[Solved] Javascript calculate 19% taxes from parseFloat value total to pay
This will give you the total tax : parseInt(totaltopay.value)*0.19/1.19 1 solved Javascript calculate 19% taxes from parseFloat value total to pay
This will give you the total tax : parseInt(totaltopay.value)*0.19/1.19 1 solved Javascript calculate 19% taxes from parseFloat value total to pay
mysql query PHP: I want to a specific items to be first and can modify the query how many items to be displayed [duplicate] solved mysql query PHP: I want to a specific items to be first and can modify the query how many items to be displayed [duplicate]
It was pretty simple, I don’t know why do I get a vote down every time I ask question. $mysqli = new mysqli(“localhost”, “root”, “”, “database”); if ($mysqli->connect_errno) { echo “Failed to connect to MySQL: (” . $mysqli->connect_errno . “) ” . $mysqli->connect_error; } $username = $_SERVER[‘REMOTE_ADDR’]; $stmt = $mysqli->prepare(“select * from `vpb_uploads` where `username` … Read more
Nobody can see your code because Apache (or whatever web server you use) is instructed to EXECUTE any .php files rather than simply serve (display) them as it does by default (with .html, .css, .js, etc). I think what you may have heard of is a general security concern using PHP in general – If … Read more
If you want to use objects, try this: foreach ($array_tmp->info as $emp) { echo $emp->name; } For arrays: foreach ($array_tmp[‘info’] as $emp) { echo $emp[‘name’]; } solved How to loop through these values in PHP [duplicate]
You get the error because you bind 7 params to the query, but don’t use any of them. Instead you insert the variables directly into the query, which leads to the data being (insecurely) inserted into the database. $insert = $this->con->db->prepare(‘UPDATE users SET firstName=”‘.$updateFirstName.'”, lastName=”‘.$updateLastName.'”, username=”‘.$updateUsername.'”, email=”‘.$updateEmail.'”, profileImage=”‘.$updateProfileImage.'”, bio=”‘.$updateBio.'” WHERE userID = ‘.$userID); should be … Read more
Use sort with a custom compare function: data.sort(function(a, b){ return a[1] – b[1]; }); Example: var data = [[4,1],[20,1],[66,1],[68,3],[70,3],[72,2],[84,1],[96,4],[102,2]]; data.sort(function(a, b){ return a[1] – b[1]; }); // data now contains: [[4,1],[20,1],[66,1],[84,1],[72,2],[102,2],[68,3],[70,3],[96,4]]; If you want to sort in descending order instead just do b[1] – a[1] instead. 5 solved javascript or PHP sorting array of x,y … Read more
read interested page to string (file_get_contents, curl ) or DOMdocument / SimpleXML find interesting information in string (by RegEx or substring search) or in DOMdocument / SimpleXML (special function in DOMdocument / SimpleXML class), echo it edit: If you like jQuery you can use phpQuery edit: For bbc.com/news you can read RSS http://feeds.bbci.co.uk/news/rss.xml – it … Read more
I assume that ‘username’ is a text/char field in your db. Try this code: mysql_query (“SELECT * FROM ” . $iAccount_table . ” WHERE username=”” . $user . “””) or die(mysql_error()); I hope you find this helpful. solved MySQL error:You have an error in your SQL syntax; check the manual that corresponds to your MySQL … Read more
Please try this code: $number = 0; $result = mysqli_query($con, $sql); if (!$result) exit(mysqli_error($con)); else $number = mysqli_num_rows($result); if ($number==0) { echo “No rented cars for this period !”; } else { while ($number){ $row = mysqli_fetch_row($result); $brand = $row[‘brand’]; $model = $row[‘model’]; $reg_num = $row[‘reg_num’]; $horse_powers = $row[‘horse_powers’]; $color = $row[‘color’]; echo $brand; $number–; … Read more
function addDate( $Date, $adday ) { list( $year, $month, $day ) = $Date; return date( “Y-m-d”, mktime( 0, 0, 0, $month, $day + $adday, $year ) ); } This should be closer to what you are looking for. If you clarify your question I can clarify my answer. 0 solved Parse error: syntax error, unexpected … Read more
You have used mysql_connect() in the update clause of the code. If your PHP version is 7 and above it will not work (will work for 5.5 and 5.6 versions but with a warning) as it is deprecated. Warning This extension was deprecated in PHP 5.5.0, and it was removed in PHP 7.0.0. Instead, the … Read more
You must use cURL or etc. For example see http://www.php-guru.in/2013/upload-files-using-php-curl/ solved Post a local file in a form of $_FILES in php [closed]
You have a typo in your code. $datetime_beginning vs $datetime_bigining Try this: $datetime_beginning = new DateTime(’60 days ago’); do { $insert_days= mysql_query(“INSERT INTO $tocreate (date_full) VALUES (‘”.$datetime_beginning->format(‘Y-m-d’).”‘);”) or die(mysql_error()); $datetime_beginning->modify(‘+1 day’); }while($datetime_beginning!=$final_time); 4 solved Inserting date()->format(Y-m-d): “Call to a member function modify() on a non-object.” [closed]
You can use something like this : (https?:\/\/www\.google\.(?:(?:com)|(?:co\.in)).*#q=.+) For Google search result url. Since in Google the searched word will be there , after q= DEMO Explanation: solved Regular Expression For indenfity google search pages [closed]