[ad_1] Python’s sort() has the optional argument key. You can use a lambda function as the key like so: numbers = [1, 9, 35, 12, 13, 21, 10] numbers.sort(key=lambda i: i % 5) print(numbers) A quick explanation of what’s going on here: A lambda function is a function that is defined in-line and isn’t named. … Read more
[ad_1] Should be just: print ‘\n’.join([str(factorial(x)) for x in range(0, 6)]) 1 [ad_2] solved Printing every item on a new line in Python [duplicate]
[ad_1] In cmd python shows python 2.7 installed but when I write python2 it shows that it isn’t recognized as a internal file or command [duplicate] [ad_2] solved In cmd python shows python 2.7 installed but when I write python2 it shows that it isn’t recognized as a internal file or command [duplicate]
[ad_1] in your count() function, the variable probability is created when the function called, it is not the same variable probability you declared at beginning. I think you may want to use the variable as global variable. 2 [ad_2] solved please correct the following code [closed]
[ad_1] You can use the Django template language independently of the framework. Read “The Django template language: For Python programmers”, specifically the section on “standalone mode”, for instructions on how to use just the template system. [ad_2] solved How to embed python variable on html [closed]
[ad_1] Using list comprehension, str.startswith and sum [sum(w.startswith(p) for w in word) for p in prefix] # [4, 2, 1] 3 [ad_2] solved Count number of occurrences in a list
[ad_1] I found a way to do what you are asking for: class AddableInt(int): def __call__(self, n): return AddableInt(self + n) def add(n): return AddableInt(n) add(5)(10)(20) # evaluates to 35 This works because the call to add(5) creates an AddableInt with a value of 5. No __init__ method was declared in AddableInt, so it just … Read more
[ad_1] print(*sorted((int(n.strip()) for n in open(“numbers.txt”)), reverse=True)[:3], sep=”\n”) This solution worked..! [ad_2] solved Python: Read the file and output the three biggest numbers [closed]
[ad_1] Surfaces doesn’t have an object for retrieving the file name, but maybe you could use another variable to hold the file name? #load images bg_filename = “start.png” background = pygame.image.load(bg_filename) #keep looping through while 1: #clear the screen before drawing it again screen.fill(0) #draw the screen elements screen.blit(background, (0,0)) #update the screen pygame.display.flip() #loop … Read more
[ad_1] The simplest way, assuming you do not wish to go further down in the tree is: import os filepaths = [] iterdir = os.scandir(path_of_target_dir) for entry in iterdir: filepaths.append(entry.path) Update: A list comprehension makes is faster and more compact: (Strongly Recommended) import os iterdir = os.scandir(path_of_target_dir) filepaths = [entry.path for entry in iterdir] If … Read more
[ad_1] You can use the or operator to assign a “default value” to a variable. This works because a or b is equivalent to a if a else b. Thus you could write lista = GETLISTA() or some_default Notice, however, that this will also use some_default if GETLISTA() evaluates to an empty list [], or … Read more
[ad_1] You could try something like this. – matched = [ x for x in dict1 if x in dict2 ] – unmatched = [ x for x in dict1 if x not in dict2 ] 2 [ad_2] solved How to compare two list of dictionary values present in any index
[ad_1] I slightly changed the input data into a form which would make more sense technically speaking. In addition I removed the ResultId() since this seems to be a special datatype which needs to be converted into a string separately before doing any further data handling after receiving the responses from the database. However, I … Read more
[ad_1] This is a bash script, not a Python script. Run it using ./script_name.sh or bash script_name.sh instead of python script_name.sh. 1 [ad_2] solved Why doesn’t Python run my bash code?
[ad_1] To work on arbitrary lengths>1, you have to change the second if-statement. I fixed the last one for you: sideLength = 5 totalLength = (sideLength) + 2*(sideLength-1) loop = 1 while loop<=totalLength : if loop==1 or loop==totalLength: print ” “*(sideLength-1) + “*”* sideLength + ” “*(sideLength-1) if loop>sideLength-1 and loop<= 2*sideLength-1: print “*” + … Read more