, 4, 5, 6] first = [random.choice(dice) for i in range(5)] print(first) while True: … Read more
It is still not really clear what you want. If you want multidimensional array you can use lists: >>> matrix = [[None]*10 for x in range(3)]#replace 10 with 1000 or what ever >>> matrix [[None, None, None, None, None, None, None, None, None, None], [None, None, None, None, None, None, None, None, None, None], [None, … Read more
input returns a string, and 0 != “0” Either parse your strings immediately parx = int(input(“Write your parX: “)) pary = int(input(“Write your parY: “)) Or check against strings while pary != “0” and parx != “0”: Note too that you should be using some error checking. If the user enters a non-number, your program … Read more
I tried a couple of times to debug the code , but wasn’t able to fix it , so i wrote the code again with a different approach and it worked. Here‘s the code solved incorrect output from minimax algorithm for Tic Tac Toe
.append() is an in place update, and returns None, so your current generator is creating a list of None which can’t be compared by sorted(). That aside, you don’t need to keep track of your newly split items with map() as it’s a generator that is being fed into sorted(). Try: >>> my_list = [“a,a”, … Read more
You have to pass “/” as a separator parameter to the split function: split(“/”). The split function by default splits by whitespace ” “. “Hello World”.split() => [“Hello”, “World”] “Hello/World”.split() => [“Hello/World”] “Hello/World”.split(“/”) => [“Hello”, “World”] Change your code to: print(sentence.split(“/”)[-1]) 3 solved Python How to get the last word from a sentence in python? … Read more